How does the law of conservation of matter apply to chemical equations

Answers

Answer 1

Answer: Since the law of conservation of matter says that no matter can be created or destroyed, chemical equations must have the same amount of matter after the reaction as there was before, making them balanced.

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How many atoms are in 1.75 mol CHCL3

Answers

1 mol = 6.022 x 10²³ atoms

In order to find how many atoms, dimly multiply the amount of moles you have by 6.022 x 10²³ or Avogadro's number.

So you have 1.75 mol CHC1₃ x (6.022x10²³) = 1.05385 x 10²⁴ atoms of CHCl₃

But now you have to round because of the rules of significant figures so you get 1.05 x 10²⁴ atoms of CHCl₃

Which of the following compounds are ionic compounds?CaCl2

C6H12O6

MgO

Na2O

SiO2

Answers

ionic compounds are compounds with ionic bonds, given by the exchange of electrons between a cation (positive ion) and an anion (negative ion).

ionic compounds usually consist of a metallic element and a non-metallic element.

as such, cacl2, mgo, and na2o are ionic compounds. c6h12o6 and sio2 consists of non-metallic elements only, so they do not form ionic bonds.

re: which of the following compounds are ionic compounds?
CaCI2 is an ionic compound.
C6H12O6 is a covalent compound.
MgO is an ionic compound.
Na2O is an ionic compound.
SiO2 is a covalent compound.
hope this helps

What does the value, or magnitude, of the equilibrium constant (K) tell you about an equilibrium system? Be specific with your answer.

Answers

The statements that are correct are ‘A large Keq value indicates that products are favored.’ And ‘A small Keq value indicates that the reverse reaction will occur very quickly.’ Having large Keq means that the concentration of the product is greater than the reactants and so products are favored. Having small Keq means that the concentration of the reactants is greater than the product.

Which of the following can only be separated into two or more pure substances by a chemical change?a. an element
b. a compound
c. a homogeneous mixture
d. a heterogeneous mixture

Answers

The best answer to the question that is being presented above would be letter b. A compound can only be separated into two or more pure substances by a chemical change. Mixtures can be separated without chemical change.

A solution of ammonia has a pH of 11.8. What is the concentration of OH– ions in the solution? Useful formulas..

Answers

The concentration of hydroxideions in the given aqueous solution is equal to 6.3 ×10⁻³ M.

What is the pOH?

pOH can be calculated from the negative logarithm of the concentration of hydroxideions in the given aqueous solution.

Mathematically, the formula of the pOH can be represented as shown below:

pOH = - log ([OH⁻ ])

and pH + pOH = 14 ..............(1)

Where [OH⁻] is representing the concentration of hydroxide ions in an aqueous solution.

Given, the value of the pH of the ammonia solution, pH = 11.8

Substitute the value of the pH in equation (1):

pH + pOH = 14

11.8 - log [OH⁻] = 14

- log [OH⁻] = 14 -11.8

log [OH⁻] = - 2.2

[OH⁻] = 6.3 × 10⁻³ M

Therefore, the concentration of the hydroxideions is equal to 6.3 ×10⁻³ M.

Learn more about pOH, here:

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They are asking you for OH- ions concentration, which is why you have to find the pOH of the solution. You can easily do this with this formula:

pH + pOH = 14

Solve for pOH and you get:

pOH = 14 - pH

Replace the pH with it's value:

pOH = 14 - 11.8
pOH = 2.2

Now that you have the pOH you can find the concentration of OH- ions with this formula:

pOH = -log[OH-]

Solve the formula for [OH-] and you get:

[OH-] = 10^(-pOH)

Now replace pOH with it's value:

[OH-] = 10^(-2.2)
[OH-] = 0.006309 M

The concentration of OH- atoms is 0.006309M or in the scientific notation 6.309×10^(-3)M

What is the molecular formula of caffeine, given that it has an empirical formula of C_4H_5N_2O and a molar mass of 194 g/mol?

Answers

Answer:

$Empirical formula : C4 H 5 N2O \n Empirical \: molar \: mass \: of \: the \n compound \: obtain : \n 12×4+5+2×14+16=97 \n \n Given \: the \: molar \: mass \: of \n Caffeine = 194.2 \n \n n= 194.2 /97=2 \n Thus \: Formula \: of \: \n Caffeine = (C 4H5 N 2 O)2$

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