MATHEMATICS MIDDLE SCHOOL

Benjamin is riding a unicycle. The tire of his unicyle has a circumference of 2.8 m, and the tire revolves 1.5 times per second. What is the distance Benjamin travels in 100 seconds?

Answers

Answer 1

Answer:

Answer:

Benjamin travels 420 m in 100 seconds .

Step-by-step explanation:

Given : The tire of his unicycle has a circumference of 2.8 m.

The tire revolves 1.5 times per second

To Find: What is the distance Benjamin travels in 100 seconds?

Solution :

Since we are given that he wheel makes 1.5 revolutions per second.

It makes revolutions in 100 seconds = $100*1.5$

= $150$

Thus it makes 150 revolutions in 100 seconds

Now, Each revolution travels 2.8 m.

So, 15 revolutions it will travel = $2.8* 150$

= $420$

Thus Benjamin travels 420 m in 100 seconds .

Answer 2

Answer:

Answer:

420m

Step-by-step explanation:

2.8mx1.5revx100s

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Express 0.5401 in scientific notation

Answers

Answer:

5.401×10^-1

Step-by-step explanation:

You move the decimal over one to get5.401×10^−1

you hav designed a picture that is shaped as a square. the dimensions of your picture are 6x6in. you want to make it into a poster with dimensions 13x13in. the duplication machine has threes settings, reduce by 75%,enlarge by 140%, or make copies,factor by 100%. howmany multiple enlargements or reductions will you need to make in order to create a poster that has its sides 13 x 13. Accurate within five hundredths

Answers

I think the answer is two just by experience of the work sheet I had done before, the teacher said it is two.

To create a poster with dimensions 13x13in, you will need to make multiple enlargements using the given settings. You will need approximately 1 enlargement.

To create a poster with dimensions 13x13in from a square picture with dimensions 6x6in, you will need to make multiple enlargements or reductions using the given settings. Since the desired dimensions are larger than the original picture, you will need to use the enlargement setting. The enlargement factor given is 140%, which means you need to increase the dimensions of the picture by 140%. Here's how many enlargements you will need:

Calculate the growth factor by subtracting 100% from the enlargement factor: 140% - 100% = 40%
Calculate the number of enlargements needed by dividing the growth factor by the enlargement factor: 40% / 140% ≈ 0.2857 (rounded to 5 decimal places)

Therefore, you will need to make approximately 0.2857 multiple enlargements, which can be rounded to 0.29 or 1 enlargement.

Learn more about Enlargements here:

brainly.com/question/27964084

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Simplify the expression by combining like terms. 1/2d−3/4d+3f−2f

Answers

Answer:

-1/4d+f

Step-by-step explanation:

First find a common denominator for the like terms 1/2d and -3/4d by multiplying 1/2d by 2/2 to get 2/4d.

Now you have common denominators so 2/4d-3/4d=-1/4d.

For the numbers that have a variable of f, 3f-2f=f.

Therefore the answer is -1/4d+f

Hope this helped!

What is the sum of three fours and four threes

Answers

The. Answer is. 145. Because. If you multiply 3 x3x3x3 which equals 81. And add 4x4x4 which equals 64. Will give you the sum of 145.

Three 4's = 12
Four 3's = 12
Sum of the two = 24

at a track meet,Jacob and daniel compete in 220 m hurdles. Daniels finishes in 3/4 of the a min.Jacob finishes with 5/12 of a min remaining.who ran the race in faster time?

Answers

Answer:

Jacob finished the race faster than Daniel.

Step-by-step explanation:

We have that,

Daniel completed the hurdle in $(3)/(4)$ of a minute i.e. 75% of a minute.

Jacob completed the hurdle with $(5)/(12)$ remaining of a minute i.e. 41.7% remaining of a minute.

Now, as we have that,

75% of a minute = 45 seconds

41.7% of a minute = 25 seconds

Since, Jacob had $(5)/(12)$ time remaining.

Thus, Jacob had = 60 - 25 = 35 seconds remaining.

So, Daniel ran in 45 seconds and Jacob ran in 35 seconds.

Hence, we get that, Jacob finished the race faster than Daniel.

Jacob

Further explanation

Given:

At a track meet, Jacob and Daniel compete in 220 m hurdles.

Daniels finishes in $(3)/(4)$ of the a min.

Jacob finishes with $(5)/(12)$ of a min remaining.

Question:

Who ran the race in faster time?

The Process:

Let us see the denominators. The least common multiple (LCM) of 4 and 12 is 12.

Let us draw the diagram that represents a minute.

$\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}$ 12 units represent in one minute.

Daniels finishes in $(3)/(4)$ of the a min.

$(3)/(4) = (9)/(12)} \rightarrow \boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}$ or 9 of 12 units.

Jacob finishes with $(5)/(12)$ of a min remaining, or 5 of 12 units. This means Jacob finishes in $(7)/(12)$ or 7 of 12 units, that is $\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}$

And now we conclude who ran the race in a faster time.

Daniels: $\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}$

Jacobs: $\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}$

Because Jacob took the race in a shorter time, he was who ran the race in a faster time.

- - - - - - - - - -

Quick Steps

Daniels: in $\boxed{ \ (3)/(4) = (9)/(12) \ }$ of the a min.

$\boxed{(9)/(12) * 60 \ minutes = 45 \ seconds}$

Jacob: in $\boxed{ \ 1 - (5)/(12) = (7)/(12) \ }$ of the a min.

$\boxed{(7)/(12) * 60 \ minutes = 35 \ seconds}$

Jacob's time is shorter, so he's the fastest.

- - - - - - - - - -

Calculate the speed

Recall $\boxed{speed = distance / time}$

Daniels: $\boxed{speed = 220 \ m / 45 \ seconds = 4(8)/(9) \ m/s \ }$

Jacob: $\boxed{speed = 220 \ m / 35 \ seconds = 6(2)/(7) \ m/s \ }$

Thus, Jacob's speed proved greater than Daniels's speed.

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Keywords: at a track meet, Jacob and Daniel, compete in 220 m hurdles, Daniels, finishes, in 3/4 of the a min, Jacob, finishes, with 5/12 of a min, remaining, who, ran, the race, in faster time, diagram

Which of the following equations is equivalent to the equation 6x – y = 1?A. y = 6x – 1
B. y = 6x + 1
C. y = -6x + 1
D. y = -6x – 1