What is the percent composition of calcium (Ca) in CaO?A 56g/40g x 100%
B 16g/56g x 100%
C 40g/56g x 100%
D 40g/100% x 56g

Answers

Answer 1
Answer:

Answer:

C 40 g/56 g × 100 %

Explanation:

Calculate the mass of each component and the total mass.

Element  Atomic mass/u  No. of atoms  Subtotal mass/u

     Ca              40.08                     1                     40.08

     O                16.00                      1                    16.00

                                                               Total = 56.08

The formula for mass percent is

% by mass = Mass of component/Total mass × 100 %

In this problem

% Ca = mass of Ca/mass of CaO × 100 %

% H = 40.08 g/56.08 g × 100 %

Answer 2
Answer:

The percentage composition of calcium (Ca) in CaO is option C.

  • Here we have to determine the mass of every component and even the total mass.

Element  Atomic mass/u  No. of atoms  Subtotal mass/u  

    Ca              40.08                     1                     40.08  

    O                16.00                      1                    16.00  

                                                              Total = 56.08

  • The mass percent formula is

\%\ by\ mass = Mass\ of\ component / Total\ mass *  100 \%  

 \% Ca = mass\ of\ Ca/ mass\ of\ CaO * 100 \%\n\n\% H = 40.08 g/ 56.08 g * 100 \%

Therefore, we can conclude that the correct option is C.

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A farmer had an accident and spilled a chemical into his pond. Several days later, he notices many dead frogs around the pond. That summer, the number of gnats around the pond was higher than ever. This is becausea. the chemical is good for the gnats.
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Answers

Answer:

The correct answer is option b.

Explanation:

A limiting factor or limiting reagent is a compound of reactant which gets used up first and effects the formation of product in a chemical reaction.

Around the pond frog would be feeding on gnat, and due to their presence population of gnats were in control .But due to accidental spilling of chemical in pond resulted in death of frogs. Which were actually responsible for less population of gnats around the pond but due to dead action of chemical on them (frogs) their population in pond declined due to which increase in population of gnats was observed.

On generalizing this fact:

  • Higher the population of frogs lower will be the population of gnats.
  • lower the population of frogs higher will be the population of gnats.

So, from this we can conclude that frogs are the limiting factors for the gnats as more the number of frogs lessor will be number of gnats.

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Bond energy is related to bond length. Use the bond energy data below to arrange the bonds listed in order of increasing bond length (shortest to longest).Bond : Energy (kJ/mol)- C-C : 346
- C=C : 835
- C≡C : 612

Answers

Answer:

The order of increasing bond lenght :

-C≡C < -C=C < -C-C

Explanation:

Bond length is defined as average distance between two nuclei of  bonded atoms in a molecule.Bond length is inversely  proportional to the number of bonds present between two atoms.

\text{Bond length} \propto \frac{1}{\text{Number of bonds}}...[1]

Bond energy is defied as amount of energy required to break apart the bond of 1 mole of molecule into their individual atom.

Bond energy is directly proportional to the number of bonds present between two atoms.

\text{Bond Energy} \propto \text{Number of bonds}..[2]

From [1] and [2]:

\text{Bond length} \propto \frac{1}{\text{Bond energy}}

Bond : Energy (kJ/mol)

-C-C : 346

-C=C : 612

-C≡C : 835

The order of decreasing bond energy :

835 kJ/mol   > 612 kJ/mol > 346  kJ/mol

The order of increasing bond lenght :

-C≡C < -C=C < -C-C

The rate constant (k) for the decay of the radioactive isotope I-131 is 3.6 x 10-3 hours 1. The slope of which of the following graphs is correct for the decay and could be used to confirm the value of k?

Answers

Answer:

Explanation:

pom, add

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Answers

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Final answer:

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Explanation:

When a cell is placed in salt water, water leaves the cell by osmosis. Osmosis is the movement of water molecules across a semi-permeable membrane from an area of lower solute concentration to an area of higher solute concentration.

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