Adam was collecting cans for recycling. in 5 months he had collected 449 bags with 50 cans inside each bag .how many cans did he have total

Answers

Answer 1
Answer: For this problem you would just multiply the number of bags by the contents of each bag, so 449*50.  The answer would be 22,450 cans.  I hope this helps, if you need more assistance tell me, and have a nice day! :)

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100 POINTS HELP PLEASEEEE !!!HURRY!!!

Answers

                                           Question # 1 Solution

Answer:

(h-f)(-8)=-229

Step-by-step Solution:

Given

h(r)=-4r^(2)+4

f(r)=2r-7

As

(h-f)(r)=h(r)-f(r)

(h-f)(r)=-4r^(2)+4-(2r-7)

(h-f)(r)=-4r^(2)+4-2r+7)

We have to find (h-f)(-8)

So,

(h-f)(-8)=-4(-8)^(2)+4-2(-8)+7)

(h-f)(-8)=-4(64)+4+16+7

(h-f)(-8)=-4(64)+4+16+7

(h-f)(-8)=-256+4+16+7

(h-f)(-8)=-229

(h-f)(-8)=-229

                                             Question # 2 Solution

Answer:

(f.p)(9)=38979

Step-by-step Solution:

Given

f(s)=7s-2

p(s)=s^(3)-10s

As

(f.p)(s)=f(s).p(s)

(f.p)(s)=(7s-2)(s^(3)-10s)

(f.p)(s)=7s^4-2s^3-70s^2+20s

We have to find (f.p)(9)

So,

(f.p)(9)=7\left(9\right)^4-2\left(9\right)^3-70\left(9\right)^2+20\left(9\right)

(f.p)(9)=7\cdot \:9^4-2\cdot \:9^3-70\cdot \:9^2+20\cdot \:9

(f.p)(9)=9^4\cdot \:7-9^3\cdot \:2-9^2\cdot \:70+180

(f.p)(9)=45927-1458-5670+180

(f.p)(9)=38979

(f.p)(9)=38979

                                      Question # 3 Solution

Answer:

((f)/(p))(r)=(11r+8)/(r\left(r^2+6\right))

Step-by-step Solution:

Given

p(r)=r^(3)+6r

f(r)=11r+8

We have to find ((f)/(p))(r)

Using the formula

((f)/(p))(r)=(f(r))/(p(r))

As

p(r)=r^(3)+6r

f(r)=11r+8

So

((f)/(p))(r)=(11r+8)/(r^(3)+6r)

((f)/(p))(r)=(11r+8)/(r\left(r^2+6\right))

((f)/(p))(r)=(11r+8)/(r\left(r^2+6\right))

                                     Question # 4 Solution

Answer:

(h-p)(k)=5k^2-3-k^3-8k

Step-by-step Solution:

Given

h(k)=5k^(2)-3

p(k)=k^(3)+8k

We have to find (h-p)(k)

Using the formula

(h-p)(k)=h(k)-p(k)

As

h(k)=5k^(2)-3

p(k)=k^(3)+8k

So

(h-p)(k)=5k^(2)-3-(k^(3)+8k)

(h-p)(k)=5k^2-3-k^3-8k

(h-p)(k)=5k^2-3-k^3-8k

                                       Question # 5 Solution

Answer:

((p)/(g))(11)=(1287)/(155)

Step-by-step Solution:

Given

p(b)=b^(3)-4b

g(b)=b^(2)+4b-10

We have to find ((p)/(g))(11)

As

((p)/(g))(b)=(p(b))/(g(b))

((p)/(g))(b)=(b^(3)-4b)/(b^(2)+4b-10)

So

((p)/(g))(11)=(11^(3)-4(11))/(11^(2)+4(11)-10)

((p)/(g))(11)=(1287)/(155)

((p)/(g))(11)=(1287)/(155)

                                   Question # 6 Solution

Answer:

(f+g)(x)=x^2+20x-18

Step-by-step Solution:

Given

g(x)=x^(2)+11x-7

f(x)=9x-11

We have to find (f+g)(x)

As

(f+g)(x)=f(x)+g(x)

