The soccer team is making pizzas for a fundraiser. They put1/4 of a pound of cheese on each pizza. If they have 12 one-pound packages of cheese, how many pizzas can they make?

Answers

Answer 1

Answer: 4 pizza equal 1 pound of cheese multiply 4×12=48

Related Questions

Consider a disease whose presence can be identified by carrying out a blood test. Let p denote the probability that a randomly selected individual has the disease. Suppose n individuals are independently selected for testing. One way to proceed is to carry out a separate test on each of the n blood samples. A potentially more economical approach, group testing, was introduced during World War II to identify syphilitic men among army inductees. First, take a part of each blood sample, combine these specimens, and carry out a single test. If no one has the disease, the result will be negative, and only the one test is required. If at least one individual is diseased, the test on the combined sample will yield a positive result, in which case the n individual tests are then carried out. [The article "Random Multiple-Access Communication and Group Testing"† applied these ideas to a communication system in which the dichotomy was active/idle user rather than diseased/nondiseased.] If p = 0.15 and n = 5, what is the expected number of tests using this procedure? (Round your answer to three decimal places.)
5. Water is flowing from Tower #1 to Tower #2 in the diagram below at a rate of 20 gallons perminute. Initially, Tower #1 contained 1650 gallons and Tower #2 contained 570 gallons.(a) How many gallons does each tower contain after 5minutes? Show your work.
Can anyone help me plzzzzz
Which is one of the transformations applied to the graph of f(x) = x2 to change it into the graph of g(x) = 9x? – 36X?The graph of f(x) = x2 is widened.The graph of f(x) = x2 is shifted right 4 units.The graph of f(x) = x? is shifted down 36 units.The graph of f(x) = x2 is reflected over the x-axis.
Which is the better buy?17-ounce jar of pickles for $8.842-pound jar of pickles for $25,28

The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among the TV sets in use, 18% were tuned to CSI: Shoboygan. Assume that an advertiser wants to verify that 18% share value by conducting its own survey, and a pilot survey begins with 14 households have TV sets in use at the time of a CSI: Shoboygan broadcast. Find the probability that none of the households are tuned to CSI: Shoboygan. P(none) = Find the probability that at least one household is tuned to CSI: Shoboygan. P(at least one) = Find the probability that at most one household is tuned to CSI: Shoboygan. P(at most one) = If at most one household is tuned to CSI: Shoboygan, does it appear that the 18% share value is wrong? (Hint: Is the occurrence of at most one household tuned to CSI: Shoboygan unusual?)

Answers

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(d) The event is not unusual.

Step-by-step explanation:

Let X = number of households watching the show.

The probability of the random variable x is, P (X) = p = 0.18.

The sample selected for the survey is of size, n = 14

The random variable X follows a Binomial distribution with parameter n = 14 and p = 0.18.

The probability of a Binomial distribution is computed using the formula:

$P(X=x)={n\choose x}p^(x)(1-p)^(n-x);\ x=0,1,2,...$

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

$P(X=0)={14\choose 0}(0.18)^(0)(1-0.18)^(14-0)=1*1*0.06214=0.062$

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-0.062\n=0.938$

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

$={14\choose 0}(0.18)^(0)(1-0.18)^(14-0)+{14\choose 1}(0.18)^(1)(1-0.18)^(14-1)\n=0.062+0.191\n=0.253$

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

An experiment is pulling a ball from an urn that contains 3 blue balls and 5 red balls. a.) Find the probability of getting a red ball. b.) Find the probability of getting a blue ball. c.) Find the odds for getting a red ball. d.) Find the odds for getting a blue ball.

Answers

Answer:

Step-by-step explanation:

The urn contains 3blue balls 5 red balls

a) probability of getting a red ball

P=no of favourable of outcomes /total no outcomes

P(red ball) = 5/8

b) Probability of blue ball

P(blue ball) = 3/8

c) Odds getting a red ball

odds in favour of any object = m/n

m : event to occur

n : event will not occur

Odds(red ball) = 5/3

Odds(blue) = 3/5

The dot plot shows the numbers of pets that students in a class own

Answers

Answer:

5 dots above zero

Step-by-step explanation:

Could the question be The dot plot shows the number of pets owned by the students in Jayod’s class.

