A migrating bird flies 312 miles in 13 hours. How many miles does it fly in 5 ​hours?

Answers

Answer 1
Answer: the answer is 120 miles , because it is a proportion 

Related Questions

Roy's average balance checking account pays simple interest of 4.8% annually, and he made $2.25 in interest last month. What was Roy's average balance last month?
324 is the same as the sum of 144 and v
Find the mode for the data set. 8.3, 8.7, 4.5, 6.9, 3, 4.2, 11.7, 4 4 6.9 8.3 no mode
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Bill can hammer 20 nails in 6 minutes. Jeff can do the same job in only 5 minutes . How long will it take them to finish if Bill hammers the first 5 nails, then Jeff hammers for 3 minutes then Bill finishes the job?A. 4.6 minutes
B. 5.0 minutes
C. 5.4 minutes
D. 5.8 minutes
E. 6.0 minutes

Answers

Bill hammers 20 nails in 6 minutes.
==> It takes him 6/20 = 0.3 minutes to hammer one nail.
==> If the total job is 20 nails, then he does 1/6 of the job in 1 minute.

Jeff hammers 20 nails in 5 minutes.
==> It takes him 5/20 = 0.25 minutes to hammer one nail.
==> If the total job is 20 nails, then he does 1/5 of the job in 1 minute.

Notice that the question doesn't say what size job they're assigned.
I'll assume it's a 20-nail job.

First step: Bill hammers 5 nails.
At 0.3 minutes per nail, that takes Bill 5 x 0.3 = 1.5 minutes

Second step:  Jeff hammers for 3 minutes.
At 0.25 minute per nail, he adds 3/0.25 = 12 nails to Bill's 5, for a total of 17 so far.

Third step:  Bill finishes the job.
There are (20 - 17) = 3 nails left to go.
At 0.3 minutes per nail, this takes Bill 3 x 0.3 = 0.9 minutes.

First step . . . . .  1.5 minutes
Second step . . . 3    minutes
Third step . . . . . 0.9 minutes
Total . . . . . . . . .5.4minutes

Compare the mean and standard deviation of Set A and Set B.Set A: 7, 3, 4, 9, 2
Set B: 5, 8, 7, 6, 4

Answers

Set A: {7, 3, 4, 9, 2}
Finding the Mean of Set A: \bar{x} = (7 + 3 + 4 + 9 + 2)/(5)
                                            \bar{x} = (25)/(5)
                                            \bar{x} = 5

Finding the Standard of Set A: \sigma = \sqrt{\frac{(\bar{x} - x_(1))^(2) + (\bar{x} - x_(2))^(2) + (\bar{x} - x_(3))^(2) + (\bar{x} - x_(4))^(2) + (\bar{x} - x_(5))^(2)}{n}}
                                                  \sigma = \sqrt{((5 - 7)^(2) + (5 - 3)^(2) + (5 - 4)^(2) + (5 - 9)^(2) + (5 - 2)^(2))/(5)}
                                                  \sigma = \sqrt{((-2)^(2) + (2)^(2) + (1)^(2) + (-4)^(2) + (3)^(2))/(5)}
                                                  \sigma = \sqrt{(4 + 4 + 1 + 16 + 9)/(5)}
                                                  \sigma = \sqrt{(34)/(5)}
                                                  \sigma = √(6.8)
                                                  \sigma \approx 2.6

Finding the Mean of Set B: \bar{x} = (5 + 8 + 7 + 6 + 4)/(5)
                                            \bar{x} = (30)/(5)
                                            \bar{x} = 6

Finding the Standard Deviation of Set B: \sigma = \sqrt{\frac{(\bar{x} - x_(1))^(2) + (bar{x} - x_(2))^(2) + (\bar{x} - x_(3))^(2) + (\bar{x} - x_(4))^(2) + (\bar{x} - x_(5))}{n}}
                                                                 \sigma = \sqrt{((6 - 5)^(2) + (6 - 8)^(2) + (6 - 7)^(2) + (6 - 6)^(2) + (6 - 4)^(2))/(5)}
                                                                 \sigma = \sqrt{((1)^(2) + (-2)^(2) + (-1)^(2) + (0)^(2) + (2)^(2))/(5)}
                                                                 \sigma = \sqrt{(1 + 4 + 1 + 0 + 4)/(5)}
                                                                 \sigma = \sqrt{(10)/(2)}
                                                                 \sigma = √(5)
                                                                 \sigma \approx 2.236

The mean and standard deviation of Sets A and B are different.

Final answer:

Mean of Set A is 5 and Set B is 6. Standard deviation of Set A is approximately 2.83, and for Set B, it's approximately 1.67. This indicates that values in Set B are generally closer to their mean than values in Set A to their mean.

Explanation:

To compare the mean and standard deviation of Set A and Set B, we first need to calculate these for each set. Mean is the average of the numbers and standard deviation is a measure of the amount of variation or dispersion of a set of values.

First, calculate the mean by adding the numbers in each set and dividing by the total number of values. For Set A, the mean is (7+3+4+9+2)/5 = 5. For Set B, the mean is (5+8+7+6+4)/5 = 6.

The standard deviation is a bit more complex, as it involves subtracting the mean from each value, squaring the result, finding the mean of these squares, and then taking the square root of that mean. For Set A, these steps result in a standard deviation of approximately 2.83. For Set B, these steps result in a standard deviation of approximately 1.67.

In conclusion, Set B has a higher mean and a lower standard deviation compared to Set A which means values in Set B are generally closer to the mean of Set B than values in Set A are to the mean of Set A.

Learn more about Mean and Standard Deviation here:

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2x + 3y = 34x + 6y = 10
One Solution
Infinitely Many Solutions
No Solutions

Answers

No solution because in the end it says -4 = 0 which is not true

V = u + 10t
Work out the value of v when
u = 10 and t = 7

Answers

well, we have to plug in the values and then solve for v

v=10 + 10 times 7

by order or operations 10 times 7=70 plus 10 is 80

so  v=80

if u=10 and t=7

first: plug in the numbers (V=10+10(7))

second: use PEMDAS to solve

Third: 10+ 70=80

V=80

What is a rational number between the two given numbers?
8/13 and 7/10.

Answers

to find the rational number inbetween those 2 numbers you have to find the average, so 8/13 plus 7/10= 1.315384615384615, than divide that by 2 which equals 0.657692307692308 (0.658 rounded)

0.648 is the rational number inbetween 8/13 and 7/10

Solve:

3/5 − 6/11

A:3/55

B:3/6

C:3/11

Answers

The answer is: [A]:  3/55 .
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Explanation:
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(3/5) - (6/11) =  [(3*11) / (5*11) ] - [(6*5) / (11*5)] = (33/55) - (30/55) = 3/ 55.
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