A circle has an area of 75 square centimeters. Which answer is closest to the measure of its radius?

Answers

Answer 1
Answer: The formula of the area of a circle is
A = \pi

75 cm² = \pi
Divide by \pi on either sides to isolate r

(75)/( \pi )( \pi r^2)/( \pi )
\pi and \pi cancels out

23.89 = r²
Take square roots to cancel power of two
√(23.89)√(r^2)
4.89 cm ≈ r
I dont know if the question had any options, but this is how we do it.

Answer 2
Answer:

Answer:

4.9 for short


Step-by-step explanation:



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A circle is defined by the equation x2 + y2 + 8x + 22y + 37 = 0. What are the coordinates for the center of the circle and the length of the radius?
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The accompanying frequency table indicates the grades on the math midterm in Ms.Dennis' class. In which interval does the median of the date lie?

                                                               Frequency Table

             Interval                                              Tally                                           Frequency

96-100                                                                  V                                                    5

91-95                                                                    I                                                     1

86-90                                                                    VIIII                                                9

81-85                                                                    IIII                                                  4

76-80                                                                    II                                                    2

71-75                                                                    IIII                                                  4

Answers

The median falls in the interval 86-90

Choose the correct simplification of the expression a to the 7th power times b to the 8th power all over a to the 4th power times b to the 4th power

Answers

First you need to write the numerical equation for the given:

( a^(7) b^(8) )/( a^(4) b^(4) )

When you will simplify this fraction, you can divide the expressions. Based on the law of exponents when you divide like terms with different exponents, you can subtract the exponents of the denominator from the numerator. 

So if you will simplify the equation:

( a^(7) b^(8) )/( a^(4) b^(4) )

Subtract the following:

Exponents of a 7-4 and;
Exponents of b 8-4

Your answer should be 
a^(3) b^(4)

What is x for number 14.

Answers


It's a right triangle.  So

         (x²) + (10²)  =  (7+x)²

         x²  +  100  =  49 + x² + 14x

That may look ugly, but I'm pretty sure you can handle it from this point.

Wow !  I just noticed that you can subtract  x²  from each side
and not even have to mess with it again.

x^2(x+7)^2=x^2+10^2x^2+14x+49=x^2+10014x+49=10014x=51x=3.64

What's the answer for:
8u+8+8i=80

Answers

The solution for the equation (8u + 8 + 8i = 80) is (u = (72 - 8i)/(8))

Whats an equation for the parabola vertex(3,3) and focus (3,5) and steps please

Answers

find directix

reemember that the vertex is equal distance from the directex as from the focus
and the directex and focus are on oposite sides of theh vertex
we seee that the directix is to the left of the vertex and focus



equation is
4p(x-h)=(y-k)^2 since the parabola opesn sideways
p is positive
p=distance from vertex to focus
distance is 2 since 3 to 5 is 2

8(x-h)=(y-k)^2
(h,k) is center
(3,3) is center

8(x-3)=(y-3)^2 is the equation
ifyo wanted it in terms of y then
square root both sides thena dd 3
√(8(x-3)) +3=y
remember that √(x) =x^{ (1)/(2)}
y=8(x-3)^{ (1)/(2) }+3


Two landscapers must mow a rectangular lawn that measures 100 feet by 200 feet. Each wants to mow no more than half of the lawn. The first starts by mowing around the outside of the lawn. How wide a strip must the first landscaper mow on each of the four sides in order to mow no more than half of the lawn? The mower has a 24-inch cut. Approximate the required number of trips around the lawn.

Answers


The total area of the complete lawn is (100-ft x 200-ft) = 20,000 ft².
One half of the lawn is  10,000 ft².  That's the limit that the first man
must be careful not to exceed, lest he blindly mow a couple of blades
more than his partner does, and become the laughing stock of the whole
company when the word gets around.  10,000 ft² ... no mas !

When you think about it ... massage it and roll it around in your
mind's eye, and then soon give up and make yourself a sketch ...
you realize that if he starts along the length of the field, then with
a 2-ft cut, the lengths of the strips he cuts will line up like this:

First lap:
       (200 - 0) = 200
       (100 - 2) = 98
       (200 - 2) = 198
       (100 - 4) = 96    

Second lap:
       (200 - 4) = 196
       (100 - 6) = 94
       (200 - 6) = 194
       (100 - 8) = 92   

Third lap:
       (200 - 8) = 192
       (100 - 10) = 90
       (200 - 10) = 190
       (100 - 12) = 88 

These are the lengths of each strip.  They're 2-ft wide, so the area
of each one is (2 x the length). 

I expected to be able to see a pattern developing, but my brain cells
are too fatigued and I don't see it.  So I'll just keep going for another
lap, then add up all the areas and see how close he is:

Fourth lap:
       (200 - 12) = 188
       (100 - 14) = 86
       (200 - 14) = 186
       (100 - 16) = 84 

So far, after four laps around the yard, the 16 lengths add up to
2,272-ft, for a total area of 4,544-ft².  If I kept this up, I'd need to do
at least four more laps ... probably more, because they're getting smaller
all the time, so each lap contributes less area than the last one did.

Hey ! Maybe that's the key to the approximate pattern !

Each lap around the yard mows a 2-ft strip along the length ... twice ...
and a 2-ft strip along the width ... twice.  (Approximately.)  So the area
that gets mowed around each lap is (2-ft) x (the perimeter of the rectangle),
(approximately), and then the NEXT lap is a rectangle with 4-ft less length
and 4-ft less width.

So now we have rectangles measuring

         (200 x 100),  (196 x 96),  (192 x 92),  (188 x 88),  (184 x 84) ... etc.

and the areas of their rectangular strips are
           1200-ft², 1168-ft², 1136-ft², 1104-ft², 1072-ft² ... etc.

==> I see that the areas are decreasing by 32-ft² each lap.
       So the next few laps are 
               1040-ft², 1008-ft², 976-ft², 944-ft², 912-ft² ... etc. 

How much area do we have now:

             After 9 laps,    Area =   9,648-ft²
             After 10 laps,  Area = 10,560-ft².

And there you are ... Somewhere during the 10th lap, he'll need to
stop and call the company surveyor, to come out, measure up, walk
in front of the mower, and put down a yellow chalk-line exactly where
the total becomes 10,000-ft².   


There must still be an easier way to do it.  For now, however, I'll leave it
there, and go with my answer of:  During the 10th lap.