Given the position function, s of t equals t cubed divided by 3 minus 12 times t squared divided by 2 plus 36 times t , between t = 0 and t = 15, where s is given in feet and t is measured in seconds, find the interval in seconds where the particle is moving to the right. (5 points)0 < t < 6


5 < t < 15


t > 15


The particle always moves to the right.

Answers

Answer 1
Answer:

Answer:

Option D is correct.

as the particle always moves to the right

Step-by-step explanation:

Given the function:  s(t) = (t^3)/(3) - (12t^2)/(2) + 36t , 0<t<15;

where

s(t) represent the distance in feet.

t represents the time in second.

Since, when the particle is moving to the right,

⇒ s(t) is increasing.

so, v(t) =(ds)/(dt) > 0

Find the derivative of s(t) with respect to t;

Use derivative formula:

(dx^n)/(dx) = nx^(n-1)

(ds)/(dt) = (3t^2)/(3)-(24t)/(2)+36

Simplify:

(ds)/(dt) = t^2-12t+36

As (ds)/(dt) > 0

t^2-12t+36 > 0

(t-6)^2 >0               [(a-b)^2 = a^2-2ab+b^2 ]

⇒ this is always true because square of any number is always positive

Therefore, it means that the particle always moves to the right.


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Let's write the whole numbers from 90 to 100 . Select the appropriate number to form the following sets . Then , write the type of sets .A={ even number}
B={ odd number}
C={ X:X is a prime numbers}
D={ y:y is a composite number}
E={z:z is a square number}
F={ cube number}
G={ multiples of 7}
H={ X:X is divisible by 11}​

Answers

Answer:

A

The even numbers between 90 and 100 are: 90, 92, 94, 96, 98, 100

B

The odd numbers between 90 and 100 are: 91, 93, 95, 97, 99

C

The prime number between 90 and 100 is: 97

D

The composite numbers between 90 and 100 are: 91, 92, 93, 94, 95, 96, 98 and 99.

E

The square numbers between 90 and 100 are:

90 = 8100

91 = 8281

92 = 8464

93 = 8649

94 = 8836

95 = 9025

96 = 9216

97 = 9409

98 = 9604

99 = 9801

100 = 10000

F

The answer for this is on the attached picture above. Kindly look at it. The cube numbers between 90 and 100.

G

The multiples of 7 between 90 and 100 are: 91 and 98

H

Divisible by 11 (between 90 and 100) is: 99

A={ even number}

B={ odd number}

C={ X:X is a prime numbers}

D={ y:y is a composite number}

E={z:z is a square number}

F={ cube number}

G={ multiples of 7}

H={ X:X is divisible by 11}

꧁Aɴsᴡᴇʀ꧂

A

  • The even numbers between 90 and 100 are: 90, 92, 94, 96, 98, 100

B

  • The odd numbers between 90 and 100 are: 91, 93, 95, 97, 99

C

  • The prime number between 90 and 100 is: 97

D

  • The composite numbers between 90 and 100 are: 91, 92, 93, 94, 95, 96, 98 and 99.

E

  • The square numbers between 90 and 100 are:

90 = 8100

91 = 8281

92 = 8464

93 = 8649

94 = 8836

95 = 9025

96 = 9216

97 = 9409

98 = 9604

99 = 9801

100 = 10000

F

  • The answer for this is on the attached picture above. Kindly look at it. The cube numbers between 90 and 100.

G

  • The multiples of 7 between 90 and 100 are: 91 and 98

H

  • Divisible by 11 (between 90 and 100) is: 99

ʰʰˡˢ

Y=6x
Y=5x+7
How do you solve this

Answers

subsitute 6x for y since they are equal
6x=5x+7
subtract 5x form both sides
6x-5x=5x-5x+7
x(6-5)=x(5-5)+7
x(1)=x(0)+7
x=0+7

x=7
subsitute 7 for x
6(7)=y
42=y

x=7
y=42 the answer to the universe


the answer to your question is 0.14 recurring

to solve this problem you must first learn about indices when u have a number with x in the back of it you must times the number by how much it is and when u have a next alphabet across of the equal sign it is always 1 and if u divide 6 into 1 you will get 0.14 recurring 

Consider the expression –3(y – 5)2 – 9 + 7y.Which statements are true about the process and simplified product? Check all that apply.

A=The first step in simplifying is to distribute the –3 throughout the parentheses.
B=There are 3 terms in the simplified product.
C=The simplified product is a degree 3 polynomial.
D=The final simplified product is –3y2 + 7y – 9.
E=The final simplified product is –3y2 + 37y – 84.

Answers

Answer: Option 'B' and 'E' are correct.

Step-by-step explanation:

Since we have given that

-3(y-y)^2-9+7y

Simplification needs a few steps:

-3(y-5)^2-9+7y\n=-3(y^2+25-10y)-9+7y\n=-3y^2-75+30y-9+7y\n=-3y^2+37y-84

So, Option 'B' and 'E' are correct.

As Option 'B' says there are 3 terms in the simplified product, which is true.

Answer:

B and E

Step-by-step explanation:

What is the area of the composite figure?4 in
O (877 + 6) in.2
(817 + 12) in 2
(877 + 18) in 2
(81T + 24) in 2
3 in

Answers

Answer:

8π + 12 in²

Step-by-step explanation:

Just add the areas of the semicircle and the triangle.

Solve for x. 3x/4+ 3 = 27 x = 32 x = 40 x = 42 x = 47.5

Answers

Hey there, first, we simplify, 3/4x+3=27, second, subtract 3 from both sides, 3/4x+3-3=27-3=3/4x=24, third, multiply both sides by 4/3, 4/3*3/4x=4/3*24=32. Therefore, x=32

Ellie, the elephant eats 4 times as much as popcorn the pony, zac the zebra eats twice as much as popcorn altogether they eat 238 kilograms of food per week how much foos does each of them require per week

Answers

Answer=Elephant:34kg  Pony:136kg  Zebra:68kg

elephant:pony:zebra
1:4:2
1+4+2=7
238/7=34
1*34=34kilograms (elephant)
4*34=136kilograms (pony)
2*34=68kilograms (zebra)

Elephant=34kg
Pony=136kg
Zebra=68kg