___________________ is the type of exercise you are doing. Are you running, swimming, or walking?A. Time
B. Type

Answers

Answer 1

Answer:

time. is the answer.

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What does it mean when the line on a graph of a distance vs. time changes direction?

Answers

The slope of the line ... or the direction it's heading ... is the speed
of whatever is being graphed. So if the line changes direction, it
means that the speed changed at that time.

what happens to the period of revolution for the planets as they move farther away in position from the sun

Answers

It increases. Mercury takes 88 days to orbit the sun once. The Earth takes a year. Pluto takes 248 years.

If the wavelength of a wave increases does its frequency also increase?

Answers

Frequency decreases whilst wavelength increases and the opposite also occurs

Bruce (the dog) is pulling on his lead with a force of 40N at an angle of 26º below the horizontal. Show that the horizontal component of this force is about 36N.Help???

Answers

Answer:

The horizontal component of this force is about 36 N.

Explanation:

Given that,

Bruce is is pulling on his lead with a force of 40 N

Angle below horizontal, $\theta=26^(\circ)$

We need to find the horizontal component of this force. The horizontal component of any vector is given by :

$F_x=F\ \cos\theta$

$F_x=40* \ \cos(26)$

$F_x=35.95\ N$

$F_x=36\ N$

So, the horizontal component of this force is about 36 N. Hence, this is the required solution.

you will use the equation for work which is w= F times distance so you will take 40N times 36N which equals 1440N

Which chart correctly describes the properties of magnets and electromagnets?

Answers

I'm gonna take a long shot here and say C. This is just based on common sense, sense electromagnets happen when electricity goes around a copper coil, as far as I know.

An artificial satellite circling the Earth completes each orbit in 129 min(a) Find the altitude of the satellite.

(b) What is the value of g at the location of this satellite?

Answers

(a) $2.09\cdot 10^6 m$ above Earth's surface

The orbital speed of a satellite orbiting the Earth can be found using the equation

$v=\sqrt{(GM)/(r)}$

where

G is the gravitational constant

$M=5.98\cdot 10^(24) kg$ is the Earth's mass

r is the radius of the satellite's orbit

The orbital speed can also be rewritten as the ratio between the circumference of the orbit and the orbital period, T:

$(2\pi r)/(T)$

where

T = 129 min = 7740 s is the period

Combining the two equations,

$(2\pi r)/(T)=\sqrt{(GM)/(r)}$

And solving for r,

$((2\pi)^2 r^2)/(T^2)=(GM)/(r)\nr=\sqrt[3]{(GMT^2)/((2\pi)^2)}=\sqrt[3]{((6.67\cdot 10^(-11))(5.98\cdot 10^(24))(7740)^2)/((2\pi)^2)}=8.46\cdot 10^6 m$

This is, however, the orbital radius: this means we have to subtract the Earth's radius to find the altitude of the satellite, which is

$R=6.37\cdot 10^6 m$

therefore, the altitude of the satellite is

$h=r-R=8.46\cdot 10^6 - 6.37\cdot 10^6 =2.09\cdot 10^6 m$

b) $5.57 m/s^2$

The value of g at the location of the satellite is given by

$g=(GM)/(r^2)$

where:

G is the gravitational constant

$M=5.98\cdot 10^(24) kg$ is the Earth's mass

$r=8.46 \cdot 10^6 m$ is the radius of the satellite's orbit

Substituting into the equation, we find

$g=((6.67\cdot 10^(-11))(5.98\cdot 10^(24)))/((8.46\cdot 10^6)^2)=5.57 m/s^2$

Final answer:

The satellite orbits at an altitude of approximately 800 km. The gravitational constant, 'g', at this location is approximately 8.66 m/s^2.

Explanation:

The orbital period of an artificial satellite can be used to calculate the altitude at which it orbits. For a satellite that completes each orbit in 129 min (or approximately 2.15 hr), we can apply Kepler's third law which states that the square of the period of a satellite is proportional to the cube of its semi-major axis (distance from the center of the Earth to the satellite).

The formula for the altitude is given by: h = [(GMT^2)/(4π^2)]^(1/3) - R, where G is the gravitational constant, M the mass of Earth, T the orbital period, and R the Earth's radius. With the values G=6.67 x 10^-11 N(m/kg)^2, M=5.98 x 10^24 kg, T=2.15 hr = 7740s, and R=6.371 x 10^6 m, we get h approximately equals 800 km.

The value of 'g' at the satellite's location is given by g = GM/(R+h)^2. Substituting the aforementioned values, we get g to be approximately 8.66 m/s^2. This is less than the 9.81 m/s^2 at Earth's surface due to the increased distance from the Earth's center.