To fit in an existing frame, the length, x, of a piece of glass must be longer than 12 cm but not longer than 12.2 cm. Which inequality can be used to represent the lengths of the glass that will fit in the frame

Answers

Answer 1
Answer: 12cm < x >12.2 cm is the inequality i would use

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How many roots do the following equations have? -12x^2 - 25x+5 +x^3=0

Answers

Answer:

There are 3 roots of the given equation.

Step-by-step explanation:

Given the equation      

-12x^2-25x+5+x^3=0

we have to tell the number of roots of the given equation.

As the number of roots for an equation is equal to degree.

The degree of a polynomial is the highest power of its monomials  with non-zero coefficients.

Hence, number of roots is the highest power in the equation.

Now, the equation is -12x^2-25x+5+x^3=0

The highest power i.e degree of equation is 3.

hence, there are 3 roots of the given equation.

-12x^2 - 25x + 5 + x^(3) = 0
x^(3) - 12x^(2) - 25x + 5 = 0
x = \sqrt[3]{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a)) + \sqrt{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a))^(2) + ((c)/(3a) - (b^(2))/(9a^(2)))^(3)}} + \sqrt[3]{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a)) - \sqrt{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a))^(2) + ((c)/(3a) - (b^(2))/(9a^(2)))^(3)}} - (b)/(3a)
x = \sqrt[3]{((-(-12)^(3))/(27(1)^(3)) + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1))) + \sqrt{((-(-12)^(3))/(27(1)^(3)) + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1)))^(2) + ((-25)/(3(1)) - (-(-25)^(2))/(9(1)^(2)))^(3)}} + \sqrt[3]{((-(-12)^(3))/(27(1)^(3))}} + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1))) - \sqrt{((-(-12)^(3))/(27(1)^(3)) + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1)))^(2) + ((-25)/(3(1)) - (-(-25)^(2))/(9(1)^(2)))^(3) - (-12)/(3(1))}}
x = \sqrt[3]{((-(-1728))/(27(1)) + (300)/(6(1)) - (5)/(2)) + \sqrt{((-(-1728))/(27(1)^(3)) + (300)/(6(1)) - (5)/(2))^(2) + ((-25)/(3(1)) - (144)/(9(1)))^(3)}}} + \sqrt[3]{((-(-1728))/(27(1)) + (300)/(6(1)) - (5)/(2)) - \sqrt{((-(-1728))/(27(1)^(3)) + (300)/(6(1)) - (5)/(2))^(2) + ((-25)/(3(1)) - (144)/(9(1)))^(3)}}} - (-12)/(3)
x = \sqrt[3]{((1728)/(27) + (300)/(6) - 2(1)/(2)) + \sqrt{((1728)/(27) + (300)/(6) - 2(1)/(2))^(2) + ((-25)/(3) - (144)/(9))^(3)}} + \sqrt[3]{((1728)/(27) + (300)/(6) - 2(1)/(2)) - \sqrt{((1728)/(27) + (300)/(6) - 2(1)/(2))^(2) + ((-25)/(3) - (144)/(9))^(3)}} - 4
x = \sqrt[3]{(64 + 50 - 2(1)/(2)) + \sqrt{(64 + 50 - 2(1)/(2))^(2) + (-8(1)/(3) - 16)^(3)}} + sqrt[3]{(64 + 50 - 2(1)/(2)) - \sqrt{(64 + 50 - 2(1)/(2))^(2) + (-8(1)/(3) - 16)^(3)}} - 4
x = \sqrt[3]{(114 - 2(1)/(2)) + \sqrt{(114 - 2(1)/(2))^(2) + (-24(1)/(3))^(3)}} + \sqrt[3]{(114 - 2(1)/(2)) - \sqrt{(114 - 2(1)/(2))^(2) + (-24(1)/(3))^(3)}} - 4
x = \sqrt[3]{(112(1)/(2)) + \sqrt{(112(1)/(2))^(2) - (24(1)/(3))^(3)}} - \sqrt[3]{(112(1)/(2)) + \sqrt{(112(1)/(2))^(2) - (24(1)/(3))^(3)}} - 4
x = \sqrt[3]{112(1)/(2) + √(12656.25 - 14408.037)} + \sqrt[3]{112(1)/(2) + √(12656.25 - 14408.037)} - 4
x = \sqrt[3]{112(1)/(2) + √(-1751.787)} + \sqrt[3]{112(1)/(2) - √(-1751.787)} - 4
x = \sqrt[3]{112(1)/(2) + 41.855i} + \sqrt[3]{112(1)/(2) - 41.855i} - 4
x = -4 + \sqrt[3]{112(1)/(2) + 41.855i} + \sqrt[3]{112(1)/(2) - 41.855i}

95% of 120 games played

Answers

since 5% of 120 is the same as 1/20 then we can figure out that 5% is 6. Then divide 95 by 5 to get 19. Finally multiply 19*6 to get 114 

A businessman buys 1,440 dozen pens at $2.50 a dozen and then sells them at a price of 25¢ apiece. What is his total profit on the lot of pens?

Answers

he spend: 1440*2.5=3600 
he earn: 0.25*1440*12=4320
[because he sells 0.25/each and buy 1440 dozen so 1440*12]

4320-3600=720

Blue beads are 5 millimeters long and red beads are 10 millimeters long. How long is the basic bead pattern (brrrr b) in millimeters?​

Answers

Answer:

50

Step-by-step explanation:

  • blue=5
  • r⁴=40
  • B=5
  • totally of 50milimeters

Answer: 50 millimeters

Cuantas horas hay de diferencia entre el meridiano qué pasa por el Perú y si antípoda

Answers

Answer:

y 5 horas entre mediterráneo que pasa por Perú

In Vancouver, the high temperature for the day was 6° C. On the same day, the high temperature in Calgary was −3° C. What was the difference in high temperatures between the two cities?

Answers

Answer:

9

Step-by-step explanation:

|6|+|-3|=9