Please help on this one ?

Answers

Answer 1

Answer:

The answer is that it is lower because it is harder to get something to move than to make it continue moving due to molecular interactions and inertia.

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Which of the following occurs on March 21?a. summer solstice b. winter solstice c. vernal equinox d. autumnal equinox

Two billion people jump up in the air at the same time with an average velocity of 7.0 m/sec. If the mass of an average person is 60 kilograms and the mass of Earth is 5.98 × 1024 kilograms:
a. What is the total momentum of the two billion people?
b. What is the effect of their action on Earth?

Answers

p=m x v =60 x 7.0= 420
total momentum = 420 x 2,000,000,000=dnt have a calculator
thier effect would shake the earth and kill some organism because they jump up at the same time and they wil probably land the same time .

Answer:

if jonah from david dobrik was there then that means they all broke thri the earth lol

Explanation:

Assignment: Ultrasound and Infrasound Research Exploration Ultrasound and infrasound are categories of sound with different frequencies. These categories of sound can be used for a variety of different applications. In this research assignment, you will take a look at the industrial applications of ultrasound and infrasound. Your essay should do the following things: • Define and describe in detail (and in your own words) ultrasound and infrasound • Describe how ultrasound and infrasound are used in specific industrial applications and provide detailed examples. When conducting your research, remember to gather information from multiple sources. Start your research by defining ultrasound and infrasound. Then find ideas about industrial applications. The essay should be about 350-450 words, which is 1-1.5 typed pages, double-spaced, using 12-pt. font. Check the rubric to review how you will be graded for this assignment. plz no funny answers

Answers

Answer:

Infrasound vs. Ultrasound: Infrasound is sound that is below the lower limit of human hearing, below 20 Hz, and ultrasound is above the upper limit of human hearing, above 20,000 Hz. Individuals use infrasound - this recurrence run for checking seismic tremors and volcanoes, graphing rock and oil developments underneath the earth. Infrasound is described by a capacity to get around hindrances with little scattering.

For instance, a few creatures, for example, whales, elephants and giraffes convey utilizing infrasound over significant distances. Torrential slides, volcanoes, seismic tremors, sea waves, water falls and meteors produce infrasonic waves. Symptomatic ultrasound, additionally called sonography or demonstrative clinical sonography, is an imaging technique that utilizes high-recurrence sound waves to create pictures of structures inside your body. The pictures can give important data to diagnosing and treating an assortment of ailments and conditions.

Explanation:

idk how many words this is but its a start for u to add on to and i hope this helps and its in my own words - pls mark me brainiest

Answer:

Ultrasound vs. Infrasound Research Exploration

Beyond the limit of human hearing, ultrasound is above 20,000 Hz. Under the limit of human hearing, infrasound is below 20 Hz. Individuals use infrasound - this recurrence run for checking seismic tremors and volcanoes as well as graphing rock and oil developments beneath the earth. Infrasound is described by a capacity to get around hindrances with little scattering.

For instance, creatures like whales, elephants and giraffes convey utilizing infrasound over significant distances. Torrential slides, volcanoes, seismic tremors, sea waves, waterfalls and meteors produce infrasonic waves. Symptomatic ultrasound, additionally called sonography or demonstrative clinical sonography, is an imaging technique that utilizes high-recurrence sound waves to create pictures of structures inside your body. The pictures can give important data to diagnosing and treating an assortment of ailments and conditions.

(Not turned in yet, but this is what i have so far. Good luck 8th graders <33)

-Sav xx

A pendulum takes 10 seconds to swing through 2 complete cycles.a. How long does it take to complete one cycle?
b. What is its period?
c. What is its frequency?

Answers

Answer:

a. 5 seconds

b. 5 seconds

c. 0.2 Hz

Explanation:

a) For 2 complete cycles, time taken is 10 s.

Thus, for 1 complete cycle, the pendulum would take = 10 s÷ 2 = 5 s

b) The time period of a pendulum can be defined as time to complete 1 cycle/oscillation. This is calculated in part a. Thus, time period of the pendulum is 5 s.

c) The frequency of a pendulum can be define number of cycles/oscillations in 1 s. It takes 5 s to complete 1 cycle.

In 1 s, number of cycles = (1 ÷ 5) s⁻¹ = 0.2 Hz.

Two objects are dropped from rest from the same height. Object A falls through a distance during a time t, and object B falls through a distance during a time 2t. If air resistance is negligible, what is the relationship between A and B?

Answers

Answer:

Distance covered by B is 4 times distance covered by A

Explanation:

For an object in free fall starting from rest, the distance covered by the object in a time t is

$s=(1)/(2)gt^2$

where

s is the distance covered

g is the acceleration due to gravity

t is the time elapsed

In this problem:

- Object A falls through a distance $s_A$ during a time t, so the distance covered by object A is

$s_A=(1)/(2)gt^2$

- Object B falls through a distance $s_B$ during a time 2t, so the distance covered by object B is

$s_B=(1)/(2)g(2t)^2 = 4((1)/(2)gt^2)=4s_A$

So, the distance covered by object B is 4 times the distance covered by object A.

A coin is placed in an empty beaker. When a transparent liquid is poured into the beaker, the apparent depth of the coin is found to be 40% less than the real depth. What is the refractive index of the liquid? The options for the answer are 0.4 / 0.6 / 1.2 / 1.7

Answers

Answer:

D. 1.7

Explanation:

Refractive index can be calculated using the formula;

η =real depth/apparent depth

Assume the real depth to be-----x

Apparent depth will be : 40% less than real depth;

60/100 *x =0.6x

η = x/ 0.6 x

η = 1/0.6

η= 10/6

η = 1.66

η = 1.7

What is distance and direction of an object from its starting point

Answers

The distance and direction of an object from its starting point is called displacement. The main difference between distance and displacement is the consideration of distance in displacement. Distance is a scalar quantity, while displacement is a vector quantity. Scalar quantities don't take note of direction, while vector quantities do.

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