07.04 Equilibrium: Hands-On Equilibrium Demonstration Lab Part III follows a similar procedure as Part I and Part II, except you will be adding additional candies to the activity. Start with 40 candies on the reactant side of the paper. For each round, half of the candies that were on the reactant (R) side of the paper from the last round should be moved to the product side. One-fourth of the candies that were on the product (P) side of the paper from the last round should be moved to the reactant side. (If you end up with a decimal for the number to exchange, round up.) At the end of each round, count the number of candies on each side of the paper and keep track of the numbers in a data table. After five rounds, add 40 more candies to the reactant side of the paper. Continue following the instructions in Step 2 with this new amount of candy (total of 80 pieces of candy) for an additional 10 rounds. At the end of 15 total rounds, calculate the ratio (ratio = P/R) of products to reactants.

Answers

Answer 1
Answer: 0-40,0 1-20,20 2-15,25 3-13,27 4-13,27 5-13,27 6-13,27 7-13,27 8-13,27 9-13,27 10-13,27
Answer 2
Answer:

Answer:

Part 1

40   0

20  20

25  15

12  28

19  21

9  31

17  23

8  32

16  24

8  32

Part 2: (has to be done at a number of your choice)

Part 3:

40 0

20  20

25  15

12  28

19  21

9  31

49  31

34  56

48  42

24  66

41 49

10 70

28 52

14 66

31 35

47 19

Step-by-step explanation:

There's the actual ratios :) Hope this helps someone!


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A pulley with a radius of 8 inches rotates three times every five seconds. Find the
angular velocity of the pulley in radians/sec (round to the nearest hundredth). Find the
linear velocity to the nearst ft/hr. 






Answers

If the pulley rotates at a rate of 3 revolutions per second, then the period T of movement is  (1)/(3)s

a) calculate the angular velocity:

\omega=(2 \pi)/(T)\n \n \omega=(2 \pi)/((1)/(3))=6 \pi \ rad/s

b) calculate the linear velocity:

v=(2 \pi R)/(T)=(2 \pi.8)/((1)/(3))=24 \pi \ in/s \approx 75,36 \ in/s

Remember: 1 in/s = 300 ft/h

So, 75,36 in/s = 22,608 ft/h

For two functions, f(x) and g(x), a statement is made that f(x) = g(x) at x = 5. What is definitely true about x = 5?

Answers

Answer:

At x= 5 the value of both function are equal.

Step-by-step explanation:

Given that two function f(x) and g(x)

And at  x=5  

f(x)=g(x)

It means when we put x=5 in the function f(x) then we get some value and when we put x= 5 in the function g(x) then we get the same value .

Hence , the value of both function at x=5 are equal and we can say that both function intersect at the point (5,0).For example,

Let we take f(x)=x-5

and g(x)=5-x

Put  x=5 in the function f(x) then we get

f(x)=5-5=0

Now we put x=5 in the function g(x) then we get

g(x)=5-5=0

Hence, we get same value for both function .

When x = 5 then the function f(x) and g(x) are equal so when you insert 5 into the two functions, you will get the same answers for both of the functions. 

Sorry I'm not good at math but I just want to learn how to do this

Answers

the answer is 8.6. I hope this helped you out!

A particular frozen yogurt has 75 calories in 2 ounces.How much calories are in 8 ounces of the yogurt?

Answers

75/2=x/8

x=(75*8)/2

x=600/2

x=300

300 lb

What is the equation of the line that passes through the point (-3, 5) with a slope of 4?y=4-7
O y-4x+17
O y= 4x+12
O y=47-17
o y = 4x+2

Answers

Answer:

y=4x+17

Step-by-step explanation:

y-b=m(x-a)

y-5=4(x--3)

y-5=4(x+3)

y-5=4x+12

y=4x+17

Write the equation of the line that passes through (4, 2) and is parallel to the line y = 2x – 1.

Answers

y= 2x-6
for the line to be parallel with y=2x-1 it has to have the same gradient which is the 2x part. and to get it to pass through (4,2) it has to be -6 

Answer:

B

Step-by-step explanation:

2x – y = 6