What is the elapsed time between 3:40 am and 2:00 pm?

Answers

Answer 1
Answer: 10 hours and 20 minutes is the answer. Adding 20 minutes makes it 4am. From 4am to 2pm is 10 hours.

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Answers

Answer:

The answer was B

Step-by-step explanation:

Answer:

b on edge !!!!!!!!!!!

Step-by-step explanation:

INVERSE PROPORTIONALITY ????q is inversely proportional to the square of t
when t = 5, q = 9.6
a) find the formula for q in terms of t
b) calculate the value of q when t = 8
c) when q = 2.4, calculate the value of t

Answers

easy peasy
if you had
y is inversely proportioal as x that means
y=k/x wher k is a constant

q is invesely peorportionto the square of t
q=k/(t^2)
t=5, q=9.6
easy peasy
subsiute and find k
9.6=k/(5^2)
9.6=k/25
mutiplyb oths ides by 25
240=k

the equation is
q=240/(t^2)
when t=8 then
q=240/(8^2)
q=240/64
q=3.75

q=2.4 find t
2.4=240/(t^2)
multiply both sides by t^2
2.4t^2=240
divide both sides by 2.4
t^2=100
square root both sides
t=10






a. q=(240)/(t^(2))
b. q=3.75
c. t=10

Simplify the following expression:
-9(14p - 8) - 4p

Answers

Step-by-step explanation:

-126p + 72 - 4p

-130p + 72

What is the doubling time of bacteria if you start with two bacteria and there are 128 bacteria after 3hrs?A) 15min
B) 30min
C) 45min
D) 1hr

Please explain step by step and how you got the answer. Thank you

Answers

Answer:

B) 30min

Step-by-step explanation:

Start with 2 and continue to multiply that by 2 until you get 128

2 x 2 = 4

4 x 2 = 8

8 x 2 = 16

16 x 2 = 32

32 x 2 = 64

64 x 2 = 128

Then start with what you think could be the right answer based on how many intervals there are.

You know it can't be 15 because there definitely isn't enough and you know its not 1hr because theres way more than 3.

So you're left with either B) 30min or C) 45min

It has to be B) 30min because there are 6 intervals and 30min goes into an hour twice, meaning that if every 2 intervals is an hour there are 3 hours.

On a coordinate grid, point P is at (5, 8) and point R is at (−1, −3). Points Q and S are a reflection of both points across the x-axis.What are the coordinates of Q and S?

Q(−5, 8), S(1, −3)
Q(5, −8), S(−1, 3)
Q(−5, −8), S(1, 3)
Q(−5, 8), S(−1, 3)

Answers

This is one of the fundamental transformation functions. Figure 2 points drew the taskThe x-axis is the axis of symmetry. We draw several pairs of points satisfying the conditions jobs.

see Figure 1. Different points . The x coordinate of points does not change. While the value of the y-coordinate is the number opposed . The points must be at the same distance from the axis x and at the same distance from the axis y . The x-axis is the axis of symmetry

This is one of the fundamental transformation functions. Figure 2 points drew the task

Answer 2 Q (5,-8),  R (-1.3)

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If m > n, which inequalities must be true? Check all that apply. m + 2.1 > n + 2.1 m - (-4) > n -(-4) m + 3 > n-3 16.5 + m > 16.5 + n 1 m > n + 2 9 + m > 6 + 1

Answers

Let's begin by listing out the information given to us:

m > n

We will proceed to solve the inequalities given as shown below:

\begin{gathered} If\colon m>n \n \n m+2.1>n+2.1 \n \text{Subtract ''2.1'' from both sides, we have:} \n m>n \n m+2.1>n+2.1\Rightarrow m>n \n \therefore m+2.1>n+2.1(TRUE) \n \n m-(-4)>n-\mleft(-4\mright) \n \Rightarrow m+4>n+4 \n \text{Subtract ''4'' from both sides, we have:} \n m>n \n m+4>n+4\Rightarrow m>n \n \therefore m+4>n+4(TRUE) \n \n m+3>n-3 \n \text{Subtract '3'' from both sides, we have:} \n m>n-3-3\Rightarrow m>n-6 \n m>n-6\ne m>n \n \therefore m+3>n-3(FALSE) \n \n \end{gathered}

The last three choices are below:

\begin{gathered} 16.5+m>16.5+n \n \text{Subtract ''16.5'' from both sides, we have:} \n m>n \n 16.5+m>16.5+n\Rightarrow m>n \n \therefore16.5+m>16.5+n(TRUE) \n \n m>n+2​ \n m>n+2​\ne m>n \n \therefore m>n+2​(FALSE) \n \n \n \end{gathered}

The inequalities marked as TRUE are the inequalities that apply