Seriously omg don’t type answers and then stop! Just put your explanation even if you think I might not understand it idc! Just try! Please I seriously need help!! #7 (Algebra 2)
Seriously omg don’t type answers and then stop! Just put - 1

Answers

Answer 1
Answer:

Hello from MrBillDoesMath!

Answer:  6 * p^(3/2) * q^4


Discussion:

We are evaluating

sqrt  { 36 * p^3 q^8 }

where "sqrt" indicates the square root and the ^ (as in q^8) means "raised to the power of:

The square root of the product is the product of the square roots. (Say that 5 time out loud quickly!). So the above equation becomes

sqrt  { 36 * p^3 q^8 }  =

sqrt( 36) * sqrt( p^3) * sqrt (q^8)

The square root of 36 is 6 as 6* 6 = 36 so the equation equals

6 *  p ^ (3/2) * q^ (8/2)        

Note that  the square root of a number, for example, r, is the same as raising the number to the (1/2) power.  That's where the (1/2) terms came from above.

But 8/2 = 4 so the equation simplifies to

6 * p^(3/2) * q^4



Thank you,

MrB


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Answer:

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Step-by-step explanation:

got it right on edge .

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Answers

The answer would be 6

Steps: The equation of a circle is (x – h)² + (y – k)² = r²; since we are trying to find the radius we are going to focus on the r². Now if you look the equation has the 36 filled in as the r² so r² = 36; we now have to isolate the r to get the radius, how do we get the radius? We Square root the r² and 36. After we get r = 6, The radius is 6 units

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Answers

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 because u just add a 0at the hnd

Answer:

.04 .40 is the answer

Step-by-step explanation:

Suppose that x and y are real numbers, and x^2 + y^2 = 4. Find all ordered pairs (x, y) that satisfy this equation. A) (2, 0) B) (0, 2) C) (-2, 0) D) (0, -2)

Answers

Answer:

All of them satisfy the equation.

Step-by-step explanation:

x^2 + y^2 = 4

2^2 + 0^2 = 4 True

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Rearrange to make a the subject:
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Answers

Answer:

a =  (v - u)/(t)

Step-by-step explanation:

v = u + at

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     at = v - u

      a = (v - u)/(t)

How do I Solve this?

Answers

2\left|x-(6)/(3)\right|=8\n |x-2|=4\n x-2=4 \vee x-2=-4\n x=6 \vee x=-2