A major stadium has 45,000 seats. If baseball fans have bought 5/8 of the seats for the next game, how many seats are available? 3. Draw a picture or a chart that shows the information and the question

Answers

Answer 1
Answer: Given:
45,000 seats
5/8 of the seats were bought for the next game.

To get the exact number of seats, we need to multiply the total number of seats by the fraction bought.

45,000 * 5/8 = (45,000 * 5) / 8 = 225,000 / 8 = 28,125 seats

5/8 of the total seats is 28,125 seats which are all unavailable.

8/8 - 5/8 = 8-5/8 = 3/8 is the fraction of the seats available.

45,000 - 28,125 = 16,875 seats available.

45,000 * 3/8 = (45,000 * 3) / 8 = 135,000 / 8 = 16,875
Answer 2
Answer:

Answer:

A. 16,875

Step-by-step explanation:

I got this correct on my test for edmentum


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Carissa and Louann both have savings accounts. Carissa has $250 in her account and deposits $80 per month. Louann has $1230 in her account and withdraws $60 per month.After how many months will they have equal amounts of money in their accounts? What amount of money will each have when it is the same amount?

It will take ____ months. Then, they will both have $ ____
in their accounts.

Answers

carissa value after x months=current+amount deposited
louan value after x months=current-amount taken out

carissa depositied=amount per month times x months=80x
louan take out=amount per month tiems x months=60x

when wil amount be equal
se equal

cariss=lousa
250+80x=1230-60x
add 60x both sides
250+140x=1230
minus 250 both sides
140x=980
divide both sides by 140
x=7

find how much that is
250+80(7)=250+560=810


7 months both have $810

I need full solution

Answers

Answer:

11= EC

Step-by-step explanation:

EC = 10 + 2 x + 19

= x + 20

So 2 x + 29 - x - 20 = 0

so x + 9 = 0

x = -9.

EC = x + 20 = -9+20 = 11.

Answer:

EC = 11 units

Step-by-step explanation:

  • first we find the value of x

10 + 2x + 19 = x + 20

2x - x = 20 - 10 - 19

x = -9

--------------------------------

check

10 + 2(-9) + 19 = -9 + 20

10 - 18 + 19 = -9 + 20

11 = 11

same value the answer is good

  • Now we find EC

EC = 10 + 2x + 19

EC = 10 + 2(-9) + 19             (remember PEMDAS)

EC = 10 - 18 + 19

EC = 11 units

Elia is training for her first marathon. she currently runs 10 mi. per week, and wants to increase her mileage by 2 mi. every week. if elia keeps to her training schedule write a formula to define the number of miles she runs each week. ( 1 point)

Answers

Answer: Required expression is given by

y=8+2x

Step-by-step explanation:

Since we have given that

Number of miles per week Elia is training for her first marathon = 10 miles

According to question, we have given that she wants to increase her mileage by 2 miles every week.

so, Equation becomes

10,12,14,16..........

Let the number of weeks be x

Since it forms an Arithmetic sequence,

As we know the formula for nth term :

a_x=10+(x-1)2\n\ny=10+2x-2\n\ny=8+2x

So, our required expression will be

y=8+2x

Answer:

y=2x+8

Step-by-step explanation:

Given is the number of miles per week Elia is training = 10 miles

And she wants to increase her mileage by 2 miles every week. Means the next week she will run 12 miles, next week she will run 14 miles and so on.

The series goes like this 10,12,14 and so on. This forms an arithmetic sequence.

Let the number of weeks be represented by x

The formula for nth term :

a = d (n - 1) + c, where d is the common difference between consecutive terms, and c = a1.

So, equation becomes a=10+(x-1)2

y=10+2x-2

y=8+2x or y=2x+8

Hence, the formula is : y=2x+8

2/√3-1 where p and q are integers. Show your working clearly. (b) Express in the form p + √q​

Answers

Answer:

Hi,

1+√(3)

Step-by-step explanation:

(2)/(√(3) -1) \n=(2*(√(3) +1))/((√(3) -1)(√(3) +1))\n=(2*(√(3) +1))/(3 -1)\n\n=\boxed{1+√(3) }

What is the square root of 325

Answers

√(325)=√(25\cdot13)=√(25)\cdot√(13)=5√(13)\approx18.03
√(325)=5√(13)\approx18

In 1985, Rick Hansen, the Man in Motion, wheeledaround the world in his wheelchair in
order to help people understand the importance of a
world without barriers for people with
disabilities. Starting on March 21, 1985, and
finishing on May 22, 1987, he went through
34 countries and travelled a total of 40 075 km. On
average, how many kilometres did he
travel on each day of his world tour? (Neither 1986
or 1987 was a leap year).

Answers