Find the distance between points (3, 5) and (4, 6) to the nearest tenth.A) 3.2
B) 2
C) 2.8
D) 1.4

Answers

Answer 1
Answer:

The distance between the two points is 1.4.

Option D is the correct answer.

What is the distance between two points of a line?

The distance between two points of a line is given as:

Distance =  √(c - a)² + (d - b)²

We have,

To find the distance between the two points (3, 5) and (4, 6)

We can use the distance formula:

d = √((x₂ - x₁)² + (y₂ - y₁)²)

where (x₁, y₁) and (x₂, y₂) are the coordinates of the two points.

Substituting the given values, we get:

d = √((4 - 3)² + (6 - 5)²)

d = √(1² + 1²)

d = √2

To the nearest tenth, the distance is approximately 1.4.

Therefore,

The distance between the two points is 1.4.

Learn more about the distance of a line here:

brainly.com/question/14645718

#SPJ3

Answer 2
Answer:

The formula of a distance between two points:

d=√((x_2-x_1)^2+(y_2-y_1)^2)

We have the points (3, 5) and (4, 6). Substitute:

d=√((4-3)^2+(6-5)^2)=√(1^2+1^2)=√(1+1)=\sqrt2\approx1.4

Answer: D) 1.4


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An element with Mass 630 grams decays by 18.8% per minute. How much of the element is remaining after 7 minutes, to the nearest 10th of a gram?

Answers

Answer:

146.6 grams

Step-by-step explanation:

We have been given an element with Mass 630 grams decays by 18.8% per minute.

We will use exponential decay function to solve our given problem.

y=a\cdot (1-r)^x, where,

y = Final amount,

a = Initial amount,

r = Rate of decay in decimal form,

x = Time.

18.8\%=(18.8)/(100)=0.188

Substitute the given values:

y=630\cdot (1-0.188)^7

y=630\cdot (0.812)^7

y=630\cdot 0.232751347

y=146.633349

y\approx 146.6

Therefore, 146.6 grams of the element is remaining after 7 minutes.


630 * {81.2}^(7)
1.5

Given f(x)=(x+5)(x-2), what are the x-intercepts?

Answers

Answer:

The intercepts are -5 and 2

Step-by-step explanation:

Using the zero product property

f(x)=(x+5)(x-2)

0 =(x+5)(x-2)

0 = (x+5)   0=(x-2)

x = -5            x = 2

The intercepts are -5 and 2

What goes into 24 and 2,500

Answers

The following numbers go into 24 and 2,500:
2, 4
Hope that helps!!

Answer:

The following numbers go into 24 and 2,500:

2, 4

Help me please help me please

Answers

The orange triangle's area is 30 because 1/2 times 6 times 10 is 30.The blue triangle's area is 30 because the right side is 6 for base because the orange triangle base is 6 and it aglines with the blue one so the right side blue triangle base is 6 times 10 times 1/2 equals 30 and the 2 left over for base of blue triangle's left side times 10 is 20  times 1/2 equals 10 so 10 plus 30 plus 30 equals 60 so your answer is 60.

kelsey made 2 pitchers of lemonade each pitcher holds 6 cups she poured 4 cups of lemonade from one pitcher what fraction of the lemonade is left?

Answers

well, easy . all u need 2 do is add one pitcher (6/6) with the remains of the other pitcher (2/6) = 8/6 which turns into 1 and 2/6 which is 1 and 1/3 

Please help!Which point is collinear with points B and C?



A.
(0, 0)

B.
(1, 1)

C.
(1, –5)

D.
(6, –8)

Answers

Answer:  Option 'A' is correct.

Step-by-step explanation:

Since we have given that

Coordinates of B = (4,-3)

Coordinates of C = (-4,3)

We need to find the collinear  point with B and C.

There is one method to find the collinear point i.e. Slope method.

Slope of BX = Slope of CX =  (y_2-y_1)/(x_2-x_1)

Let Coordinates of X = (0,0)

So, Slope of BX is given by

(0+3)/(0-4)=(3)/(-4)

Slope of CX is given by

(0-3)/(0+4)=(-3)/(4)

So, Slope of BX = Slope of CX = (-3)/(4)

And we can see from the graph (0,0) is the collinear point with B and C too.

Hence, Option 'A' is correct.

Points are collinear if they lie on the same line.

First find the equation of the line that passes through the points B and C.
B(4, -3) \nx_1=4 \n y_1=-3 \n \nC(-4,3) \nx_2=-4 \n y_2=3 \n \nm=(y_2-y_1)/(x_2-x_1)=(3-(-3))/(-4-4)=(3+3)/(-8)=(6)/(-8)=-(3)/(4) \n \ny=-(3)/(4)x+b \n(-4,3) \n3=-(3)/(4) * (-4)+b \n3=3+b \nb=0 \n \ny=-(3)/(4)x

The points lie on the line y=(-3/4)x.
Now plug the coordinates of the given points into the equation and check if they satisfy the equation.

(0,0) \nx=0 \n y=0 \n \Downarrow \n0 \stackrel{?}{=} -(3)/(4) * 0 \n0 \stackrel{?}{=} 0 \n0=0 \n\hbox{the point lies on the line} \n \n(1,1) \nx=1 \n y=1 \n \Downarrow \n1 \stackrel{?}{=} -(3)/(4) * 1 \n1 \stackrel{?}{=} -(3)/(4) \n1 \not= -(3)/(4) \n\hbox{the point doesn't lie on the line}

(1,-5) \nx=1 \n y=-5 \n \Downarrow \n -5 \stackrel{?}{=} -(3)/(4) * 1 \n-5 \stackrel{?}{=} -(3)/(4) \n-5 \not= -(3)/(4) \n\hbox{the point doesn't lie on the line} \n \n(6,-8) \nx=6 \n y=-8 \n \Downarrow \n-8 \stackrel{?}{=} -(3)/(4) * 6 \n-8 \stackrel{?}{=} -(9)/(2) \n-8 \not= -(9)/(2) \n\hbox{the point doesn't lie on the line}

The answer is A.