Select the correct answer.If a silver nitrate solution is added to excess sodium sulfide, this reaction takes place: 2AgNO3(aq) + Na2S(aq) → Ag2S(s) + 2NaNO3(aq).
Suppose you use 0.0150 liter of a 2.50 M solution of silver nitrate. Assuming the reaction goes to completion, how much silver sulfide is produced? Use the periodic table.
A. 1.49 g
B. 4.65 g
C. 9.30 g
D. 18.6 g

Answers

Answer 1

Answer:

Answer:- B. 4.65 g.

Solution:- The given balanced equation is:

$2AgNO_3(aq)+Na_2S(aq)\rightarrow Ag_2S(s)+2NaNO_3(aq)$

It asks to calculate the mass of silver sulfide formed by when 0.0150 liters of 2.50 M of silver nitrate are used.

Moles of silver nitrate are calculated on multiplying it's liters by its molarity and then on multiplying by mol ratio, the moles of silver sulfide are calculated. These moles are multiplied by the molar mass to convert to the grams.

Molar mass of $Ag_2S$ = 2(107.87)+32.06 = 247.8 g per mol

The dimensional set up for the complete problem is:

$0.0150L((2.50molAgNO_3)/(1L))((1molAg_2S)/(2molAgNO_3))((247.8gAg_2S)/(1molAg_2S))$

= $4.65gAg_2S$

So, the correct choice is B. 4.65 g.

Answer 2

Answer:

Answer:

that jawn gon be 4.65 g

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Which label belongs in the region marked X?Chang makes the diagram below to compare Gay-Lussac's
law and Charles's law.
Gay-Lussac's Law Charles's Law
O involves changes in temperature
O has a constant volume
O shows an inversely proportional relationship
O does not involve pressure changes

Answers

Answer:

A) involves changes in temperature

Explanation:

The figure is missing, but I assume that the region marked X represents the region in common between Gay-Lussac's law and Charle's Law.

Gay-Lussac's law states that:

"For an ideal gas kept at constant volume, the pressure of the gas is directly proportional to its absolute temperature"

Mathematically, it can be written as

$p\propto T$

where p is the pressure of the gas and T its absolute temperature.

Charle's Law states that:

"For an ideal gas kept at constant pressure, the volume of the gas is directly proportional to its absolute temperature"

Mathematically, it can be written as

$V\propto T$

where V is the volume of the gas and T its absolute temperature.

By looking at the two descriptions of the law, we see immediately that the property that they have in common is

A) involves changes in temperature

Since the temperature is NOT kept constant in the two laws.

List the three layers of the earth bad

Answers

core, mantle and the crust

core,mantle, and crust

Which of these substances is a compound Carbon
Chlorine
Uranium
Ammonia

Answers

Among the substances listed, ammonia (NH3) is a compound. The option D (ammonia) is the correct option.

Compound Substance

A compound substance refers to a type of substance that is composed of two or more different elements chemically combined in fixed proportions. In other words, it is a substance formed when atoms of different elements bond together to form molecules. The elements in a compound substance are chemically bonded, meaning they are held together by chemical forces such as covalent bonds, ionic bonds, or metallic bonds.

Compounds can have various physical forms, such as solids, liquids, or gases, depending on the specific elements and the nature of their chemical bonds. They can also exhibit a wide range of chemical and physical properties, such as melting point, boiling point, density, solubility, and reactivity.

Chemical formulas are used to represent compound substances, indicating the types and numbers of atoms present in a molecule of the compound. For example, the chemical formula for water is H2O, representing two hydrogen (H) atoms bonded to one oxygen (O) atom. Ammonia is composed of nitrogen (N) and hydrogen (H) atoms bonded together. Carbon (C), chlorine (Cl), and uranium (U) are elements rather than compounds.

Therefore, Ammonia which is option D is the correct option.

Learn more about chemical formula here

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Answer:

Ammonia

Explanation:

Ammonia is a inorganic compound that is made up of single nitrogen atom.

(see the picture attached) i need to make notes about balancing chemical equations, can anyone give a basic explanation please?

Answers

Yo sup??

Balancing a chemical equation is more like solving mathematical equation.

You just need do the trial and error thing.

Just plug in some random numbers so that the number of atoms on both the sides become the same....that's all.....rest will come by practise.

Hope this helps

Answer:

Explanation:

Balancing Chemical Equations

Let's take a look at this scale. We can see that it is unbalanced, with the right (red) side, weighing more than the left (blue) side. In order for the two sides to be balanced, we need to put a little more mass on the left side until they are the same mass.

Unbalanced Scale

Just like we want the scale to be balanced on both sides, a chemical equation should also be balanced on both sides. A chemical equation shows us the substances involved in a chemical reaction - the substances that react (reactants) and the substances that are produced (products). In general, a chemical equation looks like this:

Chemical Equation: General Form

According to the law of conservation of mass, when a chemical reaction occurs, the mass of the products should be equal to the mass of the reactants. Therefore, the amount of the atoms in each element does not change in the chemical reaction. As a result, the chemical equation that shows the chemical reaction needs to be balanced. A balanced chemical equation occurs when the number of the atoms involved in the reactants side is equal to the number of atoms in the products side.

Let's take a look at an equation representing a chemical reaction:

Balancing Chemical Equations: Example

In this chemical reaction, nitrogen (N2) reacts with hydrogen (H) to produce ammonia (NH3).The reactants are nitrogen and hydrogen, and the product is ammonia. If we look at this equation, we can see that the equation is not balanced.

Balancing Chemical Equations Example

The equation is not balanced because in the reactants side, there are 2 nitrogen (N) atoms and 2 hydrogen (H) atoms. In the products side, there are 1 nitrogen (N) atoms and 3 hydrogen (H) atoms. The number of the atoms is not balanced on both sides.

To balance the chemical equation above, we need to make use of coefficients. A coefficient is a number that we place in front of a chemical formula. In the chemical equation, to make the number of nitrogen (N) atoms equal on both sides, first, we place a coefficient of 2 in front of NH3.

Balancing Chemical Equations Example

Once we do that, the number of nitrogen (N) atoms on both sides is balanced. However, the number of hydrogen (H) atoms is not balanced on both sides. We need to make use of another coefficient in front of H2. This time, we put a coefficient of 3 in front of H2 to balance the chemical equation.

Balancing Chemical Equations Example

The equation above is now balanced. There are 2 nitrogen (N) atoms and 6 hydrogen (H) atoms on both the reactants and products side. Since there is no coefficient in front of N2, that means the coefficient is equal to 1.

Steps to Balance an Equation

Practice always makes perfect. In general, to balance an equation, here are the things we need to do:

Count the atoms of each element in the reactants and the products.

Use coefficients; place them in front of the compounds as needed.

The steps are simple, but it is a process of trial and error. Let's take a look at a few more example equations and techniques that can be used to balance each one.

Example 1

This is a reaction between methane (CH4) and oxygen (O2), producing carbon dioxide (CO2) and water (H2O).

Balancing Chemical Equations Example 1

The reaction shown is a combustion reaction: a compound reacts with oxygen and produces carbon dioxide and water. The technique is to balance the carbon (C) atoms first, then the hydrogen (H) atoms, and then the oxygen (O) atoms.

In this case, the carbon (C) atoms are already balanced. So now we look at the hydrogen (H) atoms. There are 4 hydrogen (H) atoms on the reactants side and 2 hydrogen (H) atoms on the products side. To balance them, we put a coefficient of 2 in front of H2O

A piece of titanium metal has a massive 67.5 g no volume of 15 cm³ what is the density of the titanium