How to write 1 x 100,000 + 3 x 10,000 + 9 x 1,000 + 8 x 100 + 5 x 10 + 2 x 1 in standard form

Answers

Answer 1

Answer:

The solution of the expression 1 x 100,000 + 3 x 10,000 + 9 x 1,000 + 8 x 100 + 5 x 10 + 2 x 1 in standard form is 139852.

A standardform is a method of writing equations, integers, or expressions that follows a set of rules.

The given expression 1 x 100,000 + 3 x 10,000 + 9 x 1,000 + 8 x 100 + 5 x 10 + 2 x 1 is in the expanded form.

The standard form can be observed by examining the number of zeroes in the expressions,

1 x 100,000 + 3 x 10,000 + 9 x 1,000 + 8 x 100 + 5 x 10 + 2 x 1

=100,000 + 30,000+ 9000 + 800 + 50 +2

= 139852

The solution of the expression in standard form is 139852.

Learn more about the standard form here:

brainly.com/question/28771755

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Answer 2

Answer:

Answer:

Step-by-step explanation:

standard form is the way to write the number the simplest. this number would be...

839,852

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How do you solve 2/3x+15=17? it is confusing. i have been stuck on this problem for a while...

Answers

Find the opposite of adding 15. So it would be subtracting 15. So subtract 15 on both sides. So it would have 2/3x on the left and then 2 on the other side. (2/3x=2) Now find the opposite of multiplying 2/3. It is dividing 23/3. So divide 23/3 on both sides. So multiply 2/3 times 1/2. It would equal 3. x = 3
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Show how you got your answer or explain it interest earned: $84

principal: $600

interest rate 7%

time:?

Answers

For simple interest, the amount of interest (I) is calculated from the principal (P), the annual rate (r) and the number of years (t) using the formula

... I = P·r·t

Fill in the given numbers, and solve for t.

... 84 = 600·0.07·t . . . of course, you know that 7% = 7/100 = 0.07

... 84 = 42t . . . . . . . . simplify

... 84/42 = t = 2 . . . . divide by the coefficient of t

The time period is 2 years.

Total = Principal × ( 1 + Rate ) ^ years

(Solved by taking logarithms)

Years = log (total / principal) / (log (1 + rate))

Years = log (684 / 600) / (log 1.07)

Years = log (1.14) / (log (1.07)

Years = 0.0569048513364726 / 0.0293837776852097

Years = 1.9366077414

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b. Who had a greater average most of the season?
Who had a greater average at the end of the season?