Mikes cat weighs 12 Pounds 9 Ounces. How many ounces does Mikes cat weigh?

Answers

Answer 1

Answer: The cat will weigh 201 ounces since 12*16+9=201 ounces

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How many hours in 3 years

Answers

Answer:

26280 hours

Step-by-step explanation:

your welcome

Answer:

Step-by-step explanation:

26280 cause the calendar year is 3 and the hours are 26280

One cubic foot of sand weighs 100 pounds a square sandbox with 5 foot sides has half a foot of sand in it how many pounds of sand in the sandbox holding

Answers

about 250 lbs because its half a foot deep of sand then you split the sum of the measurement in half

PLEASE HELP
Applications of Spheres

Answers

1.) B and C
2.) 65416.67
3.) 18.0
4.) 208.4
5.) 3836

Can anybody help me that smarter than me

Answers

Answer:

Question 5: y = 6.69 ft

Question 6: z = 12.52 in

Step-by-step explanation:

Question 5

In the right triangle shown, with respect to the angle given, y is the side that is "opposite" and the known side (15) is the "hypotenuse".

Note: The side opposite of right angle is the hypotenuse

Which trigonometric ratio relates "opposite" and "hypotenuse"? It is "SINE".

Let's setup the ratio and solve for y:

$Sin(26.5)=(y)/(15)\ny=15*Sin(26.5)\ny=6.69$

So,

y = 6.69 feet

Question 6

With relation to the angle given, we have the "adjacent" side and the "hypotenuse".

Which trigonometric ratio relates "adjacent" with "hypotenuse"?

It is COSINE!

We can set up a ratio as the previous question and solve for z:

$Cos(37)=(10)/(z)\nz=(10)/(Cos(37))\nz=12.52$

So,

z = 12.52 inches

The area of a rectangle is 123 cm2. If the width is 3 cm, find the length. Let l represent the length of the rectangle.

Answers

Answer:

41 cm

Step-by-step explanation:

123/3

The formula for the area (A) of a rectangle is given by A = l * w, where l is the length and w is the width. We are asked to find the length and we are given the width (3 cm) and the area (123 cm2).

To find the length, we need to manipulate this formula to solve for l. So, divide both sides of the equation by w, this gives us: l = A / w.

We now substitute the given values into this equation:

l = 123 / 3

This simplifies to:

l = 41.0

So, the length of the rectangle is 41.0 cm.

The science fair judges will be science teachers and volunteers. Each judge will only have time to view 5 science fair projects. There are 133 science teachers. What is the fewest number of volunteers needed to have enough judges for all of the projects?

Answers

Answer: The fewest number of volunteers needed to have enough judges for all of the projects is 2.

Step-by-step explanation:

Number of science teachers = 133

Number of science fair projects viewed by each judge = 5

Let the number of judge be n

Since number of volunteers must be multiple of 5 .

According to question,

$5n=135+\text{number of volunteers}\n\n\text{ where, n is a natural number and number of volunteer must be integer}$

So, Possibility for number of volunteers must be 2 to make it divisible by 5.

$5n=133+2\n\n5n=135\n\nn=(135)/(5)\n\nn=27$

Hence, the fewest number of volunteers needed to have enough judges for all of the projects is 2.

the answer is twenty seven

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Equivalent fractions for 15/35