Help with radicals, questions down in attachments.

Answers

Answer 1

Answer: we can't solve first 2 because of missing diagramd
but, longest side=hypotonuse=c
other 2 sides=legs=a and b
a^2+b^2=c^2
$\sqrt{a^(2)+b^(2)}=c$

last 2
1.
remember that
longest side<sum of other 2 sides or else you can't make a traignel
5+7=12
12<13
13 is longest side
13<12 is false
therefor it is false that it is a triangle
not a triangle

2.
$\sqrt{ (x)/(y) } = ( √(x) )/( √(y) )$ so
$\sqrt{ (20)/(7) } = ( √(20) )/( √(7) )$ = $(4√(5) )/(√(7) )$
rationalize denomeator by multplying by $( √(7) )/( √(7) )$

$(4√(35) )/(7)$

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Simplify. 4−16÷4+42 −16 13 15 16

Answers

Answer:

[See Below]

Step-by-step explanation:

✦ First split the equation in little pieces and solve them:

✧ 4 - 16 = -12

✧ 4 + 4² = 20 (4² = 16)

✦ Now divide them:

✧ -12 ÷ 20 = -0.6

So I'm guessing you're trying to simplify 4²... so it'd be 16 because none of the choices are the simplified version of the problem.

~Hope this helps Mate. If you need anything feel free to message me.

Which equation best represents the revenue for selling n raffle tickets at $3.50 each?

Answers

You have to multiply the price of the tickets by the number of tickets sold to obtain revenue.

p = 3.5
n = number of tickets sold

r = 3.5n

3.50n - Cost of n tickets = profit

The sum of a geometric series of twelve terms with common ratio 2 is 20,475. What is the first term? Needed help please.

Answers

Answer: the first term is 5

Step-by-step explanation:

In a geometric sequence, the consecutive terms differ by a common ratio. The formula for determining the sum of n terms, Sn of a geometric sequence is expressed as

Sn = (ar^n - 1)/(r - 1)

Where

n represents the number of term in the sequence.

a represents the first term in the sequence.

r represents the common ratio.

From the information given,

S12 = 20475

r = 2

n = 12

Therefore,

20475 = (a × 2^(12) - 1)/2 - 1

20475 = (a × 4095)

20475 = 4095a

a = 20475/4095

a = 5

Mukul has $3.75 in quarters, dimes and nickels in his pocket. he has five more dimes than quarters and nine more nickels than quarters. how many of each coin are in his pocket?

Answers

Answer:

There are 7 coins of quarters , 12 coins of dimes and 16 coins of nickels .

Step-by-step explanation:

Mukul has $3.75

1 dollar = 100 cents

3.75 dollar = 375 cents

Let he has x coins of quarters

Since we are given that he has five more dimes than quarters.

So, Dimes = x+5

Since we are given that he has nine more nickels than quarters .

So, nickels = x+9

Now 1 quarter = 25 cents

So, x quarter = 25 x cents

1 dime = 10 cents

So, (x+5) dimes = 10(x+5) cents

1 nickel = 5 cents

So, (x+9) nickels = 5(x+9) cents.

Since he had 375 cents in total .

$\Rightarrow 25 x+ 10(x+5) +5(x+9)=375$

$\Rightarrow 25 x+ 10x+50 +5x+45=375$

$\Rightarrow 40 x+95=375$

$\Rightarrow 40 x=375-95$

$\Rightarrow 40 x=280$

$\Rightarrow x=(280)/(40)$

$\Rightarrow x=7$

Thus there are 7 coins of quarters

Coins of dimes = x+5=7+5=12

Coins of nickels = x+9=7+9 =16

Hence there are 7 coins of quarters , 12 coins of dimes and 16 coins of nickels .

Their should be 18 dimes and 8 quarters

What is the y- intercept of the line 6y+12x=18
A. 18
B.-18
C.3
D.-3

Answers

The answer would be C. which is 3.

answer is sea. positive three

How does the graph of f(x) = 3(x - 2)^2 + 1 compare to the graphof g(x) = x^2?
(1) The graph of f(x) is wider than the graph of g(x), and its vertex
is moved to the left 2 units and up 1 unit.
(2) The graph of f(x) is narrower than the graph of g(x), and its vertex
is moved to the right 2 units and up 1 unit.
(3) The graph of f(x) is narrower than the graph of g(x), and its vertex
is moved to the left 2 units and up 1 unit.
(4) The graph of f(x) is wider than the graph of g(x), and its vertex is
moved to the right 2 units and up 1 unit.

Answers

Hello,

Answer B

Just see the graphs. y=x² is passing by (0,0)