The control group in an experimental study will __________.

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Answer 1

Answer:

Answer:

receive no treatment during the experiment

Explanation:

Answer 2

Answer: Give you something to compare your results with. It's always nice to be able to see what changes have been made to the original, even if it's not technically the original (I know that was worded weird, I just don't know how else to explain it.) Hope this helped!

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A truck is moving around a circular curve at a uniform velocity of 13 m/s. If the centripetal force on the truck is 3,300 N and the mass of a the truck is 1,600 kg what's the radius of the curve.

Answers

The radius of the curve is 81.93 metres. We can work this out byconsidering the centripetal force (Fc) = mass x centripetalacceleration.
Fc = m x u (squared)
R = mu (squared) over Fc = 1600 x (13 squared) over 3300
R = 81.93 metres

The Correct answer to this question for Penn Foster Students is: 81.94m

The approximate mass of a nickel in kilograms is

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The nickel has a mass of approximately 0.005kg

When there is no air resistance, objects of different masses dropped from rest?

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Reach the ground at the same time

An ocean-going barge is 50.0 m long and 20.0 m wide and has a mass of 145 metric ton. Will the barge clear a reef 1.50 m below the surface of the water?

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Since its mass is 145 metric tons, the barge must displace 145 metric tons of water
in order to float. 145 metric tons= 145,000 kilograms. Use the rough-but-close rule
of thumb that 1 liter of water has 1 kilogram of mass. So the barge displaces 145,000
liters, which is also 145 cubic meters of water.

(Length) x (width) x (depth of the part under water) = 145 cubic meters

Draft of the barge (depth under water) = 145 / (50 x 20) = 145/70 = 2.07 meters.

No, it will not clear the reef 1.5 meters below the surface. Either the barge will shave off the top 0.57 meter of the reef, or else the reef will do serious damage to the barge. In any case, there will be a situation.

What is the volume of a rectangular object with L = 4.00 cm W = 2.00 cm H = 0.50 cm?

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simply plug in these numbers into the Volume formula of a rectangle:
1) V=LWH
2)V=(4.00)(2.00)(0.50)
3)V=4cm^3

V=LWH
L=4
W=2
H=0.5
V=(4)(2)(0.5)
V=4cm^3

4 cubic centimeters

The gas-phase reaction between nitrogen and oxygen was carried out in a device designed to maintain constant pressure. There are two cylinders of equal volume with a reaction arrow between them. The cylinder on the left has two molecules of O 2 and two molecules of N 2. The cylinder on the right has four molecules of N O. A constant pressure is applied to both cylinders Write the balanced chemical equation for the reaction between nitrogen oxygen. Include physical states.

Answers

The balanced chemicalequation for the reaction between nitrogen and oxygen is:

2N₂(g) + 2O₂(g) —> 4NO(g)

The equation between nitrogen and oxygen can be written as follow:

N₂(g) + O₂(g) —> NO(g)

The above equation can be balance as illustrated below:

There are 2 atoms of O on the left side and 1atom on the right side. It can be balance by writing 2 before NO as shown below:

N₂(g) + O₂(g) —> 2NO(g)

Multiply the equation by 2, we have:

2N₂(g) + 2O₂(g) —> 4NO(g)

The equation is balanced!

Learn more: brainly.com/question/2399130

Answer:

2N₂(g) + 2O₂(g) ----> 2NO(g)

Explanation:

Gaseous nitrogen and gaseous oxygen reacts in a molar volume ratio of 1 : 1 to produce nitrogen (ii) oxide.

In the reaction, two molecules of nitrogen gas combines with two molecules of oxygen gas in the cylinder to form two molecules of nitrogen (ii) oxide. The equation of the reaction is given below:

2N₂(g) + 2O₂(g) ----> 2NO(g)

Nitrogen (ii) oxide is formed naturally during lightning bolts. The heat released the lightning flashes causes the nitrogen and oxygen in air to combine to form nitrogen (ii) oxide. The nitrogen (ii) oxide formed however, quickly reacts with more oxygen to form nitrogen(ii) oxide.

Nitrogen (ii) oxide is a colorless, poisonous gas. It is slightly denser than air and almost insoluble in water. it is also neutral to litmus.

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