Can someone plz help me. How can you find the inequalities of 11/15 and 5/7. Next 5/9 and 7/13. Next 11/15 and 5/7. Lastly 5/9 and 7/13. PLZ HELP.

Answers

Answer 1
Answer: To make this a little clearer, let's give the pairs of inequalities the same denominator:

Question 1: 
(11)/(15)(5)/(7)
First, apply the common denominator to the first fraction:
((11)/(15))7 \n (11)/(15) * (7)/(7) \n (11*7)/(15*7) \n (77)/(105)
Do the same for the second:15( (5)/(7)) \n (5)/(7)* (15)/(15) \n (5*15)/(7*15) \n (75)/(105)
Nest, compare the two fractions:
(77)/(105) \ \textgreater \ (75)/(105)
Therefore:
(11)/(15) > (5)/(7)

Question Two:

(5)/(9)(7)/(13)
Apply the common denominator to fraction one:
13( (5)/(9)) \n (5)/(9) * (13)/(13) \n (5*13)/(9*13) \n (65)/(117)
Fraction two:
9((7)/(13)) \n (7)/(13) * (9)/(9) \n (7*9)/(13*9) \n (63)/(117)
Evaluate:
(65)/(117) > <span>(63)/(117)
Therefore:
(5)/(9)> (7)/(13)

Hope this helps!

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Find and simplify an expression for the area of five rows of x squares with side lengths of x centimeters.

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Answers

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