Compute the permutation. 30 P 3
Answer options: 9,000 27,000 24,360

Answers

Answer 1
Answer:

Answer:

24,360

Step-by-step explanation:

30P3 = 30!/(30-3)! = 30·29·28 = 24,360

Answer 2
Answer:

Answer:

Compute the permutation. 30 P 3  

Answer options: 9,000 27,000 24,360

Step-by-step explanation:

The factorial function (symbol:!) Means that descending numbers are multiplied.  30 P 3.

30! = 30 x 29 x 28 =24,360

The answer is: 24,360


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What’s the answer to this

Simplify 12x7y3 divided by 6x3y

Answers

Answer:

12x7y3

----------- = 6x4y3

 6x3y

Step-by-step explanation:

In dividing these numbers, you simply subtract 6x from 12x and subtract 3y from 7y because 6x and 3y are both in the denominator. 3 is left alone.

If I have a 8 inch by 10 inch poster what is the area​

Answers

Answer:

80 inches

Step-by-step explanation:

8x10=80

because, lxw

l= length

w= width

Answer:

80

Step-by-step explanation:

im not trying to copy the answer above, im just going to say why its 80

so firstly we have the known dimensions of 10 by 8, so in this case we have 10 rows that each contain 8 units

we can then multiply the 8 units of one row, by the amount of rows there are total (in this case 10) to get the total unit count, or area

8 * 10 = 80

(NOTE: you can use the Asterisk (*) as a multiplication mark as to not get it confused with x as in the variable, as with slash (/) for dividing)

hope this helps with this and other problems, credits to the answer above for doing the initial work :)

What is the number in scientific notation ?

0.000000000093

Answers

0.000000000093 in scientific notation is 9.3 x 10 ^ -11

Answer:

your answer for  0.000000000093 would defiantly be 9.3 x 10^-11

Step-by-step explanation: i know this cause i took the test and got it wright

A trough has a semicircular cross section with a radius of 9 feet. Water starts flowing into the trough in such a way that the depth of the water is increasing at a rate of 2 inches per hour. (a) Give a function w = f(t) relating the width w of the surface of the water to the time t, in hours. Make sure to specify the domain and compute the range too.(b) After how many hours will the surface of the water have width of 6 feet?

(c) Give a function t = f −^1 (w) relating the time to the width of the surface of the water. Make sure to specify the domain and compute the range too.

Answers

Answer:

(a) Let h represents the height of water and w represents the width of the water,

Since, the depth of the water is increasing at a rate of 2 inches per hour,

So, after t hours,

The height of water, h(t) = 2t inches = t/6 ft,

( ∵ 1 foot = 12 inches ⇒ 1 inch = 1/12 ft )

Thus, the distance distance from the centre to the top of the water, d = 9 - h(t)   ( see in the diagram )

d=9-(t)/(6),

By the Pythagoras theorem,

d^2 + ((w)/(2))^2 = 9^2

(9-(t)/(6))^2 +(w^2)/(4) = 81

(t^2)/(36)-(18t)/(6) + (w^2)/(4)=0

(t^2 - 108t + 9w^2)/(36)=0

t^2 - 108t + 9w^2 =0

9w^2 = 108t - t^2

w = (1)/(3)√(108t - t^2)

Since, diameter of the semicircular cross section is 18 ft,

So, 0 ≤ w ≤ 18,

i.e Range = [0, 18]

Also, w will be defined if 108t - t² ≥ 0

⇒ (108 - t)t ≥ 0,

0 ≤ t ≤ 108

i.e Domain = [0, 108]

(b) If w = 6,

6 =(1)/(3)√(108t - t^2)

18 =√(108t-t^2)

324 = 108t - t^2

\implies t^2 - 108t+ 324=0

By using quadratic formula,

\implies t = 3.088\text{ or }t = 104.912

Hence, After 3.1 hours or 104.9 hours will the surface of the water have width of 6 feet.

(c)w = (1)/(3)√(108t- t^2)

\implies 3w = √(108t- t^2)

9w^2 = 108t - t^2

-9w^2 = -108t + t^2

-9w^2 + 2916 = 2916 - 108t + t^2

2916 - 9w^2 = (t - 108)^2

(t-108) = √(2916 - 9w^2)

t = √(2916 - 9w^2) + 108

For 0 ≤ w ≤ 18,

0 ≤ t ≤ 108,

So, Domain = [0, 18]

Range = [0, 108]

Final answer:

The width of the water's surface in a semicircular trough can be represented by the function w=t/3 and its domain is t ≥ 0 and the range is 0 ≤ w ≤ 6. To have a 6 feet wide surface, thus, it would take 18 hours. The inverse function is t=3w, with a domain of 0 ≤ w ≤ 6 and range of t ≥ 0.

Explanation:

Given that the depth of the water is increasing at a rate of 2 inches per hour in a semicircular trough, we can convert this rate to feet per hour by dividing by 12, getting an increase of 1/6 feet per hour.

(a) We can express the width of the surface of the water as a function of time. We consider the cross-section of the trough is a semicircle. So, the radius of the water's surface will be the height of water, and this height increases at 1/6 feet per hour. Therefore, the width of the surface of water, w=2r=2*1/6t=t/3. The domain of the function is t ≥ 0 and the range is 0 ≤ w ≤ 6.

(b) We set w=6 in the function w=t/3 and solve for t. We get t=3*6=18 hours.

(c) The inverse function of w=t/3 is t=3w. The domain of the inverse function is 0 ≤ w ≤ 6 and the range is t ≥ 0.

Learn more about Mathematical functions here:

brainly.com/question/30594198

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He height of Niagara Falls is 56 meters. How many
kilometers high is Niagara Falls?

Answers

Answer:

0.056 kilometers

Step-by-step explanation:

N<2^2. mathematical induction​

Answers

Answer:

Inequality Form:
n < 4

Interval Notation:
(-, 4)


God bless you have a beautiful blessed day and I hope this makes it!