At the market, 5 light bulbs cost $9.85 How much do 7 light bulbs cost?

Answers

Answer 1
Answer: Divide 9.85 by 5 to get the cost of one, and that is 1.97. Then mutiply 1.97 by 7 to get the cost of 7 of them, and that is 13.79. So the answer is 13.79. Hope this helps.
Answer 2
Answer: Cost of one light bulb: $1.97

I found this my dividing 9.85 by 5. Next we need to multiply 1.97 by 7 to get 13.79.

Answer: 7 light bulbs cost $13.79'
Hope this helps
:)

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Claire walked 2 2/5 miles. Jason walked 2/3 as far as Claire. How many miles did Jason walk?

Using coordinate geometry, prove that Quadrilateral MIKE is a Parallelogram:

Answers

Answer: It has two pairs of parallel lines

Step-by-step explanation:

coordinates of E (-4,4)  K (4,4)   M(-6,-3) I( 2,-3)

The distance from E to K is 8  the same as the distance from M to I.

The distance from M to E is  about 7.3 and the distance between K and I is the the same thing.

Answer:

Counting the unit on graph, we observes:

EK = MI = 8

EK // MI // x-axis

=> MEKI is parallelogram

Hope this helps!

:)

Write the coordinates of the vertices after a reflection over the line y=3?​

Answers

Answer:

L(4,-3)  -> L'(4,9)

M(4,3)  -> M'(4,3)

N(-4,3) -> N'(-4,3)

K(-4,-3) -> K'(-4,9)

Step-by-step explanation:

Reflection of an object means to flip that object on a line called the axis of reflection or line of reflection or mirror line.

Line of reflection here is y = 3

So, after a reflection over the line y = 3

Co ordinates

L' =  (4,9)

M' = (4,3)

N' = (-4,3)

K' = (-4,9)

Final answer:

A reflection over the line y=3 changes the y-coordinate of a point to 2*3 minus its original y-coordinate, keeping the x-coordinate the same.

Explanation:

To find the coordinates of the vertices after a reflection over the line y=3, one should understand that a reflection over a horizontal line, such as y=3, changes the y-coordinate of each point while keeping the x-coordinate the same. For instance, if you have a point (a, b), after reflecting over the line y=3, the new point would be (a, 2*3-b). This is because the difference between the y-coordinate of the point and the line of reflection (3 in this case) would be the same before and after reflection, but with a different sign.

For example, if you have a vertex at (2, 5), to find its new position after reflection, you would keep the x-coordinate (2) the same, and calculate the new y-coordinate as (2*3 - 5) = 1. So, the reflected vertex would be at (2, 1). Apply this same method to all vertices to find their new positions after reflection.

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Who can help me please!!!!

Answers

Question 1- B.
4
— = 0.444444444444444
9
Since the 4 repeats, just put the – on top of the second 4.

Question 2- C
If s is the number of students going, and you want to break them up into groups of 12, divide the total number of students by 12 to figure out how many groups there will be to find out how mang adults are required.

Question 3- A
There is a 25% chance of snow. There isnt a 0% chance so it isnt impossible. There isnt 100% chance so it isnt certain. Since it is less then 50% it is unlikely.


question 1:
                                       __
4/9=0.44444444...=0. 44
                          __
Answer: B) 0.44

Question 2:

1/12=a/s    ⇒a=s/12

Answer: C     a=s/12

Question 3:

Answer: B) Likely.

15^1/5 rewrite in radical form

Answers

Answer:

\sqrt[5]{15}

Step-by-step explanation:

A number to 1/5 is the \sqrt[5]{n}

A number to 1/3 is the \sqrt[3]{n}

So, since the number is 15 to the 1/5, it is \sqrt[5]{15}

Answer:  \sqrt[5]{15}

Answer:

15^{(1)/(5) } = \sqrt[5]{15}

Step-by-step explanation:

recall that

a^{(1)/(b) }  = \sqrt[b]{a}

if we apply this to our case,

15^{(1)/(5) } = \sqrt[5]{15}

Consider this function.F(x) = x - 4 + 6
If the domain is restricted to the portion of the graph with a positive slope, how are the domain and range of the function and
its inverse related?
Since the domain of the original function is limited to x 6, the range of the inverse function is y s6.
Since the domain of the original function is limited to x> 4. the range of the inverse function is ys 1.
Since the range of the original function is limited to y > 6, the domain of the inverse function is x 26
Since the range of the original function is limited to y 4, the domain of the inverse function is x 1.​

Answers

The answer is the statement Since the range of the original function is limited to y > 6, the domain of the inverse function is x ≥ 6.

What is the domain of an inverse function?

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.

What is a positive slope?

The positive slope definition tells us that a line with a positive slope is one where the right side of the line is higher than the left side of the line.

So, by the definition given above, we see that

if the range of the original function is limited to y > 6, the domain of the inverse function is x >= 6.

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Answer:

Since the range of the original function is limited to y  6, the domain of the inverse function is x ≥ 6.

Step-by-step explanation:

Work out the value of 4(2x+3y) when x=8 and y=-3

Answers

4(2 x 8 + 3 x (-3))
4(16 + (-9))
4(7)
=28

Final answer:

To find the value of 4(2x+3y) when x=8 and y=-3, substitute the given values into the expression. Simplify the expression and solve for the value.

Explanation:

To find the value of 4(2x+3y) when x=8 and y=-3, we substitute the given values into the expression. So, we have:

4(2(8)+3(-3))

Simplifying, we get:

4(16-9)

4(7)

Finally, we multiply 4 by 7 to get the answer: 28

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