The ordered pair (0,4) is a solution of what system?
Answers
(x,y) format
if x=0, y=4 soo
y=x+4 is one equation
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(04.01 LC) The vertices of a quadrilateral ABCD are A(1, -3), B(4, -3), C(4, -5), and D(-1, -5). The vertices of another quadrilateral EFCD are E(1, -7), F(4, -7), C(4, -5), and D(-1, -5). Which conclusion is true about the quadrilaterals? (5 points) The shape of the quadrilaterals is same but their areas are different. The ratio of their corresponding sides is not equal. The measures of the corresponding angles are different. The angles and sides overlap when one quadrilateral is placed on the other.
Answers
θ = tan^-1 (7/8) = 41.2 degrees
cos θ = 0.7526
Answer: see below
Step-by-step explanation:
Presuming you meant this
0< θ < 90 degree; tan (θ) = 7/8 find cos (θ)
Using the identity
1 + tan²θ = sec²θ (where sec θ = 1/cosθ)
cosθ = √{1/(1 + tan²θ)} = √{ 1/(1 + (7/8)²} = √{ 1/(1 + 49/64)}
= √{ 64/113} = 8/√113 <= answer.
ASA
SSS
HL
AAS
SAS
or Not Congruent
Answers
Answer:
SSS
Step-by-step explanation:
The sides of ABC and DEF are equal
AC = DF
CB = EF
AB = DE
Because the sides of both triangles correspond, the two are congruent
Answer:
SSS
Step-by-step explanation:
The sides on the triangles are of the same length.
AC = CF
CB = EF
AB = DE
Answers
Answer:
20 m/s
Step-by-step explanation:
Distance = rate * time
400 m = rate * 20 seconds
Divide each side by 20 seconds
400m/ 20 seconds = rate
20 m/second = rate
Answers
Answer:
C)
E)
F)
Step-by-step explanation:
Answers
Answer: 1/18
Step-by-step explanation: The x's basically cancel each other out so all that is left is the 1 and the 18
Answers
Answer:
The length is 10 yards and the width is 20 yards of the playground.
Step-by-step explanation:
Given,
Area of the rectangular playground = 200 yards.
Solution,
Let the length of the playground be x.
Then the width of the playground is 2x.
Now, According to the formula of area of rectangle;
On substituting the values, we get;
So the length of the playground is 10 yards.
Since the width is twice of the length.
So width =
Hence the length is 10 yards and the width is 20 yards of the playground.