Julian stands on his toes to lift his body high enough so that he can reach a book. In this example, Julian's toes are aA) pulley
B) load
C) wedge
D) fulcrum
its actual a physical science question

Answers

Answer 1

Answer:

Answer : (D) Fulcrum.

Explanation :

It is given that Julian stands on his toes to lift his body high enough so that he can reach a book. This is the example of a second class lever.

In the second class lever, the load is between the effort and the fulcrum.

In this case, the muscles provide the input force. His weight of the foot that is lifted up is the output force and toes act as a fulcrum.

So, the correct option is (D) Fulcrum.

Answer 2

Answer:

Explanation:

EDGE 22

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A graduated cylinder has 20 ml (cm3) of water placed in it. An irregularly shaped rock is then dropped in the graduated cylinder and the volume of the rock and water in the cylinder now reads 30 ml (cm3). The mass of the rock dropped into the graduated cylinder is 23 grams.a.) Find the volume of the rock dropped into the graduated cylinder.
b.) Find the density of the rock dropped into the graduated cylinder.

Answers

A) Volume = displacement
Therefore the rock has a volume of 10mL
B) density = Mass/ Volume
Therefore density = 23/10 = 2.3 per unit volume

Final answer:

The volume of the rock dropped into the graduated cylinder is 10 ml. The density of the rock is 2.3 g/ml.

Explanation:

We first determine the volume of the rock dropped into the graduated cylinder. The initial volume of water in the cylinder is 20 ml, and after placing the rock, the total volume increases to 30 ml. Therefore, the volume of the rock is the total volume minus the initial volume of the water, which is 30 ml - 20 ml = 10 ml.

Next, we find the density of the rock. The formula for density is mass/volume. Given that the mass of the rock is 23 grams and the volume is 10 ml, the density of the rock would be mass/volume = 23 grams / 10 ml = 2.3 g/ml.

Learn more about Density here:

brainly.com/question/34199020

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An object moving in a circle at a constant speed is accelerating. Why?A. because it is going faster
B. because it has constant velocity
C. because its direction is changing
D. because the distance it is traveling is changing

Answers

"Acceleration" does NOT mean 'speeding up'. It means any change
in the speed or direction of motion ... speeding up, slowing down, or
moving in a curve.

An object moving in a circle at a constant speed is accelerating, because
when you're moving along a circle, your direction is constantly changing.

A. Because it is going faster.

What is the speed of sound, when travelling through steel?

Answers

20000 ft/s or 6100 m/s

Which type of rock is created when lava cools and hardens?

Answers

Igneous rocks are created when lava cools and hardens.

It's probably called Magna rock

C. The driver is looking at her phone and has a total reaction time of 4.6 seconds as the car is moving at a constant speed of 11 m/s. If the driver slams on her brakes and slows down at a rate of -8.2 m/s2, what is the stopping distance for the car in this situation

Answers

Answer:

The stopping distance for the car when the driver slams on her brakes is 7.38 m.

Explanation:

The distance traveled for the car after stopping can be found using the following equation:

$v_(f)^(2) = v_(0)^(2) + 2ad$

Where:

vf is the final speed = 0 (it stops)

v₀ is the initial speed = 11 m/s

a is the acceleration = -8.2 m/s²

d is the distance =?

When the driver slams on her brakes the distance traveled is:

$d = -(v_(0)^(2))/(2a) = -((11 m/s)^(2))/(2*(-8.2 m/s^(2))) = 7.38 m$

Therefore, the stopping distance for the car when the driver slams on her brakes is 7.38 m.

I hope it helps you!

Suppose a log's mass is 5 kg. After burning, the mass of the ash is 1 kg. explain what May have happened to the other 4 kg

Answers

I think the "missing mass" may have escaped the site of the
conflagration in the form of hot, invisible gases, and in the form
of all the tiny particles in the smoke.

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When the resultant force acting on a system is zero, the total momentum of the system...