What number is 20% of 20
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20 move the decimal point to the left = 2
Now that we know that 10% of 20 is 2, we can find 20% by multiplying 2 by 2.
20% of 20 is 4.
Our answer is 4.
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Don't need the answer, just how you would solve this:Tobin rows 2 miles per hour faster than her opponent. If it takes Tobin 30 minutes to finish a race, and it takes her opponent 45 minutes to finish the same race, how fast does Tobin row? (A) 4 mph (B) 5 mph (C) 6 mph (D) 30 mph
the area of a rectangle is 56 square inches. the width of the rectangle is 7 in. What is the length?
Evaluate sinA for the triangle shown
(x+4)^2=
Answers
Answer:
x² + 8x + 16
Step-by-step explanation:
(x + 4)² = (x + 4)(x + 4)
Each term in the second parenthesis is multiplied by each term in the first parenthesis, that is
x(x + 4) + 4(x + 4) ← distribute both parenthesis
= x² + 4x + 4x + 16 ← collect like terms
= x² + 8x + 16 ← perfect square trinomial
Answers
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Yep, this looks good!
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You need to plug in the equations for C(x) and R(x) into the equation P(x)= R(x) - C(x) and solve.
P(x) = R(x) - C(x)
P(x) = (
P(x) =
P(x) =
Hope this helps!
x
(minutes) y
(candies)
3 90
6 180
9 270
12 360
Machine K: y = 26x
How many more candies could machine J pack than machine K in 11 minutes?
30
44
90
330
Answers
30
Now that you know 30 is the slope, you can plug that and one set of coordinates, I'll use (3,90) into point-slope form.
y - y_1 = m(x - x_1) Substitute in your x and y coordinates and slope
y - 90 = 30(x - 3) Use the Distributive Property
y - 90 = 30x - 90 Add 90 to both sides
y = 30x
Now you have the equations for both machines. You want to find out how many candies each machine packages in 11 minutes, and x represent minutes, so plug 11 into the x value for both equations.
Machine J
y = 30x Substitute
y = 30 (11) Multiply
y = 330
Machine J packs 330 candies in 11 minutes.
Machine K
y = 26x Substitute
y = 26 (11) Multiply
y = 286
Machine K packs 286 candies in 11 minutes.
Finally, to find out how many more candies Machine J packs than Machine K, subtract the two values.
330 - 286 = 44
Machine J can pack 44 more candies than Machine K in 11 minutes.
Answers
The equations are as follows where x represents the number of minutes the cell phone is used.
For plan one: Total cost = $20 + $0.15x
For plan two: Total cost = $35 + $0.10x
For both the costs to be the same, we need to use the cell phone for
300 minutes.
What are equations?
Equations are relations showing the value of one quantity related to another quantity when it can change. The changing value is the variable.
How do we solve the given question?
We are informed that one cell phone plan charges $20 per month plus $0.15 per minute used. A second cell phone plan charges $35 per month plus $0.10 per minute used.
We are asked to write and solve an equation to find the number of minutes you must talk to have the same cost for both calling plans.
Let the number of minutes the cell phone is used be x minutes.
Now we solve for equations for both plans in the following way:-
Plan one:
Charges $20 per month plus $0.15 per minute used.
When the use is for x minutes, the additional charge = $0.15*x = $0.15x
∴ Total cost = Fixed cost + Additional cost
or, Total cost = $20 + $0.15x.
Plan two:
Charges $35 per month plus $0.10 per minute used.
When the use is for x minutes, the additional charge = $0.10*x = $0.10x
∴ Total cost = Fixed cost + Additional cost
or, Total cost = $35 + $0.10x.
We are asked to find the number of minutes used so that the costs in both the plans are equal. To find this we equate the equation of total costs in both the cases to get:
$20 + $0.15x = $35 + $0.10x.
Subtracting ($20 + $0.10x) from both sides of the equation, we get
$20 + $0.15x - ($20 + $0.10x) = $35 + $0.10x - ($20 + $0.10x).
or, $20 + $0.15x - $20 - $0.10x = $35 + $0.10x - $20 - $0.10x.
or, $0.05x = $15
Dividing both sides of the equation by $0.05, we get
$0.05x/$0.05 = $10/$0.05
or, x = 300.
∴ We must talk for 300 minutes for both the plans to cost the same to us.
Learn more about equations at
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Answer: 300 minutes