PHYSICS MIDDLE SCHOOL

A spring stores 3500 j of energy when it is stretched 1.5 meters. What is the spring constant of this spring? A) 4667 N/m B) 778 N/m C) 3938 N/m D) 3111 N/m

Answers

Answer 1

Answer:

As we know that spring potential energy is given by the formula

$U = (1)/(2)kx^2$

now it is given to us that

$U = 3500 J$

$x = 1.5 m$

now we will plug in data in above equation

$3500 = (1)/(2) k(1.5)^2$

$k = (2 * 3500)/(1.5^2)$

now we will have

$k = 3111 N/m$

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Answers

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