A wave travels at a speed of 34 cm/s. It’s wavelength is 18 cm. What is the period of the wave?0.75 s

1.2 s

0.66 s

0.53 s

Regions of compression and rarefaction help define _______.

Electromagnetic waves

Longitudinal waves, but not transverse waves

Transverse waves, but not longitudinal waves

All mechanical waves

Answers

Answer 1
Answer: 0.53 seconds
(Comment if you need calculations/explanation)

Longitudinal waves but not transverse waves

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Function and location of esophagus

The orbits of planets being elliptical was one the planetary laws developed by

Answers

The correct answer is Kepler



Final answer:

The concept that planets move in elliptical orbits was established by Johannes Kepler in his First Law of Planetary Motion. This significant idea disrupted the earlier belief of circular orbits and brought tremendous knowledge in our solar system understanding.

Explanation:

The fact that the orbits of planets are elliptical was part of the planetary laws developed by the renowned astronomer and mathematician Johannes Kepler. Damaging the former belief of circular orbits, Kepler, based on detailed and exhaustive astronomic observations, established his First Law of Planetary Motion which stated that planets move in elliptical orbits with the Sun at one of the two foci. This was a significant breakthrough in understanding our solar system and continues to be fundamental in physics and astronomy today.

Learn more about Kepler's Laws,

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A 1200 kg car starts from rest and travels 100m in a time of 10 seconds . A) what is the acceleration of the car? B) what force must have acted on the car during this time? C) what is the velocity of the car after 10 seconds? D) what work was done on the car? E) what minimum power did the engine produce?

Answers

Given:
Mass (m) = 1200 kg
Distance (s) = 100 m
Time (t) = 10 seconds
Now,
velocity (v) =  (distance)/(time)

                         = (100~ m)/(10~seconds)

                         = 10 m/s
Note that this one is the final velocity.
We also know that, 
initial velocity (u) = 0 m/s .......because the car starts from rest.
Now,
acceleration (a)= (change~in~velocity)/(time)

                               = (v-u)/(t)

                               = (10-0)/(10)

                               = 1 m/s²
Now,
Force (F) = mass (m) * acceleration (a)
                = 1200 kg * 1 m/s²
                = 1200 kg.m/s²
                = 1200 N
Now,
Work Done (W) = Force (F) * displacement (s) ....note that displacement is                                                                                                      same as distance.
                         = 1200 N * 100 m
                          = 120000 N.m
                          = 120000 J
Now,
Power (P) = (Work~done(W))/(time(t))

                 = (120000~J)/(10s)

                 = 12000 J/s
                 = 12000 watt
SO,
 A) The acceleration of the car is 1 m/s².
 B) 1200 Newton (N) force must have acted on the car.
 C) The velocity of the car after 10 seconds is 10 m/s.
 D) 120000 Joule (J) work was done on the car.
 E) The engine produced a minimum power of 12000 watt.

A demographic tool used to predict a population's future growth isChoose one answer.
a. a hairline growth curve.
b. demographic transition.
c. age structures.
d. maximum sustained growth.
e. population momentum

Answers

C. Age structure. Hope I helped :) 

What are the requirements for an inertial frame of reference?

Answers

As simply put as I believe is possible, it's the immediate space-time co-oridinate in which the observer is not in motion. All measurements by the observer are in relation to that 'place'

The amount of heat neededto raise 2.0 kg of a substance by 80 K is 33 kJ. What is the specific heat of
the substance?

Answers

Q = mcθ
 
Where Q = Amount of heat in J
             m = Mass of substance in kg
              θ  = Temperature rise in °C or K
              C = Specific heat capacity in J/kgK

From given data:
Q = 33 kJ = 33 000 J, m= 2.0 kg,   θ  = 80 K,   c = ?

33000 =  2 * c * 80
33000 = 160c
160c   = 33000
       c   =  33000/160 = 206.25

Therefore specific heat capacity is 206.25 J/kgK

If the activation energy for a given compound is found to be 103 kJ/mol, with a frequency factor of 4.0 × 1013 s-1, what is the rate constant for this reaction at 398 K?

Answers

Answer: The Rate constant is 1.209

Explanation:

in the attachment

Explanation:

Below is an attachment containing the solution.