what is the equation of y=x^3 with the transformation: vertical compression by a factor of 1/2, horizontal shift 7 units to the left, reflection across the x-axis?

Answers

Answer 1

Answer: Assuming the transformations are in order,
because S(x,y) = (x, 1/2y), reverse what is done to y and simplify,
y = x^3 > y = 1/2*x^3 to compress vertically,
because S(x,y) = (x-7,y), reverse what is done to x,
y = 1/2*(x+7)^3 to shift to the left,
reflection across the x-axis changes positives to negatives,
y = -1/2(x+7)^3 to reflect across the x-axis.

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Six students share 8 granola bars equally. How many granola bars does each student get?

Answers

Answer:

1 whole one and a third of one.

Step-by-step explanation:

1 1/3 of a granola bar

Answer: 1.33333333333 or 1.3 as a repeating decimal

Just divide 8 ÷ 6

What is 18027x1003. please explain the problem.

Answers

Well all you have to do is input 18027 * 1003 into your calculator, formerly known as 18027 multiplied by 1003 which gives us 18081081x

what are the values of a, b, and c in the quadratic equation –2x^2 4x – 3 = 0? a = 2, b = 4, c = 3 a = 2, b = 4, c = –3 a = –2, b = 4, c = 3 a = –2, b = 4, c = – 3

Answers

a=-2
b= either negative or positive 4 (you didn't include a plus or minus sign in your question)
c=-3
It should be the last answer choice.

Graph the line with slope 1/3

passing through the point (-2, 5).

Answers

Answer:

y = 1/3x + 17/3

Step-by-step explanation:

Required answer: Below

Detailed explanation:

Let's find the equation of the line first.

We know that the line:

has a slope of 1/3
passes through (-2,5)

So, we use these pieces of information and plug them into the formula:

$\bf{y-y_1=m(x-x_1)}$

$\bf{y-5=(1)/(3)(x-(-2)}$

$\bf{y-5=(1)/(3)(x+2)}$

Now let's graph it.

The lcd for fractions 1/3 3/4 and 8/9 is

Answers

Answer:

the answer is /36

Step-by-step explanation:

3 goes into 36

4 goes into 36

9 goes into 36

For all real numbers x and y, if x # y = x(x-y), then x # (x # y) =My question is, how does x # (x # y) = 8 and how does it also equal to x(squared) - x(cubed) + x(squared) y?

Is there a rule of the function that I have forgotten?

Thanks

Answers

$x\#y=x(x-y)\n\nx\#(x\#y)\n\nx\#y=x(x-y)=x^2-xy\n\nx\#(x\#y)=x\#(x^2-xy)=x[x-(x^2-xy)]=x(x-x^2+xy)\n\n=x^2-x^3+x^2y$

$x^2-x^3+x^2y=8\n\nx^2(1-x+y)=8\n\nx^2(1-x+y)=2^2\cdot4\iff x^2=2^2\ and\ 1-x+y=4\n\nx=2\ and\ y=4-1+x\n\nx=2\ and\ y=3+2\n\nx=2\ and\ y=5$

if x # y = x(x-y) => x # (x # y) = x # [x(x-y)] =x[ x - x(x-y)] = x( x - x^2 +x*y ) = x^2 - x^3 + ( x^2 ) * y;

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