MATHEMATICS MIDDLE SCHOOL

What is the volume enclosed by the slanted prism in the diagram 225cm
270cm
300cm
540cm
What is the volume enclosed by the slanted prism in - 1

Answers

Answer 1
Answer:

To find the volume of a slanted prism, all you need to know is the area of the base and the height of prism. If you know these two things, then the volume of a prism can be calculated using formula

V_(prism)=A_(base)\cdot H_(prism).

Since A_(base)=25 cm^2 and H_(prism)=9 cm, you have

V_(prism)=25\cdot 9=225 cm^3.

Answer: correct choice is A.
Answer 2
Answer: we know that
volume of the slanted prism is equal to
V=B*h
where
B is the area of the base------> B=25 cm^(2)
h is the height of the prism-----> h=9 cm
so
V=25*9 \n V=225 cm^(2)

the answer is the option 
225 cm^(2)

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You roll a six sided die two times what is the probability the two numbers are one apart
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The pre-image point B(-4, 3) is translated to B'(-1, 1). What was the translation used?A. ( x + 3, y + 2)B. ( x - 3, y - 2)C. ( x + 3, y - 2)D. ( x - 3, y + 2)
5 times what equals 200

Chris brought 2 umbrellas each costing $13.He brought 3 ponchos each costing $4 how much did Jack spend in all

Answers

We know that 2 umbrellas each cost $13, so 13*2=26 and we also know that he brought 3 ponchos that cost $4, so 4*3=12. The question asks how much did Jack spend in all. In all means add, so we add 26+12 which equals 38. So, Jack spent $38.
Jack would have spent a total of 38 dollars all together

What are the first three common multiples of 5 and 15

Answers

The first 3 common multiples of 5 and 15 are 15, 30, and 45. Remember that the number itself is also a multiple of any number, since you can multiply it by 1.

5 - 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100
15 - 15, 30, 45, 60, 75, 90, 105

Hope this helps!

Can someone please help me with #10. i need the one with solution. thanks!

Answers

Problem 10
One foot is equal to 0.333 yards, so convert the feet to yards.
One inch is equal to 0.0278 yards.
(36 feet × 0.333 = 12) 36 feet = 12 yards 
(24 feet × 0.333 = 8) 24 feet = 8 yards 
(9 inches × 0.0278 = 0.25) 9 inches = 0.25 yards 
Now, multiply it all together (L × W × H).
12 × 8 × 0.25 = 24 yards
Then multiply the number of cubic yards.
24 × 55= $1320
The answer is $1320
The reason this problem is so sneaky is that it has a lot of
different units in it, and you have to keep them all straight.

Volume of concrete for the patio = (length) x (width) x (height).

You know all of these dimensions, but be careful.  Before
you multiply them, they must all be in the same units.

          Length  =  36 ft
          Width  =  24 ft
          Height  =  9 inches  =  3/4 of a ft  (0.75 ft).

NOW you can multiply to get the volume.

         Volume = (36 ft) x (24 ft) x (0.75 ft) .

                       The result is the volume in ft³  (cubic feet).

Now you need to figure out how much this will cost, but you run into
another problem . . . you know how much each yd³ costs, but you
only have the volume in ft³.  You have to change the ft³ into yd³ .

Here's the tool you need to do that:      1 yd³ = 27 ft³
 
The rest is just arithmetic.  I know you can handle it from this point.

Solve each system of linear equations by substitution.3x - 2y = 9
y = 2x - 7 Pease show all steps

Answers

3x-2(2x-7)=9 \n 3x-4x+14=9 \n -x+14=9 \n -14\ \ \ \ -14 \n -x=-5 \n /-1/-1 \n \ \ x=5
3x-2y=9 will be
3x-9=2y and
(3x)/2-9/2=y

2) y=2x-7

if you mean the intersection , so y=y
(3x)/2-9/2=2x-7
1,5x-4,5=2x-7
-4,5+7=2x-1,5x
2,5=0,5x
x=2,5/0,5
x=5 is the answer

Question 2. I give thanks and 5 stars :D

Answers

OK! I usually find the Lateral Area first. To do this you would take the outside side, not the circle bases. To find the LA you would do 2 times pi times the radius times the height of the cylinder, so 2πrh. THen you would find the SA of the bases, you would do pi times r squared, so πr^2. So, to find the SA of a cylinder, you would do 2πrh + πr^2

What is the LCM of 40 and 15?

Answers

LCM\ is\ the\ least\ common\ number\ that\ is\ multiply\ of\ both:\n\n Factors\ of\ 40\n40:2\n20:2\n10:2\n5:5\n\n Factors\ of\ 15\n15:3\n5:5\n\n LCM(24,38)=2^3*3*5=120\n\n \textbf{LCM(40,15)=120}
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