MATHEMATICS HIGH SCHOOL

What is the first step of the following division problem?(8x^3 – x^2 + 6x + 7) ÷ (2x – 1)

A. Divide 8x^3 by 2x.
B. Divide 2x by 8x^3.
C. Divide 6x by 2x.
D. Divide 2x by 6x.

Answers

Answer 1
Answer: c. divide 6x by 2x, because you have to put the same variables together.

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jenny`s mom says she has an hour before it's bedtime. Jenny's spends 3\5 of hour texting a friend and 3\8 of the remaining time brushing her teeth and putting on her pajamas. she spends the rest of the time reading her book. how long did jenny read?
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Solve the following equations.X^2 + 5x + 6 = 0 (Factorise) X^2 + 7x + 11 = 0 (Use the quadratic formula)

Graph this line using the slope and y-intercept:
y=–3x–3

Answers

Answer:

Check the attachment (image).

Step-by-step explanation:

The slope is -3, so you have to put a point on the y-intercept (where the line touches the y-axis), or -3. Then you have to put a point 3 down (so -6 on the y-axis), and 1 right (so 1 on the x-axis) since the slope is actually:
-3/1
...now you get a ruler and make a line running through those points (if on paper).

HURRY PLEASE!! :(
Find c(8) in the sequence given by c(n) = 20 – 17(n − 1)

Answers

20-17(8-1)
20-17(7)
20-119
Answer
-99

Find a quadratic model for the set of values: (-2, -20), (0, -4), (4,-20) Show your work

Answers

For this case, the quadratic function in its generic form is given by:

We must find the values of the coefficients.

For this, we evaluate the given points.

For (0, -4):

For (-2, -20):

For (4, -20):

Therefore, for the values of a and b we have the following system of equations:

Resolving graphically (see attached image) we have:

Then, the quadratic model is:

Answer:

a quadratic model for the set of values is:

y = -2x ^ 2 + 4x - 4
A quadratic function:
y=ax^2+bx+c

First, take the point (0,-4) and plug the values (x,y) into the equation:
-4=a * 0^2+b * 0 +c \n-4=c

So the equation is y=ax^2+bx-4.

Now plug the values of the other two points into the equation and set up a system of equation:
-20=a * (-2)^2+b * (-2)-4 \n-20=a * 4^2+b * 4-4 \n \n-20+4=4a-2b \n-20+4=16a+4b \n \n-16=4a-2b \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | / 2 \n-16=16a+4b \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |/ 4 \n \n-8=2a-b \n\underline{-4=4a+b} \n-12=6a \n(-12)/(6)=a \na=-2 \n \n-8=2a-b \n-8=2 * (-2)-b \n-8=-4-b \n-8+4=-b \n-4=-b \nb=4

The function is:
\boxed{y=-2x^2+4x-4}

A family has 8 girls and 4 boys. A total of 2 children must be chosen to speak on the behalf of the family at a local benefit. What is the probability that 1 girl and 1 boy will be chosen?A. 2/11
B. 1/6
C. 2/33
D. 16/33

Answers

Probability is all about multiplying fractions.

The first fraction is the probability of picking a girl.. so how many of the 12 total children are girls. (8/12)

The second fraction is the probability of picking a boy.. so how many of the 11 remaining children are boys. (4/11) 

8/12 X 4/11 = 8/33 -> this isn't even an option but I'm like 10000% this is the right answer.. 

I started off this answer feeling so confident lol. good luck.
D. 16/33

because there are 28 g/g pairs, 6 b/b pairs, and 32 g/b pairs. In total 66 pairs, and of those pairs 32/66 are 1 girl and 1 boy, reduced is 16/33.

Coach Kelly bought 32 L of water to the football game, and she divied the water equally between 8 coolers how many milliliters of water did coach Kelly put in each cooler

Answers

ANSWER

Find out the how many milliliters of water did coach Kelly put in each cooler.

To proof

let us assume that the water put in the each cooler be x.

As given

Coach Kelly bought 32 L of water

she divied the water equally between 8 coolers

1  litre = 1000 miilitre

x = (32* 1000)/(8)

solving the above

x = 4000 millitre

therefore 4000 milliliters of water did coach Kelly put in each cooler.

Hence proved

Which type of triangle is formed with the points A(1, 7), B(-2, 2), and C(4, 2) as its vertices?

Answers

We will have to use the distance formula in order to determine the lengths of each side of the triangle.

Distance formula: \sqrt{(x_(2) - x_(1))^(2) + (y_(2) - y_(1))^(2) }

Let's calculate AB first:
A (1, 7) and B (-2, 2)
A: x1 = 1 and y1 = 7
B: x2 = -2 and y2 = 2

so
\sqrt{(-2 - 1)^(2) + (2 - 7)^(2) }
\sqrt{(-3)^(2) + (-5)^(2) }
√(9 + 25 )
AB = √(34) or (rounded to the nearest tenth) ≈ 5.8

Now let's do BC:
B: x1 = -2 and y1 = 2
C: x2 = 4 and y2 = 2

So
\sqrt{(4 - -2)^(2) + (2 - 2)^(2) }
\sqrt{(6)^(2) + (0)^(2) }
BC = √(36 ) or 6

Now let's do CA
C: x1 = 4 and y1 = 2
A: x2 = 1 and y2 = 7

So
\sqrt{(1 - 4)^(2) + (7 - 2)^(2) }
\sqrt{(-3)^(2) + (5)^(2) }
√(9 + 25)
CA = √(34) or (rounded to the nearest tenth) ≈ 5.8

So let's recap:

AB ≈ 5.8
BC = 6
CA ≈ 5.8

So AB and AC are the same length while BC is .2 units longer which means this is an isosceles triangle.
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