Find the greatest common factor of
21
and
49
.

Answers

Answer 1
Answer: The greatest common factor (GCF) is 7.

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Simplify
1) 3b + b + 6 =
2)n + 5n - 3c =
3) 12d - 2d + e =

Answers

1. 4b plus 6
2. 6n minus 3c
3. 10d plus e

Answer:

1) 4b +6

2) 6n - 3c

3) 10d +e

Step-by-step explanation:


When you do 288 divided by 30 long division what's the remainder

Answers

(288)/(30) = (6* 48)/(6* 5) = (48)/(5) = (45+3)/(5) = (45)/(5) +(3)/(5) = 9+(3)/(5) = \boxed{\bf{9(3)/(5)}}

The divisor is 30.
The dividend is 288.
The quotient is 9.
The remainder is 3.

The remainder is 3.

Select the number line model. A, B, or C.

Answers

Answer:

I would say C, None of the above.

Step-by-step explanation:

Due to the fact that it says 8-1, so the number line should go to 8 down to 7.

If Alyssa created a family tree in the year 2001 and if grandma is 68 what year was grandma born Please show work

Answers

2001-68=1933
Grandma was born in 1933

have students write a story problem that can be solved by finding the difference of 432,906 and 61,827 then have them solve the problem

Answers

Here is a problem, Donald Trump had 432,906 supporters.  After his statement about the Mexicans, his supporters decreased by 61, 827.  Write out the equation and figure out how many supporters Donald Trump has now.  
BTW- The answer to the problem is 371, 079.

a committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions.​

Answers

Answer:

(1)/(990)

Step-by-step explanation:

The full question:

"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current​ positions?"

The permutation of choosing 3 members from a group of 11 would be:

P(n,r) = (n!)/((n-r)!)

Where n would be the total [in this case n is 11] & r would be 3

Which is:

P(11,3) = (11!)/((11-3)!)=(11!)/(8!)=11*10*9=990

So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:

1/990