How many millimeter are there in 2 kilometers?

Answers

Answer 1
Answer:

Answer:

2,000,000

Step-by-step explanation:

There are 1,000,000 millimeters in a kilometer. So multiply that by two. Hope this helps

Answer 2
Answer:

Answer:

2 km = 2000000.00 mm

Step-by-step explanation:



Related Questions

A gardener uses 144144feet of fencing to build a rectangular garden. The function ()=24−2A(w)=24w-w2can be used to find the area of the garden for a given width, w. Does the function model the situation over the interval 12<<2412<w<24?
Which is a solution to (x – 3)(x + 9) = -27?
In YPS, PS is included between which angles?S and PS and YY and PP and Y
A survey asked students which vegetable they prefer. Of those who responded 17 said corn, 22 said carrots , 9 said green beans , and 7 said sweet patatoes. select an appropete display for this data.
From 126 ounces to 48 ounces nearest percent

Alice has 1/5 as many cars as Sylvester has. Sylvester has 35 miniature cars. How many miniature cars does Alice have?

Answers

If im not wrong...
1/5 * 35 to get 1/5th of 35.
0.2*35=7

Martin has 15 texts messages on his phone .Two thirds of them are from his sister how many texts does martin have from his sister? I need three different ways to calculate this answer?

Answers

15/3=5. 5x2=10. 2/3=66.66%. 10%=1.5 5%=0.75 1%=0.15 0.66 rounds to 1 1.5x6=9. 9+0.76+1.5+1.5=10. 2:3=10:15.
Divide 15 by 3 and add that number to itself

Multiply 15 by (2/3) (don't forget parentheses if you are using a calculator)

Draw a pic and shade in two thirds

_______________________________
| //////////////////|///////////////////|///////////////////|
|__________|__________|__________|

_______________________________
| //////////////////|///////////////////|///////////////////|
|__________|__________|__________|

_______________________________
| | | |
|__________|__________|__________|

////=shade in

What is 8-4/5f>-14-2f

Answers

8-4/5f>-14-2f

(subtract 8 on both sides)

-4/5f>-22-2f

(add 2f on both sides)

6/5f>-22

(divide 6/5 on both sides)

f>-55/3(-18.33)

8-(4)/(5)f>-14-2f\ \ \ \ \ |\cdot5\n\n40-4f>-70-10f\n\n-4f+10f>-70-40\n\n6f>-110\ \ \ \ \ |:6\n\nf>-(110)/(6)\n\nf>-(55)/(3)\n\nf\in(-(55)/(3),\infty)

Whats 65/100 in simplest form

Answers

divide both by 5 and you'll get 13/20.. that's in simplest form
It would be 13 over 20 

while shopping, Lucinda spent $48. if the amount she spent was 15% of her savings, how much savings did she have before she she shopped ?

Answers

Answer: $320

Step-by-step explanation:

Let the savings of Lucinda is denoted by 'x' .

If the amount she spent was 15% of her savings.

Then , the amount she spent would be 0.15x

[We can write 15% in 0.015 ∵ to convert a percentage sign we divide it by 100.]

It is given that  Lucinda spent $48.

\Rightarrow 0.15x=48\n\n\Rightarrow\ x=(48)/(0.15)\n\n=(4800)/(15)=320

Hence, she had $320 as savings before she she shopped.

im not sure if this is write but i would assume you would have to add it back so 
48 + 15 % = 55.2

Josh used a standard deck of 52 cards to conduct an experiment. Half of the cards in the deck were red. The other half were black. Josh predicted that he would choose a red card in 4 out of 8 trials. When he conducted the experiment, he actually chose a red card 6 out of 8 times. Which explains the most likely reason for the discrepancy between Josh’s predicted and actual results?A.He incorrectly predicted the number of times he would choose a red card.
B.He incorrectly determined the actual number of times he chose a red card.
C.He used too few trials for the sample space.
D.He used too many trials for the sample space.

Answers

Answer: C. He used too few trials for the sample space.


Step-by-step explanation:

Given: Josh used a standard deck of 52 cards to conduct an experiment.

As half of the cards in the deck were red.

If we take sample space= 52 cards

Then probability of getting a red card=(1)/(2)

But Josh took 8 cards as sample space which is not enough for the sample space.

therefore, C. is the right answer. "He used too few trials for the sample space."


Answer:

Option C - He used too few trials for the sample space.

Step-by-step explanation:

Given: Josh used a standard deck of 52 cards to conduct an experiment. Half of the cards in the deck were red. The other half were black.

Josh predicted that he would choose a red card in 4 out of 8 trials.

When he conducted the experiment, he actually chose a red card 6 out of 8 times.

To find : Which explains the most likely reason for the discrepancy between Josh’s predicted and actual results?

Solution :

Sample space = 52 cards

As half of the cards in the deck were red.

Probability of getting a red card is (1)/(2)

He predict and conduct to choose a red card out of 8 trials which is not enough for the sample space.

Therefore, Option C is correct.

He used too few trials for the sample space.