Y=5cos(20x) find amplitude, period & graph

Answers

Answer 1

Answer: amplitude is 5
period is 360/20 = 18 degree
Im lazy to do graph

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To solve the problem: "What is 3/4 of 12," you would _____ .
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How do I find BCD? Please help

Answers

Hi,
BCD and ECF are opposite angles and so are equal. If they are equal, then their equations are equal, and if their equations are equal, you can set the equations against each other to find x. See below, and hope this helps!

(10x - 20)° = (8x + 4)°

This is basic algebra. (I'm taking off the degree sign for now to make it simpler, but be sure to add it to your answer at the end.) Group like terms.

10x - 20 = 8x + 4
2x = -16
x = -8

Once you've found "x", plug "x" into the equation for BCD and solve. I'll get you started:

(10 × -8) - 20

all you need to do is add the angles up and you have your answer

Which of the following is the radical expression of a to the four ninths power ?

Answers

first if a>0 sqrta=a^(1/2), and (a^p)^q=a^pxq

sqrt(a^4/9)= (a^4/9)^1/2=a^4/9x1/2=a^(2/9)
so the answer is a^(2/9)

Write 5 whole numbers that can be rounded to 73 000 when rounding to the nearest 1000.

Answers

Answer:

72500

73205

72968

72758

73261

Yuto left his house at 10 a.m. to go for a bike ride. By the time Yuto’s sister Riko left their house, Yuto was already 5.25 miles along the path they both took. If Yuto’s average speed was 0.25 miles per minute and Riko’s average speed was 0.35 miles per minute, over what time period in minutes, t, starting from when Riko left the house, will Riko be behind her brother?Riko will be behind Yuto when 0 ≤ t <________ minutes.

Answers

-- When Riko left the house, Yuto was 5.25 miles ahead of her.

-- From the time she left the house, she gained (0.35 - 0.25) = 0.1 mile on Yuto
every minute ... closing the gap at the rate of 0.1 mile per minute.

-- If she can keep it up, she'll close the gap in (5.25 / 0.1) = 52.5 minutes.

-- Riko is behind her brother when 0 ≤ t < 52.5 minutes .

Answer:

52.5

Step-by-step explanation:

e2020

There are 20 cards labeled from 1 to 20 in a bag. A card is randomly selected from the bag.What is the probability of getting an even number or a 1?

9/20

11/20

1/2

3/5

Answers

Answer:

option 2=11/20 is the answer.

Step-by-step explanation:

given that there are 20 cards numbers 1,2... 20.

A card is randomly drawn.

We have to find the probability of drawing either 1 or even card.

P(drawing even card) = no of even cards/total cards = 10/20= 0.5

P(drawing one) = no of 1's/total cards = 1/20 = 0.05

P(drawing both one and even card) = 0 (since impossible)

Hence P(drawing even or one) =0.5+0.05-0

=0.55

= 11/20

Hence option 2 is the answer.

Answer : 11/20

There are 20 cards labeled from 1 to 20 in a bag. A card is randomly selected from the bag.

Total number of outcomes = 20

outcomes of an even number ={2,4,6,8,10,12,14,16,18,20}

So number of outcomes of even number = 10

outcomes of a 1 ={1}

So number of outcomes of a 1 = 1

Number of outcomes of even number and a 1 = 10+1 = 11

Probability ( any event) =number of favorable outcomes divide by total number of outcomes

Probability (getting an even number or a 1) = $(11)/(20)$

The table shows the amount that each person spend on snacks, games, and souvenirs the las time they went to the carnival.Sinea- snacks $5/ games $8/ souvenirs $12
Ren- snacks $10/ games $8/ souvenirs $20

A. Siena wants to spend money using the same ratios as on her last trip to the carnival. If she spends $26 on games, how much will she spend on souvenirs?
B. Ren wants to spend money using the same ratios as on his last trip to the carnival. If he spends $5 on souvenirs, how much will he spend on snacks?

Answers

Let

x-------> money spent in snacks

y-------> money spent in games

z-------> money spent in souvenirs

we know that

Siena's ratios

$(x)/(y) =(5)/(8) \n\n (x)/(z)= (5)/(12) \n \n (y)/(z) =(8)/(12)$

Ren's ratios

$(x)/(y) =(10)/(8) \n\n (x)/(z)= (10)/(20) \n \n (y)/(z) =(8)/(20)$

Part A) A. Siena wants to spend money using the same ratios as on her last trip to the carnival. If she spends $ $26$ on games, how much will she spend on souvenirs?

$(y)/(z) =(8)/(12) \n \n 12y=8z\n \n z=(12)/(8) y$

$y=26$ -----> money spent in games

substitute the value of y

$z=(12)/(8) y\n \n z=(12)/(8) *26\n \n z=39$

therefore

the answer Part A) is

Siena spend on souvenirs $ $39$

Part B) Ren wants to spend money using the same ratios as on his last trip to the carnival. If he spends $ $5$ on souvenirs, how much will he spend on snacks?

$(x)/(z) =(10)/(20) \n \n 20x=10z\n \n x=(1)/(2) *z$

$z=5$ ----> money spent in souvenirs

Substitute the value of z

$x=(1)/(2) *z\n \n x=(1)/(2) *5\n \n x=2.5$

therefore

the answer part B) is

Ren spend on snacks $ $2.5$

This is a problem of proportions. The initial data gives you the ratios, then you can use them to build proportions for each case. A. Siena's game to souvenier ratio is 8/12 then you can build the proportion: 8/12 = 26/x and solve for x: x = 26*12/8 = 17.33 B. Ren's souvenier to snacks ratio is 20 / 10, the the proportion is 20 / 10 = 5 / x => x = 5 * 10 / 20 = 2.5

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