Help!! How many moles of CaCO3 are needed to get 2.35 moles of CaO? What would be my reasoning and evidence?

Answers

Answer 1
Answer:

Equation

CaCO3 ===> CaO + O2

Solution

If you start with this equation, then the balance numbers (molar ratios) are

  • 1 for the CaCO3
  • 1 for the CaO
  • 1 for the O2

If you want 2.35 moles of CaO then you are going to have to start out with 2.35 moles of CaCO3

Answer 2
Answer:

Final answer:

In the decomposition of calcium carbonate to form calcium oxide, there is a 1:1 mole ratio. Therefore, to get 2.35 moles of calcium oxide, 2.35 moles of calcium carbonate are required.

Explanation:

To answer this question, you need to consider stoichiometry, which is the study of the relationships or ratios between the amounts of products and reactants in chemical reactions. The balanced chemical equation for the thermal decomposition of calcium carbonate (CaCO3) to form calcium oxide (CaO) and carbon dioxide (CO2) is:

CaCO3(s) → CaO(s) + CO2(g)

This equation tells us that 1 mole of CaCO3 will produce 1 mole of CaO. Therefore, if we need 2.35 moles of CaO, we would need 2.35 moles of CaCO3 because of the 1:1 mole ratio in the chemical reaction.

Learn more about Stoichiometry here:

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Answers

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Explanation:

Because the all have leaves

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Answers

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