(f+g)(x)=9x-11+(x^(2)+11x-7)

(f+g)(x)=9x-11+x^(2)+11x-7

(f+g)(x)=x^2+20x-18

(f+g)(x)=x^2+20x-18

                                  Question # 7 Solution

Answer:

h(10)+g(10)=-983

Step-by-step Solution:

Given

h(w)=-11w^(2)-7

g(w)=w^(2)+3w-6

We have to find h(10)+g(10)

So,

h(10)=-11(10)^(2)-7

h(10)=-1107.....[1]

and

g(10)=10^(2)+3(10)-6

g(10)=124.....[2]

Adding Equation [1] and Equation [2]

h(10)+g(10)=-1107+124

h(10)+g(10)=-983

h(10)+g(10)=-983

                                   Question # 8 Solution

Answer:

(f+g)(-3)=-6

Step-by-step Solution:

Given

g(b)=b^(2)+9b+10

f(b)=3b+11

We have to find (f+g)(-3)

As

(f+g)(b)=f(b)+g(b)

So

(f+g)(b)=3b+11+b^(2)+9b+10

(f+g)(-3)=3(-3)+11+(-3)^(2)+9(-3)+10

(f+g)(-3)=-6

(f+g)(-3)=-6

                             

                                   Question # 9 Solution

Answer:

(f.h)(k)=33k^3+22k-12k^2-8

Step-by-step Solution:

Given

f(k)=-11k+4

h(k)=-3k^(2)-2

We have to find (f.h)(k)

As

(f.h)(k)=f(k).h(k)

So,

(f.h)(k)=(-11k+4).(-3k^(2)-2)

\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd

∵ FOIL means (First, Outer, Inner, Last)

(f.h)(k)=\left(-11k\right)\left(-3k^2\right)+\left(-11k\right)\left(-2\right)+4\left(-3k^2\right)+4\left(-2\right)

(f.h)(k)=33k^3+22k-12k^2-8

(f.h)(k)=33k^3+22k-12k^2-8

                                 Question # 10 Solution

Answer:

p(-8)-f(-8)=-581

Step-by-step Solution:

Given

p(s)=s^(3)+6s

f(s)=-2s+5

We have to find p(-8)-f(-8)

So,

p(-8)=(-8)^(3)+6(-8)

p(-8)=-560.....[1]

and

f(-8)=-2(-8)+5

f(-8)=21.....[2]

Subtracting Equation [2] from Equation [1]

p(-8)-f(-8)=-560-21

p(-8)-f(-8)=-581

p(-8)-f(-8)=-581

Keywords: function operation

Learn more about function operations from brainly.com/question/3725682

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Answer:

-2229

Step-by-step explanation:

R/12=1 9/10 A.22 4/5 B.12 9/10 C.10 4/5 D.19/120

Answers

The correct answer is Bmultiply both sides by 12 to get the answer:R = 12

An expression is shown below.
4(6+3)+4

Answers

Answer:

40

Step-by-step explanation:

4(6+3)+4

24+12+4

=40

Answer:

40

Step-by-step explanation:

PEMDAS

(6+3)=9

4(9)=36

36+4=40

Raul calculated that he would spend $125 on school supplies this year but he accually spent 87.50 on school supplies what is his percent of error

Answers

So you would use:
[ ((V2 - V1) / |V1|) * 100 ] 
V1 = 87.5 to V2 = 125 

= ((125 - 87.5) / |87.5|) * 100 
= (37.5 / 87.5) * 100 
= 0.428571 * 100 
= 42.8571% change 

= 42.8571% increase

Hope it helps !!!!!!!!! :)

Answer:

42.85

Step-by-step explanation:

How do you solve the following equation:  a/9.05=8.2

Answers

(a)/(9.05) =8.2\ \ / \cdot 9.05 \n \n a=8.2 \cdot 9.05 =74,21


List one way a parallelogram and a rhombus are different?

Answers

a rhombus has equil side lengths and a parallelogram doesnt

A rhombus has sides that are all equal.

A parallelogram has two pairs of parallel lines, but they do not have to be all equal (just a long as they are parallel to the opposite line).