MATHEMATICS MIDDLE SCHOOL

I need help with this question
i need help with this question - 1

Answers

Answer 1
Answer:

Answer:

The answer is 9

Step-by-step explanation:

6÷2(1+2)

6÷2=3

3(1+2)

3(3)

3*3

=9

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The product of two consecutive integers is 5 more than three time the larger. What are the integers?

Answers

When calculating consecutive integers, the smaller number is x and the larger number is (x + 1).
So the equation you can use is x + (x + 1) = 5 + 3(x + 1)
This is because the sum of the consecutive integers are equal to 5 more than 3 times the larger integer.
Now simplify:
x + (x + 1) = 5 + 3(x + 1)
2x + 1 = 5 + 3(x + 1)
2x + 1 = 5 + 3x + 3
2x + 1 = 3x + 8
Now isolate the variable:
2x + 1 = 3x + 8
Subtract 2x from both sides:
1 = x + 8
Subtract 8 from both side:
-7 = x
x = -7
So the smaller number is -7 and the larger number is -6.

Now check your answer:
-7 + (-7 + 1) = 5 + 3(-7 + 1)
-7 + (-6) = 5 + 3(-7 + 1)
-7 + (-6) = 5 + 3(-7 + 1)
-7 - 6 = 5 + 3(-7 + 1)
-13 = 5 + 3(-7 + 1)
-13 = 5 + 3(-6)
-13 = 5 + (-18)
-13 = 5 - 18
-13 = -13
This works!

So the integers are -7 and -6.

Is this right and what's the answer for number 3?

Answers

Answer: Hello!

the problems are wrong:

in the first problem, you have 38 rocks, and you can separate them into groups of 10 or in single rocks.

You have 4 options to do it:

0 groups of 10, and 38 single rocks.

1 group of ten and (38 - 19) = 28 single rocks

(this is 10 rocks in the group of then + 28 single rocks = 38 total rocks)

2 groups of ten and (38 - 2*10) =  18 single rocks

3 groups of ten and (38 - 3*10) = 8 single rocks

and you can't form more groups of tens because you only have 8 single rocks left at this point.

in the second problem, the case is the same, now you have 30 pieces of felt and you can divide them into groups of 10 or in single pieces.

then the possible options are:

0 groups of ten and 30 single pieces

1 group of ten and (30 - 10) = 20 single pieces

2 groups of ten and (30 - 2*10) = 10 single pieces

3 groups of ten and (30 - 3*10) = 0 single pieces

in the third problem you need to write, similarly as i did, why you organized the rocks or the pieces as you did.
That looks great! But say you chose number 2. You could say you organized it by multiplying single packs by the pieces of packs.

How many kilograms are equal to 5,000 grams?

Answers

1 Kilogram = 1000 Grams, so 5,000 grams = 5 kg
For every thousand grams is one kilogram so in 5000 grams is 5 kilograms. :D

An art gallery has 18 paintings and 4 photographs displayed in equal rows on a wall,with the same number of each type of art in each row.which of the following could be the number of rows?A 2 rows, B 3 rows, C 4 rows, D 6 rows

Answers

The question is asking us to determine the number of rows in which 18 paintings and 4 photographs could be displayed, such that there should be the same number of each type of art in each row. First we have to find the GCF ( the Greatest Common Factor ) of 18 and 4. 18 = 2 * 3 * 3 and 4 = 2 * 2. The prime factors of 18 are 2 and 3 and the prime factor of 4 is 2. Therefore GCF ( 18, 4 ) = 2. There could be 2 rows, with 9 paintings and 2 photographs in each. Answer: A . 2 rows.

Find all the factors of 28 the first 6

Answers

  The first 6 factors of 28 are....1, 2, 4, 7, 14, 28 
1,28 
2,14
4,7
These are all I have so far

If g(x) = x2 + 3, find g(4).
011
19
16
08

Answers

Answer:

11

Step-by-step explanation:
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