Which organisms play roles similar to organisms in water ecosystem

Answers

Answer 1

Answer: Is there a multiple choice?

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: suppose you are designing a device to transmit information without wires. What part of the EM spectrum will your device use, and why?

Answers

Funny that you should ask. This week, I would definitely use radio waves, specifically the 5.8 GHz unlicensed microwave band, because I just happen to have a complete terminal for that service ... including the dish antenna ... in the back seat of my car, until I can set up a meeting with its rightful caretakers and get rid of it.

A wave has an amplitude of0.0800 m and is moving 7.33 m/s.
One oscillator in the wave takes
0.115 s to go from the lowest point
in its motion to the highest point.
Find the frequency of the wave.
(Unit = Hz)

Answers

Answer:

The frequency of wave is 4.34 Hz.

Explanation:

We know the relation:

λ = $(v)/(f)$ = $v$ × $T$ ........................................1

where,

λ= wavelength

v= velocity of wave

T= Period of wave

By the definition of period T, you are given that HALF of T is 0.115 s, so

T = 2 × (0.115 s)

= 0.23 s

Then,

λ = v × T

= (7.33 m/s) × (0.23 s)

≅ 1.686 m

Now for frequency, return to equation 1,

$f$ = $(v)/( \lambda )$

= $(7.33)/(1.686)$

= 4.34

The frequency of the wave is calculated as 4.34 Hz.

Answer:

0.230

Explanation:

That's the answer, the one above isn't, I got this answer correct on acellus

Plants are made of_________________cells, which have membrain-bound_____.

Answers

Plant cells are eukaryotic cells that differ in several key aspects from the cells of other eukaryotic organisms. number two sry but Idk
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What is meant by gravitational field strength at a point in the gravitational field

Answers

Answer:

Explanation:

The gravitational field strength at a point is the gravitational force exerted per unit mass placed at that point. This means that the gravitational field strength, g {\displaystyle g} is equal to the force experienced by a mass of 1 kg in that gravitational field.

Calculate the density of a sample of gas with a mass of 30 g and volume of 7500 cm3.

Answers

By definition we have that the density is given by:

Where,

M: mass of the sample

V: volume occupied by the sample

Therefore, substituting values in the given equation we have:

$D = 0.004 (g)/(cm^3)$

Answer:

the density of a sample of gas with a mass of 30 g and a volume of 7500 cm3 is:

$D = 0.004 (g)/(cm^3)$

The density of the sample of gas is $\boxed{4*10^(-3)\text{ g}/\text{cm}^3}$ or $\boxed{0.004\text{ g}/\text{cm}^3}$ .

Further Explanation:

Density of any kind of matter is defined as the total mass of that substance present in the volume occupied by it in the region of space.

Example (1) : If we consider equal amounts of tungsten and iron, then tungsten is heavier than iron because tungsten occupies lesser volume or lesser empty spaces inside it for a particular mass as compared to iron. Therefore, tungsten has density higher than that of iron.

Example (2): If we take 2 cubes of similar size (same volume) of tungsten and gold then the cube of gold will be heavier because its density is more than that of tungsten.

Given:

The mass of the sampleof the gas is $30\text{ g}$ .