The center, or the middle value, of the data set is _____.????

If it is that is the answer.

Hope this helps!! :)

Two bags hold a total of 31 baseballs. The smaller one has 13 baseballs. How many baseballs are in the larger bag?

Answers

31 in total and the smaller one has 13. So just subtract 31-13 and it means there are 18 balls in the larger bag

Nondigestible carbohydrates can be used in diet foods, but they may have Problem 7.2 effects on colonic hydrogen production in humans. We want to test to see if inulin, fructooligosaccharide, and lactulose are equivalent in their hydrogen production. Preliminary data suggest that the treatment means could be about 45, 32, and 60 respectively, with the error variance conservatively estimated at 35. How many subjects do we need to have power .95 for this situation when testing at the ????1 = .01 level?

Answers

Answer:

null hypothesis = µ1=µ2=µ3; µ1= popuation mean of inulin µ2 = population mean of fructicoligosaccharide =µ3=population mean of lactulose

alternative hypothesis =µ1≠µ2 ≠µ3

t1= µ-45/s1 / N-1

at the significance level 0.01

t at ᵅ/2 =0.005 and degree of freedom= 35-1=34 is 2.25

t1 = µ-32/s1/N-1

2.25= µ-45/s1/34

= s1/34= µ-45/2.25

=s1 =(µ-45/2.25)*34

t2= µ-32/s2/34

2.25 =µ-32/s2/34

s2/34= µ-32/2.25

s2=µ-32/2.25*34

T= 45-32/s1/sqrt34+s2/sqrt34

t at 0.005 and no of grees of freedom 68 =2.37

2.37=45-32/

or s1/sqrt34+s2/sqrt34 = 13/2.37

s1+s2 = 13/2.37 *5.83

s1+s2= 31.98 or 32

(µ1-45/2.25)*34+µ2-32/2.25*34=32

or µ1+µ2 = 2525

µ1=2525-µ2

µ1 and µ2 are not equal

thus null hypothesis is rejected

conclusion all the three components are not in equal amount in hydrogen production

Explanation : in this experiment we have to prove whether the means of insulin,fructicoligosaccharide and lactulose are equal. so even if we prove that two of them are not equal null hypothesis will be rejected. we use student-t test because we have to compare the means of two population.

4. Quadrilateral ROPQ is inscribed in a circle. Show all work on no credit. Find x and y. What is the measure of each angle of quadrilateral EFGH? What is the measure of arc HF?

Answers

Answer:

x = 55, y = 60
E = 70°, F = 120°, G = 110°, H = 60°
arcHF = 140°

Step-by-step explanation:

a) The sum of opposite angles of an inscribed quadrilateral is 180°. This lets us use angles E and G to solve for x:

(x+15) + (2x) = 180

3x + 15 = 180 . . .simplify

x +5 = 60 . . . . . divide by 3

x = 55 . . . . . . . . subtract 5

Similarly, we can use angles F and H to solve for y:

(3y -60) + (y) = 180

4y -60 = 180 . . . . simplify

y -15 = 45 . . . . . . divide by 4

y = 60 . . . . . . . . . add 15

___

b) Then the measures of the angles are ...

G = 2x = 2·55 = 110

E = 180 -G = 70

H = y = 60

F = 180 -H = 120

The angle measures are ...

m∠E = 70°, m∠F = 120°, m∠G = 110°, m∠H = 60°

___

c) short arc HF is intercepted by inscribed angle E, so the arc will have twice the measure of the angle.

arc HF = 2·m∠E = 140°

_____

Comment on the problem

Throughout, the only relation being used is that the measure of an arc is twice the measure of the inscribed angle intercepting it. For opposite angles of the quadrilateral, the sum of the two intercepted arcs is 360° (the whole circle), so the sum of the two angles is 180°.

Other Questions

A local charity sponsors a 5K race to raise money. It receives $55 per race entry and $10,000 in donations, but it must spend $15 per race entry to cover the cost of the race. Write and solve an inequality to determine the number of race entries the charity needs to raise at least $55,000.

What is the exact quotient of 434 divided by 7

4.5 lbs of carnitas / 15 sweet rolls

0.4p – 5 = 0.08p + 3Solve pls