A and B are two events. P(A)=0.5 , P(B)=0.4 and P(A and B)=0.3 . What is the value of P(A or B) ?

Answers

Answer 1
Answer:

Answer:  The required value of P(A\cup B). is 0.6.

Step-by-step explanation:  Given that A and B are two events such that

P(A)=0.5,~~P(B)=0.4,~~P(A\cap B)=0.3.

We are to find the value of P(A\cup B).

From the laws of probability, we have

P(A\cup B)=P(A)+P(B)-P(A\cap B)=0.5+0.4-0.3=0.9-0.3=0.6.

Thus, the required value of P(A\cup B). is 0.6.

Answer 2
Answer:

Answer: 0.6

Work Shown:

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 0.5 + 0.4 - 0.3

P(A or B) = 0.9 - 0.3

P(A or B) = 0.6


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Determine the discriminant for the quadratic equation 0 = –2x2 + 3. Based on the discriminant value, how many real number solutions does the equation have?Discriminant = b2 – 4ac

Answers

Answer:

There are two real, distinct roots to the quadratic equation .

Step-by-step explanation:

Given  : -2x² + 3 = 0.

To find : Determine the discriminant  and how many real number solutions does the equation have.

Solution : We have given  -2x² + 3 = 0.

On comparing ax²+bx +c = 0

Discriminant = b² - 4ac

Where b = -2 , c = 3

Plugging the values

D = ( -2)² - 4 ( -2) ( 3) .

D = 4 + 24 .

D = 28 > 0

If the discriminant is greater than zero, this means that the quadratic equation has two real, distinct (different) roots.

Therefore, There are two real, distinct roots to the quadratic equation .

Hello,

Δ=0-4*(-2)*3=24

2 real solutions

Helllllp >_< Compare: 1.2057 O 1.1421OA) >
OB) <
OC)
=
OD) none of the above

Answers

The decimal number 1.2057 is greater than the decimal number 1.1421. Then the correct option is A.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

The decimal numbers are given below.

1.2057 and 1.1421

Compare the decimal numbers, then we have

1.2057 > 1.1421

The decimal number 1.2057 is greater than the decimal number 1.1421. Then the correct option is A.

More about the Algebra link is given below.

brainly.com/question/953809

#SPJ2

Answer:

Widal Kit Salmonella Ha, Hb, Hc, Hd, OA, OB, OC, OD

Rapid Labs Widal antigen set contains ready to use concentrated smooth antigen suspensions of the bacilli; S. typhi ‘O’. S. typhi ‘H’. S, paratyphi ‘AO’. S. paratyphi ’BO‘. S. paratyphi ’AH’, S. paratyphi ‘BH’. S. paratyphi ‘CH’. S. paratyphi ‘CO’ and/or polyspecific positive control reactive with these antigens.

When the Widal antigen suspensions are mixed and incubated with the patient’s serum, anti salmonella antibodies present in the patient serum react with the antigen suspensions to give agglutination. Agglutination is a positive test result, indicating presence of anti-salmonella antibodies in the patient serum. No agglutination is a negative test result indicating absence of anti-salmonella antibodies.

Pack size – 8 x 5ml

This kit does NOT contain positive and negative controls

Widal Kit Salmonella Ha, Hb, Hc, Hd, OA, OB, OC, OD

Rapid Labs Widal antigen set contains ready to use concentrated smooth antigen suspensions of the bacilli; S. typhi ‘O’. S. typhi ‘H’. S, paratyphi ‘AO’. S. paratyphi ’BO‘. S. paratyphi ’AH’, S. paratyphi ‘BH’. S. paratyphi ‘CH’. S. paratyphi ‘CO’ and/or polyspecific positive control reactive with these antigens.

When the Widal antigen suspensions are mixed and incubated with the patient’s serum, anti salmonella antibodies present in the patient serum react with the antigen suspensions to give agglutination. Agglutination is a positive test result, indicating presence of anti-salmonella antibodies in the patient serum. No agglutination is a negative test result indicating absence of anti-salmonella antibodies.

Pack size – 8 x 5ml

This kit does NOT contain positive and negative control

Step-by-step explanation:

If f(x) = 0, what is x?0 only
–6 only
–2, 1, or 3 only
–6, –2, 1, or 3 only

Answers

Answer:

answer will be 0

plz mark me as brainliest

Cedric and doug each had an equal amount of money. After cedric spent $35 and doug spent $28, the ratio of cedrics money to dougs money was 2:3. How much money did each boy habe at first?

Answers

Answer:

Each of them had $49 at first.

Step-by-step explanation:

Given:

Cedric and Doug each had an equal amount of money.

Let the number of money they had at first be x

Cedric spent = $35

Doug spent = $28

Cedric Money left = x-35

Doug Money left = x-28

the ratio of Cedric money to Doug money was 2:3

Hence the expression can be made as;

(x-35)/(x-28)=(2)/(3)

Now by cross multiplication method we get;

3(x-35)=2(x-28)

Now we will use distributive property to elaborate the same;

3x-105=2x-56

Combining common terms we get;

3x-2x=105-56

Using Subtraction property we get;

x= 49

Hence $49 they each had at first.

Barry brought 17.50 meters of a light rope at $0.48 per meter and three meters of heavy rope at $1.08 per meter. How much change did he get back from three $5 bills?

Answers

Barry will get back $3.36.

The line passes through the points (x1, y1) and (x2, y2). The slope of the line is: a) x2−x1y2−y1​ b) y2−y1x2−x1​ c) x1−x2y1−y2​ d) y1−y2x1−x2​

Answers

Answer:

b

Step-by-step explanation:

the slope m of a line passing through (x₁, y₁ ) and (x₂, y₂ ) is

m = \frac{y_{2-y_(1) } }{x_(2)-x_(1) }slope formula