What is the value of the expression below when c - 5 and d - 4 (c is to the second power)?6c2-5d+8

Answers

Answer 1
Answer: Well, let's write it out, shall we? 6c2-5d+8 Now plug in the numbers. 6(5^2)2-5(4)+8 Now simplify using PEMDAS Parentheses Exponents Multiplication Division Addition and Subtraction (They go together go from left to right in the equation) 5^2= 5*5 = 25 6 * 25 = 150 150 * 2 = 300 5 * 4 = 20 Rewrite the equation. 150-20+8 Use PEMDAS again ( refer to the previous mentioning) 150 - 20 = 130 130 + 8 = 138

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Triangle ABC underwent a sequence of transformations to give triangle A′B′C′. Which transformations could not have taken place? A. a reflection across the line y = x followed by a reflection across the line y = -x B. a reflection across the x-axis followed by a reflection across the y-axis C. a rotation 180° clockwise about the origin followed by a reflection across the line y = x D. a reflection across the y-axis followed by a reflection across the x-axis

Answers

Answer:

C. a rotation 180° clockwise about the origin followed by a reflection across the line y = x

Step-by-step explanation:

Let us assume that the coordinate of A in triangle ABC is A(x, y)

A) If there is a reflection across line y = x, the new coordinate is at A'(y, x).

If a reflection across the line y = -x is then followed, the new coordinate is at A"(-x, -y)

B) If there is a reflection across line x axis, the new coordinate is at A'(x, -y).

If a reflection across the line y axis is then done, the new coordinate is at

A"(-x, -y)

C) If there is a rotation 180° clockwise about the origin, the new coordinate is at A'(-x, -y).

If a reflection across the line y = x is then followed, the new coordinate is at A"(-y, -x)

D) B) If there is a reflection across line y axis, the new coordinate is at A'(-x, y).

If a reflection across the line x axis is then done, the new coordinate is at

A"(-x, -y)

Since only option C has a different result from the remaining options, hence option C would not five triangle A'B'C'

Answer:

C. a rotation 180° clockwise about the origin followed by a reflection across the line y = x

Step-by-step explanation:

Let us assume that the coordinate of A in triangle ABC is A(x, y)

A) If there is a reflection across line y = x, the new coordinate is at A'(y, x).

If a reflection across the line y = -x is then followed, the new coordinate is at A"(-x, -y)

B) If there is a reflection across line x axis, the new coordinate is at A'(x, -y).

If a reflection across the line y axis is then done, the new coordinate is at

A"(-x, -y)

C) If there is a rotation 180° clockwise about the origin, the new coordinate is at A'(-x, -y).

If a reflection across the line y = x is then followed, the new coordinate is at A"(-y, -x)

D) B) If there is a reflection across line y axis, the new coordinate is at A'(-x, y).

If a reflection across the line x axis is then done, the new coordinate is at

A"(-x, -y)

Since only option C has a different result from the remaining options, hence option C would not five triangle A'B'C'

Consider the following system of equations.y = 6x - 6

y - 6x = 5

What can you conclude about the system of equations?

Answers

y = 6x - 6  therefore   y - 6x = -6
y - 6x = 5 
so:
-6 ≠ 5
There is no solution to this system.
==========================
\left \{ {{y=6x-6} \atop {y-6x=5}} \right.  \n  \left \{ {{6x-y=6} \atop {-6x+y=5 }} \right.  \n 0 \neq 11

Write the expression as the sine, cosine, or tangent of an angle.
sin 9x cos x - cos 9x sin x

Answers

Answer:

\sin (9x)\cos (x) - \cos 9(x) \sin (x)=\sin (8x)      

Step-by-step explanation:

Given : Expression \sin (9x)\cos (x) - \cos 9(x) \sin (x)

To find : Write the expression as the sine, cosine, or tangent of an angle?

Solution :

We know the trigonometry property of additional,

\sin A\cos B-\cos A\sin B=\sin (A-B)

On comparing the expression with property,

A=9x and B=x

Substitute in formula,

\sin (9x)\cos (x) - \cos 9(x) \sin (x)=\sin (9x-x)

\sin (9x)\cos (x) - \cos 9(x) \sin (x)=\sin (8x)

Therefore, The expression is written as the sine of an angle

\sin (9x)\cos (x) - \cos 9(x) \sin (x)=\sin (8x)

from sin(a-b) = sin(a)cos(b) - cos(a)sin(b)
let a=9x, b=x
sin(9x)cos(x) - cos(9x)sin(x) = sin(9x-x) = sin(8x)

One question is all I need help on.

Answers

Hello,

y=x²+2x
y=3x+20

==>x²+2x=3x+20
==>x²+2x-3x-20=0
==>x²-x-20=0
==>x²-2*1/2*x+1/4-20-1/4=0
==>(x-1/2)²-81/4=0
==>(x-1/2-9/2)(x-1/2+9/2)=0
==>(x-5)(x+4)=0
==>(x=5 and y= 35 ) or (x=-4 and y=-8)


-9y-6+7y=16
What is the answer for this?

Answers

-9y - 6 + 7y = 16
-9y + 7y - 6 = 16
        -2y - 6 = 16
             + 6   + 6
             -2y = 22
              -2     -2
                 y = -11

Please help me!!!!!!!

Answers

Answer:

a? ya- no (jk its c) :)

Step-by-step explanation:

uh there the same degree to find the others find out from 180