Multiply the following equation: (2x-7)(x+3).

Answers

Answer 1

Answer: FOIL
first
outer
inner
last
example if you had
(a+b)(c+d)
first a times c
outer a times d
inner b times c
last b times d

(2x-7)(x+3)
first 2x times x=2x^2
outer 2x times 3=6x
inner -7 times x=-7x
last -3 times 3=-21

add them
2x^2+6x-7x-21
2x^2-x-21

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Which of the following types of statement cannot be used to explain the steps of a proof? Check all that apply. A.Postulate B.Guess C.Conjecture D.Theorem

Answers

Answer:

Guess and Conjecture

Step-by-step explanation:

Conjecture is simply an opinion gotten from an incomplete information .Fro example. 10 boys selected from Nigeria were served pizza. None of them ate pizza.

it is a conjecture to conclude that all the males in Nigeria do not eat pizza, because the information is incomplete

Guess is almost similar to conjecture. It is conclusion from incomplete information. It is based on one's personal opinion. Guess can be true or false. it is underprobaility and hence cant be banked upon to explain a proof.

Answer:

guess, conjecture

Step-by-step explanation:

Solving systems by elimination:2x + 4y = -4
3x + 5y = -3

Please show me your work so I can do the rest myself. Thanks!

Answers

$2x+4y=-4 (/*3)$
$3x+5y=-3 (/*(-2)) \Rightarrow$

$6x+12y=-12$
$-6x-10y=6 \Rightarrow$

$2y=-6\Rightarrow y=-3$
$y=-3\Rightarrow 2x+4y=-6\rightarrow 2x+4.(-3)=-6 \Rightarrow 2x-12=-6\Rightarrow$
$2x=6\Rightarrow x=3$

$(x,y)=(3,-3)$

Answer:

222

Step-by-step explanation:

2x+4y=-4

3x+5y=-3------> y=-3x-3

What two numbers multiply to 44 and add up to 12?

Answers

This pattern of question is always coming up. Since we can't easily guess, then let us set up simultaneous equation for the statements.

let the two numbers be x and y.

Multiply to 44.    x*y = 44 ..........(a)

Add up to 12. x + y = 12 .........(b)

From (b)

y = 12 - x .......(c)

Substitute (c) into (a)

x*y = 44

x*(12 - x) = 44

12x - x² = 44

-x² + 12x = 44

-x² + 12x - 44 = 0.

Multiply both sides by -1

-1(-x² + 12x - 44) = -1*0

x² - 12x + 44 = 0.

This does not look factorizable, so let us just use quadratic formula

comparing to ax² + bx + c = 0, x² - 12x + 44 = 0, a = 1, b = -12, c = 44

x = (-b + √(b² - 4ac)) /2a   or (-b - √(b² - 4ac)) /2a

x = (-(-12) + √((-12)² - 4*1*44) )/ (2*1)

x = (12 + √(144 - 176) )/ 2

x = (12 + √-32 )/ 2

√-32 = √(-1 *32) = √-1 * √32 = i * √(16 *2) = i*√16 *√2 = i*4*√2 = 4i√2

Where i is a complex number. Note the equation has two values. We shall include the second, that has negative sign before the square root.

x = (12 + √-32 )/ 2 or (12 - √-32 )/ 2

x = (12 + 4i√2 )/ 2 (12 - 4i√2 )/ 2

x = 12/2 + (4i√2)/2 12/2 - (4i√2)/2

x = 6 + 2i√2 or    6 - 2i√2

Recall equation (c):

y = 12 - x, When x = 6 + 2i√2, y = 12 - (6 + 2i√2) = 12 - 6 - 2i√2 = 6 - 2i√2

When x = 6 - 2i√2, y = 12 - (6 - 2i√2) = 12 - 6 + 2i√2 = 6 + 2i√2

x = 6 + 2i√2, y = 6 - 2i√2

x = 6 - 2i√2, y = 6 + 2i√2

Therefore the two numbers that multiply to 44 and add up to 12 are:

6 + 2i√2 and 6 - 2i√2

$xy=44\n x+y=12\n\n xy=44\n x=12-y\n\n (12-y)y=44\n 12y-y^2=44\n y^2-12y+44=0\n y^2-12y+36+8=0\n (y-6)^2=-8$

No solutions in real numbers.

In complex numbers:
$(y-6)^2=-8\n y-6=-√(-8) \vee y-6=√(-8)\n y=6-2\sqrt2 i \vee y=6+2\sqrt2 i\n\n x=12-(6-2\sqrt2i) \vee x=12-(6+2\sqrt2i)\n x=12-6+2\sqrt2i \vee x=12-6-2\sqrt2i\n x=6+2\sqrt2i \vee x=6-2\sqrt2i$

These numbers are $6-2\sqrt2i$ and $6+2\sqrt2i$ .

Abigail realizes that she has too much debt. What is a financially irresponsible decision for Abigail?A.make a budget and limit spending according to the plan

B.take out some easy-access loans and extend them as needed

C.limit spending to writing checks that do not exceed her account balance

D.save $2500 to help pay off debt

Answers

B would be the least wise...loans have interest which means that when you get around to paying them back you owe more than you borrowed and you can get yourself into even deeper debt. Hope this helps, and if you are able to do so, please mark Brainliest! Thanks!

In the diagram ce =12 and be=5 based on the given info ae =

Answers

the answer is ae=12 that what i got right on my test

12 - it is congruent to CE

For each quadratic function, find the domain range vertex and axis of symmetry y=(x-1) squared +1

Answers

$y=(x-1)^2 +1 \n \n For \ the \ quadratic \ function \n \n f(x) =a(x-h)^2+k \n \n where \ a, \ h \ and \ k \ are \ real \ numbers \ with \ a \neq 0 , \n \n the \ vertex \ is \ (h,k) =(1,1) \n \n a \ symmetry \ about \ the \ vertical \ line \ x = h \n \n x= 1$

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