A rectangle has an area of 112 square units. If its width was half as long and its length was 8 times as long, what would be its new area?
Answers
lenght=x
width=y
xy=112 u²
Then
(y/2)(8x)=4xy
Therefore:
xy=112 u² then 4xy=4(112 u²)=448 u²
answer: the new area would be 448 u²
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2x-y=4
X+2y=2
A) no solution
B) one solution
C) infinitely many solutions
Answers
Answer:
B) one solution
Step-by-step explanation:
The ratio of x-coefficient to y-coefficient is different in the two equations, so the lines have different slopes. Two lines with different slopes will always have exactly one point of intersection. You don't need to graph the equations to know there is ...
one solution
__
A graph is attached. As it happens, the two lines are perpendicular. The solution is (2, 0).
Answers
Tom is 3 times older so 3*5=15
The difference between them is 15-5=10 years
When Sam is 20 we add the difference 20+10=30, and we have Tom's age :)
Answers
Answer:
60
Step-by-step explanation:
Answers
Answer:
you should find the value of 112°
So 180-79-73 =28 and 180 -37-96=47
Angles around a point add to 360 so
112 + 28 + 47 = 187 then 360 - 187 = 173
So angle AED = 173 degrees
Answers
Answer:
see below
Step-by-step explanation:
sqrt(20)
sqrt(4*5)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(4) sqrt(5)
2 sqrt(5)
Answer:
We can factor down 20 with it's greatest prime GCF, which is 5. We get a 4. When we factor that down the same way, we get 2. If we repeat that process, we get 5, 2, and 2, which turns into .