Answer:Density
Explanation: The students should compute the density of the cube. Density is a physical property that can be used to identify most pure substances. The students know the length of a side so they can compute the volume. They also know the mass. Using the density formula, density =
mass
volume
, they can compute the density and identify the metal.
The initial volume of the gas is 117L.
Volume is the amount of space the matter occupies.
PV/T = k
where P = pressure, V = volume, T = absolute temperature in K and k= constant.
P1V1 / T1 = P2V2 / T2
Where P1 and P2 = initial and final pressure in atm
T1 and T2 = Initial and final temperature in K
V1 and V2 = initial and final volume in L
Using combined gas law:
P1V1/T1 = P2V2/T2
Given:
P1 = 0.5 atm
T1 = 325K
P2 = 1.2 atm
V2 = 48L
T2 = 320K
Assuming that the number of moles are constant for both conditions:
(P1 x V1)/T1 = (P2 x V2)/T2
Substituting the given values,
(0.5 x V1)/325 = (1.2 x 48)/320K
Solving for V1
V1 = (1.2atm x 48L x 325K)/ (320Kx 0.5 atm)
V1 = 117L
Hence, the initial volume of the gas is 117L.
To learn more about combined gas law here
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Answer:
Explanation:
1) Data:
a) mass of solute = ?
b) volume of solution = 1.25 liter
c) M = 2.92 mol/liter
d) solute NaOH
2) Formulae:
a) Molarity, M = number of moles of solute / volume of solution in liters
b) mass in grams = molar mass × number of moles
3) Solution:
a) Calculate number of moles of solute:
⇒ number of moles of solute = M × volume of solution in liters
⇒ number of moles of solute = 2.92 mol/liter × 1.25 liter = 3.65 mol
b) Molar mass of NaOH = 39.997 g/mol (you can take this number from internet or calculate it using the atomic masses of Na, O, and H).
c) Calculate the mass of solute:
The answer must be reported with 3 significant figures, so it is 146. g.
Answer:
3) Each sample has the same number of molecules
Explanation:
1 mol are 6,022x10²³ particles. Moles of a chemical substance represent the number of molecules that this chemical has.
Thus, one mol of oxygen are 6,022x10²³ molecules of oxygen and one mol of nitrogen are 6,022x10²³ molecules of nitrogen.
Right answer is:
3) Each sample has the same number of molecules.
I hope it helps!
(2) a gamma ray (4) a proton