Well, for the first one, you count all the values that fit into the certain range. For example if I were to try and find the first one (10-19) I would count up all the numbers from 10 to 19. There are 4 (17, 10, 16, 19). Okay, for the second one (20-29). There are 6 (22, 20, 22, 20, 24, 20). On to the third (30-39). There are 5 (37, 34, 32, 33, 34). Now for the fourth one (40-49). There are 4 (49, 48, 40, 46) Now for the fifth one (50-59). There are 4 (56, 50, 51, 58). Now for the sixth (last) one. There are 2 (61, 60). With this info, the answer is the first choice.
I honestly do not remember ever doing box-and-whisker plots, so I cannot help you there. Sorry.
Cannot help with questions 12 and 13 or 15 either, I have never seen this.
Now, for number 16, you would just divide 900 by 15 and you would get 60. So, she would have to mow 60 lawns.
A proportion is a set of numbers that are equal to each other. The only choice is 5/1000 and 10/2000. You can multiply 5/1000 by 2 and get 10/2000, or you can divide 10/2000 to get 5/1000.
Sorry I couldn't answer some of your questions, but I hope this helps! Sorry again.
The quantity of distance measures in miles depends on the quantity of time measures in hours
The quantity of time measured in minutes depends on the quantity of speed measured in feet
The quantity of speed measured in feet depends on the quantity of time measured in minutes
Step-by-step explanation:
Angles in the same segment. The angles at the circumference subtended by the same arc are equal. More simply, angles in the same segment are equal.
Picture 1 a° = a° they are the same
Picture 2 p= 52° q= 40° Angles in the same segment are equal. if they ask you to calculate you just show both angles p= 52 and q=40.
Picture 3 + 4 Let the obtuse angle MOQ = 2x.
Using the circle theorem, the angle at the centre is twice the angle at the circumference.
Therefore picture 4 tells us and proves;
Angle MNQ = x and angle MPQ = x.
Picture 5
A cyclic quadrilateral is a quadrilateral drawn inside a circle. Every corner of the quadrilateral must touch the circumference of the circle.
The second shape is not a cyclic quadrilateral. One corner does not touch the circumference.
Picture 6
The opposite angles in a cyclic quadrilateral add up to 180°.
a + c = 180°
b + d = 180°
Picture 7
Example
Calculate the angles a and b.
The opposite angles in a cyclic quadrilateral add up to 180°.
This is a picture that couldn't be added but has a quadrilateral occupying half the triangle consisting of 3 arcs the middle one was 140 and proved part of one triangle. The x (a) missing angle showed below a = 180-60 = 120 °
So hopefully this will help you remember the format here for quadrilateral shapes within a circle.
b = 180 - 140 = 40°
a = 180 - 60 = 120°
y 6 15 ?