if you have a mass of 55 kg and you are standing 3 meters away from your car, which has a mass of 1234 kg, how strong is the force of gravity between you and the car?

Answers

Answer 1

Answer:

From Newton's gravitational law, the force of gravity between you and the car is 5.03 x $10^(-7)$ Newton strong.

NEWTON'S GRAVITATION LAW

According to Newton, the force of attraction between two masses of directly proportional to the product of the masses and inversely proportional to the square of the distance between them. That is,

F = $(GMm)/(r^(2) )$

From the question, the given parameters are

M = 1234 kg

m = 55 kg

r = 3 m

G = 6.67 x $10^(-11)$ N $m^(2)kg^(-2)$

Substitute all the parameters into the formula

F = (6.67 x $10^(-11)$ x 1234 x 55) / $3^(2)$

F = 4.527 x $10^(-6)$ / 9

F = 5.03 x $10^(-7)$ N

Therefore, the force of gravity between you and the car is 5.03 x $10^(-7)$

Newton strong.

Learn more about Gravitational force here: brainly.com/question/2537310

Answer 2

Answer:

Gravitational force between two masses is given by formula

$F = (Gm_1m_2)/(r^2)$

here we know that

$m_1 = 55 kg$

$m_2 = 1234 kg$

$r = 3 m$

$G = 6.67 * 10^(-11) Nm^2/kg^2$

now from the above equation we will have

$F = ((6.67 * 10^(-11))(55)(1234))/(3^2)$

$F = 5.03 * 10^(-7)N$

so above is the gravitational force between car and the person

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