Solve the equation.
x/2= 5 for x
Answer:x=10
Step-by-step explanation:
multiply both sides by 2, to get x=10
Answer:
x = 10
Step-by-step explanation:
x/2 = 5
x = 5 / 1/2
x = 5 * 2
x = 10
10/2 = 5
A.
from x = −4 to x = −2
B.
from x = −2 to x = 1
C.
from x = 1 to x = 3
D.
from x = 3 to x = 4
The coordinates of vertex B′ are ____ .
The coordinates of vertex C′ are ____.
Answer:
A'(1, 1); B'(3, 2); C'(1, 2)
Step-by-step explanation:
The original points are A(1,1 ), B(2, 3) and C(2, 1).
Reflecting the triangle across the x-axis will negate every y-coordinate; this maps
(1, 1)→(1, -1); (2, 3)→(2, -3); (2, 1)→(2, -1)
Rotating the figure 90° clockwise about the origin switches the x- and y-coordinates and negates the x-coordinate; this maps
(1, -1)→(-1 -1); (2, -3)→(-3, -2); (2, -1)→(-1, -2)
Reflecting across the line y=x will negate both the x- and y-coordinates; this maps
(-1, -1)→(1, 1); (-3, -2)→(3, 2); (-1, -2)→(1, 2)
To find the coordinates of ∆ABC after reflection across the x-axis, rotation by 90°, and reflection across y = x, we would apply these transformations to each point. Initially reflected across x-axis results in (x, -y), the 90° rotation gives (-y, x), and final reflection over y = x gives (x, -y). To find A′B′C′ we would need original coordinates, but general rule follows this pattern.
In this mathematics problem, we will find the coordinates for vertex A′, B′, and C′ of ∆A′B′C′. Given a triangle ∆ABC reflected across the x-axis, then rotated 90° clockwise about the origin, and finally reflected across the line y = x, we need the original coordinates of A, B, and C to find A′B′C′. However, if we take a generic point (x, y), we can assume the following:
Assuming these transformations, we can find the final coordinates for A′, B′, and C′.
#SPJ12
r = 5
Need help!?
Answer:
The expression = 6
Step-by-step explanation:
The expression is 30/r
30/r
Substitute r=5
30/5
6