Which statements correctly describe the decay rates of radioactive isotopes? a} It takes two half-lives for a sample to fully decay.
b} The exact time when an individual atom will decay can be accurately predicted.
c} After each half-life, the amount of radioactive material is reduced by half.
d) All radioactive isotopes have the same half-life.
e} The decay of individual atoms in a sample of radioactive material is random.
Answers
Answer: b} The exact time when an individual atom will decay can be accurately predicted.
c} After each half-life, the amount of radioactive material is reduced by half.
Explanation:
All radioactive decay follows first order kinetics.
Rate law expression for first order kinetics is given by:
where,
k = rate constant
t = time taken for decay process
a = initial amount of the reactant
a - x = amount left after decay process
Expression for calculating half life, which is the time taken by the half of the reactants to decompose is:
Answer:
For plato, the answer is C: after each half tile, the amount of radioactive material is reduced by half
Related Questions
A ______________________ is required to cause atoms to bond together or be separated from one another. *a physical changeb phase changec radioactive decayd chemical reaction
A chemist fills a reaction vessel with 0.750 M lead (II) (Pb2+) aqueous solution, 0.232 M bromide (Br) aqueous solution, and 0.956 g lead (II) bromide (PbBr2 solid at a temperature of 25.0°C. Under these conditions, calculate the reaction free energy AG for the following chemical reaction: Pb2+ (aq) + 2Br (aq) = PbBr2 (s) Use the thermodynamic information in the ALEKS Data tab. Round your answer to the nearest kilojoule.
Calculate the molar mass of each compound given below. c4h4
In the following structure, carbons (I),(2),(3) and (4) are classified respectively as
Answers
Answer:
1. C
2.B
Explanation:
a) air
b) land
c) water
d) birds in the air
e) trees on land
f) organisms in the water
Answers
The resources and organisms are affected by oil spillages are Air, Water, and Organisms in water
Effect of oil spillage
Oil spillage can cause to the general environment and the organisms in the environment.
Based on the passage, the resources and organisms are affected by oil spillages include the following;
- Air
- Water, and
- Organisms in water
Learn more about oil spillage here: brainly.com/question/2880031
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Answer:
A,C,F/Air,water,orginisams in water
Explanation:
Answers
Answer:no
Explanation:
Answer:
Scandium is a transition metal
Explanation:
Answers
The amount left after 1 half life = 16*1/2 = 8 g Then after each half life the amount of x will be 4 , 2 ,1 , 1/2, 1/4 grams
That's a total of 6 half-lives. Answer
Age s rock = 6*220,000 = 1,320,000 years Answer
Answers
Answer:
Limiting reagent: AgNO3
grams AgCl : 2.44 g AgCl
grams of excess reagent remain: 0.62 g BaCl2
Explanation:
1. Change grams to mol:
AgNO3:
5.738g x (1mol/169.87g) = 0.034 mol AgNO3
BaCl2:
4.115g x (1 mol/208.23g) = 0.020 mol BaCl2
2. Limiting reagent:
AgNO3:
0.034 mol AgNO3 x (1 mol BaCL2/ 2mol AgNO3) = 0.017 mol BaCl2
BaCl2:
0.020 mol BaCl2 x (2 mol AgNO3/1 mol BaCl2) = 0.04 mol AgNO3
Limiting reagent: AgNO3
3. Grams of AgCl produced:
Using the limiting reagent:
0.017 mol AgNO3 x (2mol AgCl / 2 mol AgNO3) = 0.017 mol AgCl
4. Change mol to grams:
0.017 mol AgCl x ( 143.32 g AgCl /1mol AgCl) =2.44 g AgCl
5. Grams of the excess reagent:
0.034 mol AgNO3 x (1 mol BaCl2 / 2 mol AgNO3) = 0.017 mol BaCl2
0.020 mol BaCl2 - 0.017 mol BaCl2 = 0.003 mol BaCl2
0.003 mol BaCl2 x ( 208.23 g BaCl2 / 1 mol BaCl2) = 0.62 g BaCl2
Answers
Answer:
2.14x10¹⁹ atoms of Cu were deposited
Explanation:
The increased in mass of the glass slide is due the deposition of copper.
That means the mass of copper deposited is 2.26mg = 2.26x10⁻³g Cu
To know the copper atoms we need to convert this mass to moles of Cu using molar mass of copper (63.546g/mol), and these moles are converted to atoms using Avogadro's number (6.022x10²³ atoms = 1 mole)
Moles Cu:
2.26x10⁻³g Cu * (1 mol / 63.546g) = 3.556x10⁻⁵ moles Cu
Atoms Cu:
3.556x10⁻⁵ moles Cu * (6.022x10²³ atoms / 1 mole) =
2.14x10¹⁹ atoms of Cu were deposited