Which values from the specified set make up the solution set of the inequality?5w–10>20 ; {5,6,7,8}

Select each correct answer.

5
6
7
8

Answers

Answer 1
Answer:

5w - 10 > 20      add 10 to both sides

5w > 30     divide both sides by 5

w > 6

Answer: 7 and 8.

Answer 2
Answer:

Answer: 7 and 8

Step-by-step explanation:


Related Questions

What are the operations to get1,a) 4-25, 5-32, 6-39, 7-462,a) 25-15, 30-18, 35-21
What is a quotient in math
Can someone please run the answer
An assistant receives a 10% raise bringing the salary to 47,633 what was the salary before the raise
Jim buys two boxes of apples. 90% of the total apples are ripe.Each box contains 15 apples.How many apples are unripe?

What is the square root of 10 000

Answers

√(10,000) = √(100 * 100) =√(100^2) = (100^2)^{(1)/(2)} =100^{2* (1)/(2)} = 100^1 = \boxed{\bf{100}}

100 is your answer. :)

√10000
=100
(100)²= 100x100=10000

Factorise 56x + 35. Need to know asap please.

Answers

The answer is 7(8x+5)

What is the value of x?

Answers

There are two things you can do.
Firstly, you can add 4 plus 7 and then 90 degrees divided by 11.
Or, multiply 4 times 7 and then 90 divided 28. 
I do not know if this was helpful.

What is the approximate volume of the cone? Use 3.14 for pi

A. 1206 cm
B. 2170 cm
C. 3260 cm
D. 6510 cm

Answers

Answer:

A

Step-by-step explanation:

V=(pi)(r^2)(h/3)

This is the formula for volume

V=3.14(12^2)(8/3)

plug this into a calculator and make sure you use parenthesis!

V=1205.76

The answer is A

The population of a town was 89,443 in 1990 and then has increased at a rate of 0.6% per year since then. Which function represents the town's population t years after 1990?

Answers

Answer:

f(t)=89,443(1.006^t)

Step-by-step explanation:

In this problem we have a exponential function of the form

f(t)=a(b^t)

where

f(t) is the population of a town

t  is the number of years since 1990

a is the initial value

b is the base

r is the rate

b=(1+r)

we have

a=89,443\ people\nr=0.6\%=0.6/100=0.006

b=1+0.006=1.006

substitute

f(t)=89,443(1.006^t)

The debate team is showing a video of their recent debate. The first showing begins at 3:15 p.m. The second showing starts at 4:50 p.m with a 1/2 break between the showings. The second showing started 20 minutes late. Will the second showing be over by 6:30 p.m? EXPLAIN you answer.

Answers

Given:
3:15 pm - start of first showing.
30 minutes break;
20 minutes late - 2nd showing.
4:50 - start of second showing.

4:50 - 0:20 = 4:30 should be the start of the second showing.
4:00 - 4:30 = 1/2 hour break
3:15 - 4:00 = duration of the 1st showing. 45 minutes in all.

4:50 + 0:45 = 5:35 pm end of the 2nd showing.

Yes, the 2nd showing will be over by 6:30 pm. 

Answer:

Given:

3:15 pm - start of first showing.

30 minutes break;

20 minutes late - 2nd showing.

4:50 - start of second showing.

4:50 - 0:20 = 4:30 should be the start of the second showing.

4:00 - 4:30 = 1/2 hour break

3:15 - 4:00 = duration of the 1st showing. 45 minutes in all.

4:50 + 0:45 = 5:35 pm end of the 2nd showing.

Yes, the 2nd showing will be over by 6:30 pm.  

Step-by-step explanation: