Find the equation of the line perpendicular to the line y=4x+5, passing through the point (0,-3)

Answers

Answer 1
Answer:

Answer:

y=-0.25x-3

Step-by-step explanation:

-3=-1/4*0+b

b=-3


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Clayton Road is 2.35 miles long. Wood Pike Road is 1.7 miles long. Draw a quick picture to find the combined length of Clayton Road and Wood Pike Road

Answers

Answer:

4.05 miles.

Step-by-step explanation:

See the attached diagram. (not in scale)

Let AB is the Clayton Road and its length is 2.35 miles and BC is the Wood Pike Road and it is 1.7 miles long.

So, the combined length of Clayton Road and Wood Pike Road is AC (= AB + BC)

So, the length of AC will be (2.35 +1.7) miles = 4.05 miles. (Answer)

Explain to me the rule of pemdas in order of operations.

Answers

parenthesis
exponents
multiplication/division
addition/subtraction

when given a math problem you must go through these operations from top to bottom to recieve the correct answer
Hi There!

PEMDAS is a term in math in order of operations. 

Here is what this means
Paranthesis
exponents
multiplication/division (left to right)
addition/subtraction (left to right)

In order of operations, you use pemdas in order so the P, would come first, E second, and so on.

Example 1: (10+9)-1, in this example, since parenthesis is first you would solve 10+9=19 and then you would subtract that by one 19-1=18

In conclusion this is the rule of pemdas.

Hope this helps :)

Every morning Jim runs for 20 minutes if Jim runs for 9 miles per hour how far does he travel

Answers

First we have to know how much of one hour is 20 min.
To get it, we have to dividie 20min by 60 min (60 min=1hour), so
20:60=(20)/(60)= (2)/(6)= (1)/(3)

We know that
v= (s)/(t)
where v is velocity, s is distance and t is time
We can modify formula to get

v= (s)/(t) \n v*t=s
Now we just have to substitute our data ( t=1/3 and v=9 miles/hour)
s=(1)/(3)*9=3 miles - its the result
One hour is sixty minutes, so if he runs nine miles in one hour and he only runs for twenty minutes than it should be 9/3= 3 miles

What two integers do 199 fall between

Answers

Between 198 and 200, I believe.

What is the greatest common factor of 8 and 9

Answers

The greatest common factor of 8 and 9 is 1. The largest positive integer that divides two numbers without producing a remainder is known as the greatest common factor (GCF).

We have the numbers 8 and 9 in this instance. We must uncover the elements that both numbers have in common and choose the biggest one to determine their GCF. In comparison to the factors of 9, which are 1, 3, and 9, the factors of 8 are 1, 2, 4, and 8.

The highest positive integer that divides both 8 and 9 is 1, hence the only factor they have in common is that. Therefore, 1 is the number that connects 8 and 9 most frequently.

To know more about factor :

brainly.com/question/14452738

#SPJ6.

Answer:The factors of 8 are: 1, 2, 4, 8

The factors of 9 are: 1, 3, 9

Then the greatest common factor is 1.

Step-by-step explanation:How to Find the Greatest Common Factor (GCF)

There are several ways to find the greatest common factor of numbers. The most efficient method you use depends on how many numbers you have, how large they are and what you will do with the result.

Factoring

To find the GCF by factoring, list out all of the factors of each number or find them with a Factors Calculator. The whole number factors are numbers that divide evenly into the number with zero remainder. Given the list of common factors for each number, the GCF is the largest number common to each list.

Example: Find the GCF of 18 and 27The factors of 18 are 1, 2, 3, 6, 9, 18.

The factors of 27 are 1, 3, 9, 27.

The common factors of 18 and 27 are 1, 3 and 9.

The greatest common factor of 18 and 27 is 9.

Example: Find the GCF of 20, 50 and 120

The factors of 20 are 1, 2, 4, 5, 10, 20.

The factors of 50 are 1, 2, 5, 10, 25, 50.

The factors of 120 are 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120.

The common factors of 20, 50 and 120 are 1, 2, 5 and 10. (Include only the factors common to all three numbers.)

The greatest common factor of 20, 50 and 120 is 10.Prime Factorization

To find the GCF by prime factorization, list out all of the prime factors of each number or find them with a Prime Factors Calculator. List the prime factors that are common to each of the original numbers. Include the highest number of occurrences of each prime factor that is common to each original number. Multiply these together to get the GCF.

You will see that as numbers get larger the prime factorization method may be easier than straight factoring.

Example: Find the GCF (18, 27)

The prime factorization of 18 is 2 x 3 x 3 = 18.

The prime factorization of 27 is 3 x 3 x 3 = 27.

The occurrences of common prime factors of 18 and 27 are 3 and 3.

So the greatest common factor of 18 and 27 is 3 x 3 = 9.

Example: Find the GCF (20, 50, 120)

The prime factorization of 20 is 2 x 2 x 5 = 20.

The prime factorization of 50 is 2 x 5 x 5 = 50.

The prime factorization of 120 is 2 x 2 x 2 x 3 x 5 = 120.The occurrences of common prime factors of 20, 50 and 120 are 2 and 5.

So the greatest common factor of 20, 50 and 120 is 2 x 5 = 10.

Paula caught a tarpon with a weight that was 10 times as great as the weight of a permit fish she caught. the total weight of the two fish was 132 pounds. How much did each fish weight.

Answers

60 poundage and 6 pounds