Add the fractions to simplify the answer 1/2 + 2/3
Answers
=7/6
=1 1/6
Least common denominator:
2 × 1 =2 3 × 1 = 3
2 × 2 =4 3 × 2 = 6
2 × 3 =6
6 is the least common denominator
(multiplying to have the same denominator)
As a mixed number:
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Plzzzz help me but dont ansewer if you dont know it. 100 points
Answers
The height of the office building is 99.2 meters
The given parameters are:
- d1: The flagpole's distance from the office building = 60 m
- d2: Marquis' distance from the office building = 170 m
- h1: Height of the flagpole = 35 m
The above parameters can be represented using the following equivalent ratio
Express as fraction
So, we have:
Multiply both sides by 170
Rewrite as:
Hence, the building is 99.2 meters tall
Read more about equivalent ratios at:
Answer:
99.17m
Step-by-step explanation:
In the diagram, Marquis is at Point A and the flag pole is length DE, the building is of length BC.
Triangles ADE and ABC are therefore similar right triangles.
Applying this,
[TeX]\frac{|DE|}{|AE|}=\frac{|BC|}{|AC|}[/TeX]
[TeX]\frac{35}{60}=\frac{|BC|}{170}[/TeX]
|BC|=170*35÷60
|BC|=99.17m
{x | x R, x > -7}
{x | x R, x > -3}
{x | x R, x > 3}
{x | x R, x > 7}
Answers
x-5+5>-2+5
x>3
{x l x R, x > 3}
{x | x R, x > -7} Is the answer
Took the test :)
Answers
Final answer:
To find out how long it takes for the temperature of the roast to drop to 110 F, we can use the Newton's Law of Cooling equation. By setting up and solving a differential equation, we find that it takes approximately 34 minutes for the temperature of the roast to drop to 110 F.
Explanation:
To find out how long it takes for the temperature of the roast to drop to 110 F, we can use the Newton's Law of Cooling equation. This equation states that the rate of change of temperature of an object is proportional to the difference between its temperature and the temperature of its surroundings.
In this case, we can write the equation as: dT/dt = -k(T - Troom),
where dT/dt represents the rate of change of temperature with respect to time, T is the temperature of the roast, Troom is the temperature of the room, and k is a constant.
We know that when the roast was taken out of the oven, its temperature was 165 F, and after 15 minutes, its temperature dropped to 135 F. Using these values, we can set up the initial value problem:
dT/dt = -k(T - 70), T(0) = 165
Solving this differential equation, we find the value of k to be 1/15. Using this value, we can find the time it takes for the temperature to drop to 110 F:
dT/dt = -1/15(T - 70)
Integration of the equation gives: ln|T - 70| = -t/15 + C
Using the initial condition T(0) = 165, we can find the value of the constant C as: ln|165 - 70| = 0 + C
Therefore, C = ln(95).
Substituting back into the equation, we get:
ln|T - 70| = -t/15 + ln(95)
T - 70 = e^(-t/15 + ln(95))
T = 70 + 25e^(-t/15)
Now, we can substitute T = 110 and solve for t:
110 = 70 + 25e^(-t/15)
25e^(-t/15) = 40
e^(-t/15) = 40/25
-t/15 = ln(40/25)
t = -15ln(40/25)
Simplifying, we find that it takes approximately 34 minutes for the temperature of the roast to drop to 110 F.
Learn more about Newton's Law of Cooling here:
#SPJ2
Answers
Answer:
C
Step-by-step explanation:
The scale factor is the ratio of corresponding sides, image to original, so
scale factor = =
=
→ C
Answers
Answer:
-9/6
Step-by-step explanation:
y2-y1 , x2-x1
Answers
hey there!
I think i might be able to help.
AC:20, BK:9.6
try it out!